Answer:
Explanation:
Ketcher 01232019462D 1 1.00000 0.00000 0 5 4 0 0 0 999 V2000 -0.0330 2.2250 0.0000 C 0 0 0 0 0 0 0 0 0 0 0.8330 2.7250 0.0000 C 0 0 0 0 0 0 0 0 0 0 1.6990 2.2250 0.0000 C 0 0 0 0 0 0 0 0 0 0 0.8330 3.7250 0.0000 C 0 0 0 0 0 0 0 0 0 0 1.6990 1.2250 0.0000 C 0 0 0 0 0 0 0 0 0 0 1 2 1 0 0 0 2 3 1 0 0 0 2 4 1 0 0 0 3 5 1 0 0 0 M END
Thermal energy will flow from an object high temperature to an object of low one. In this case, the thermal energy will flow from object B to object A.
First step is to get the mass of the mercury:
Pressure = mass/volume
mass = pressure x volume = 13.5 x 1.85 = 24.975 gm
Second step is to calculate the number of moles in 24.975 gm:
From the periodic table, the molar mass of mercury is 200.59
mass = number of moles x molar mass
number of moles = 24.975 / 200.59 = 0.1245 mole
Last step is to get the number of atoms:
Each mole contains 6.02 x 10^23 atoms
number of atoms = 0.1245 x 6.02 x 10^23 = 7.4949 x 10^22 atoms
Answer:
A) coenzyme A
Explanation:
The NADH and FADH₂ are the energy rich molecules which are formed in the processes like glycolysis, TCA cycle and the fatty acid oxidation as they contain pair of electrons which have very high transfer potential.
As a result of the energy produced when these molecules transfer their electrons to the oxygen , ATP is generated by a series of electron carriers which collectively is called electron transport chain (ETC).
<u>The components of chain include Fe–S centers, Non-heme, FMN, coenzyme Q, and cytochromes .
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The energy derived from the transfer of electrons is used to pump the protons across mitochondrial membrane.
As a result, an electrochemical gradient is generated which results in some energy which is then harnessed by the ATP synthase to form ATP.
The correct answer is e. 3.57×10³
Al³+(aq) + 3e→AL(s)
4.00g of AL=4g/26.98 g/mol= 0.1483 mol
t=znF/1 where t is time in seceonds.
Z= valency number of ions of the substance or electrons which are transferred per ion
F= Faraday's constant
I = electric current in'A'CA C/s
t=(3×0.1483 mol ×96485 C/mol) /12(C15)
t=3577 second = 3.5 ×10³s
