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Anit [1.1K]
2 years ago
11

Urea is an organic compound widely used as a fertilizer. Its solubility in water allows it to be made into aqueous fertilizer so

lutions and applied to crops in a spray. What is the maximum theoretical number of water molecules that one urea molecule can hydrogen bond with? Ignore shape for the purposes of this answer.
Chemistry
1 answer:
Talja [164]2 years ago
3 0

Answer:

8 water molecules

Explanation:

The hydrogen bond may be H-O~H-N or  H-N~H-O; in the first one, the hydrogen bond is between an oxygen atom and a hydrogen which is covalently bonded to a nitrogen atom. The second one is the hydrogen bond of a nitrogen atom with a hydrogen covalently bonded to a oxygen one. The first case would be the hydrogen bonds that water may form with the hydrogen of the urea; the second ones would be the hydrogen bonds that urea may form with water molecules. So, for each nitrogen in urea there would be a hydrogen bond, and for each hydrogen too. Finally, the oxygen in the urea molecule may form hydrogen bonds with water as well, but it has two lone pairs to donate, so the oxygen atom may form hydrogen bond with 2 water molecules:

N=(2 because of the oxygen atom of the urea)+(4 because of the hydrogen bonded to nitrogen)+2(because of the nitrogens).

N=8.

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How many sodium ions are in the initial 50.00-mL solution of Na2CO3
tresset_1 [31]
From other sources, the given mass of the solute that is being dissolved here is 7.15 g Na2CO3 - 10H2O. We use this amount to convert it to moles of Na2CO3 by converting it to moles using the molar mass then relating the ratio of the unhydrated salt with the number of water molecules. And by the dissociation of the unhydrated salt in the solution, we can calculate the moles of Na+ ions that are present in the solution.

Na2CO3 = 2Na+ + CO3^2-

7.15 g Na2CO3 - 10H2O (1 mol / 402.9319 g) (1 mol Na2CO3 / 1 mol Na2CO3 - 10H2O) ( 1 mol Na2CO3 / 1 mol Na2CO3-10H2O ) ( 2 mol Na+ / 1 mol Na2CO3) = 0.04 mol Na+ ions present
8 0
2 years ago
A flask contains 1/3 mole of h2 and 2/3 mol of he. Compare the force on the wall per impact of h2 relative to that for he.
densk [106]

The force on the wall is actually the pressure exerted by gas molecules

Higher the pressure more the force exerted on the walls of container

The pressure depends upon the number of molecules of a gas

In a mixture of gas the pressure depends upon the mole fraction of the gas

As given the mole fraction of He is more than that of H2 therefore He will exert more pressure on the wall

The ratio of impact will be

H2 / He = 2/3 / 1/3 = 2: 1

8 0
2 years ago
Read 2 more answers
Jill is doing an experiment on the movement of pill bugs. She will place the pill bugs on flat surfaces covered with diffirent m
Ostrovityanka [42]

Answer:D

Explanation:

6 0
2 years ago
Write chemical equations and corresponding equilibrium expressions for each of the two ionization steps of carbonic acid. Part A
lesantik [10]

<u>Answer:</u> The chemical equations and equilibrium constant expression for each ionization steps is written below.

<u>Explanation:</u>

The chemical formula of carbonic acid is H_2CO_3. It is a diprotic weak acid which means that it will release two hydrogen ions when dissolved in water

The chemical equation for the first dissociation of carbonic acid follows:

               H_2CO_3(aq.)\rightleftharpoons H^+(aq.)+HCO_3^-(aq.)

The expression of first equilibrium constant equation follows:

Ka_1=\frac{[H^+][HCO_3^{-}]}{[H_2CO_3]}

The chemical equation for the second dissociation of carbonic acid follows:

               HCO_3^-(aq.)\rightarrow H^+(aq.)+CO_3^{2-}(aq.)

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H^+][CO_3^{2-}]}{[HCO_3^-]}

Hence, the chemical equations and equilibrium constant expression for each ionization steps is written above.

6 0
2 years ago
The button batteries in small devices like watches are commonly composed of silver-zinc or mercury-zinc batteries. The reaction
photoshop1234 [79]

Answer:

The mercury button battery line notation is:

        Zn⁰| Zn²|| , HgO| Hg⁰||

Explanation:

Mercury batteries either use

pure mercury(II) oxide (HgO)—which is called mercuric oxide

or a mixture of HgO with manganese dioxide (MnO2) which is as the cathode.

Anode has two half reactions:

The first step is an electrochemical reaction step:

Zn + 4OH− → Zn(OH)4−2 + 2e−[3]

cathode has a half reaction :

HgO + H2O + 2e− → Hg + 2OH−[3]

+0.0977 V  standard potential is of this reaction.

which is followed by a chemical reaction step:

Anode consists of oxidation:

Zn+2OH>ZnO+H2O+2e

which gives an overall anode half-reaction of:

Zn + 2OH− → ZnO + H2O + 2e−[3]

Therefore,

The overall reaction for the battery is:

Zn + HgO → ZnO + Hg

7 0
2 years ago
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