Answer:
Explanation:
Ketcher 01232019462D 1 1.00000 0.00000 0 5 4 0 0 0 999 V2000 -0.0330 2.2250 0.0000 C 0 0 0 0 0 0 0 0 0 0 0.8330 2.7250 0.0000 C 0 0 0 0 0 0 0 0 0 0 1.6990 2.2250 0.0000 C 0 0 0 0 0 0 0 0 0 0 0.8330 3.7250 0.0000 C 0 0 0 0 0 0 0 0 0 0 1.6990 1.2250 0.0000 C 0 0 0 0 0 0 0 0 0 0 1 2 1 0 0 0 2 3 1 0 0 0 2 4 1 0 0 0 3 5 1 0 0 0 M END
<h3>
Answer:</h3>
19.3 g/cm³
<h3>
Explanation:</h3>
Density of a substance refers to the mass of the substance per unit volume.
Therefore, Density = Mass ÷ Volume
In this case, we are given;
Mass of the gold bar = 193.0 g
Dimensions of the Gold bar = 5.00 mm by 10.0 cm by 2.0 cm
We are required to get the density of the gold bar
Step 1: Volume of the gold bar
Volume is given by, Length × width × height
Volume = 0.50 cm × 10.0 cm × 2.0 cm
= 10 cm³
Step 2: Density of the gold bar
Density = Mass ÷ volume
Density of the gold bar = 193.0 g ÷ 10 cm³
= 19.3 g/cm³
Thus, the density of the gold bar is 19.3 g/cm³
Remember the formula as per the second Law of Newton: F = m*a
And also remember that the weight is the force with which the mass is attracted by the planet (or satellite in the case of the moon).
With that information you can answer the questions:
a) Weight = F = m*a
m = 175 slugs = 175 lbm
i) Earth
a = 32.17 ft/s^2
Weight on Earth = 175 lbm * 32.17 ft / s^2 = 5,629.75 poundal
ii) Moon
a = [1/6] 32.17 ft/s^2
Weight on the Moon = [1/6]*5,629.75 poundal = 938.29 poundal
b) Force = 355 poundal
m = 25.0 slug
a in m/s^2 = ?
First calculate the force in ft/s^2
F = m*a => a = F/m = 355 poundal / 25.0 slug = 14.2 ft/s^2
Conversion:
14.2 ft / s^2 * [ 0.3048 m/ft] = 4.32816 m/s^2
Answer: 4.33 m/s^2
PH and conductivity have no common rekationship
