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hodyreva [135]
2 years ago
12

A pure sample of bromine was vaporized and injected into a mass spectrometer and the data was plotted on the graph below. The ma

ss value for Br-79 is 78 918 amu Find the mass of Br-81.

Chemistry
1 answer:
Whitepunk [10]2 years ago
4 0

Answer:

m_{Br-81}=80.945amu

Explanation:

Hello,

In this case, since the percent abundance of Br-79 is 51.1% and that of the Br-81 is 48.9 %, we can write:

m_{Br}=m_{Br-79}*51.1\%+m_{Br-81}*48.9\%

Taking into account that the mass of bromine from the periodic table is 79.909 amu, the mass of Br-81 turns out:

m_{Br-81}=\frac{m_{Br}-m_{Br-79}*51.1\%}{48.9\%} =\frac{79.909amu-78.918*0.511}{0.489} \\\\m_{Br-81}=80.945amu

Best regards.

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What are the 4 most abundant minerals in the continental crust? What percentage do these 4 makeup of the total?
Tanya [424]

Answer:

SiO_2, Al_2O_3, CaO, MgO

Explanation:

The four most abundant minerals in the continental crust are, SiO_2, Al_2O_3, CaO, MgO.

The percentages are

SiO_2=60.6\%

Al_2O_3=15.9\%

CaO=6.4\%

MgO=4.7\%

SiO_2 is called quartz

Al_2O_3 is called corundum

CaO is called calcium oxide or quick lime

MgO is called magnesium oxide or magnesia

5 0
2 years ago
Which graphic below shows the correct orientation of each water molecule when it is near the cl- ion in the aqueous solution?
andrew-mc [135]
The question is missing the graphics required to answer which I have attached as an image.

There are four different representations of the orientation of water molecules around chloride anion. Let's first analyze the water molecule.

We have H-O-H as the structure of water. The oxygen atom is more electronegative than the hydrogen atoms, which results in a partial positive charge on the hydrogen atoms and a partial negative charge on the oxygen atom.

The chloride anion is a negative charge. Therefore, the water molecules should orient themselves with the hydrogen atoms facing the chlorine atom as the partial positive charge on the hydrogen atoms will be attracted to the negative charge of the chlorine atom.

The correct representation is shown in graph 3 which shows all hydrogen atoms facing the chlorine anion.

8 0
2 years ago
Given equilibrium partial pressures of PNO2= 0.247 atm, PNO = 0.0022atm, and PO2 = 0.0011 atm calculate the equilibrium constant
maxonik [38]
Answer 1:
Equilibrium constant (K) mathematically expressed as the ratio of the concentration of products to concentration of reactant. In case of gaseous system, partial pressure is used, instead to concentration.

In present case, following reaction is involved:

                        2NO2    ↔      2NO + O2

Here, K = \frac{[PNO]^2[O2]}{[PNO2]^2}

Given: At equilibrium, <span>PNO2= 0.247 atm, PNO = 0.0022atm, and PO2 = 0.0011 atm
</span>
Hence,  K = \frac{[0.0022]^2[0.0011]}{[0.247]^2}
                 = 8.727 X 10^-8

Thus, equilibrium constant of reaction = 8.727 X 10^-8
.......................................................................................................................

Answer 2:
Given: <span>PNO2= 0.192 atm, PNO = 0.021 atm, and PO2 = 0.037 atm.

Therefore, Reaction quotient = </span>\frac{[PNO]^2[O2]}{[PNO2]^2}
                                              = \frac{[0.021]^2[0.037]}{[0.192]^2}
                                              = 4.426 X 10^-4.

Here, Reaction quotient > Equilibrium constant.

Hence, <span>the reaction need to go to reverse direction to reattain equilibrium </span>
5 0
2 years ago
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At 4.00 L, an expandable vessel contains 0.864 mol of oxygen gas. How many liters of oxygen gas must be added at constant temper
fgiga [73]

Answer:

We have to add 2.30 L of oxygen gas

Explanation:

Step 1: Data given

Initial volume = 4.00 L

Number of moles oxygen gas= 0.864 moles

Temperature = constant

Number of moles of oxygen gas increased to 1.36 moles

Step 2: Calculate new volume

V1/n1 = V2/n2

⇒V1 = the initial volume of the vessel = 4.00 L

⇒n1 = the initial number of moles oxygen gas = 0.864 moles

⇒V2 = the nex volume of the vessel

⇒n2 = the increased number of moles oxygen gas = 1.36 moles

4.00L / 0.864 moles = V2 / 1.36 moles

V2 = 6.30 L

The new volume is 6.30 L

Step 3: Calculate the amount of oxygen gas we have to add

6.30 - 4.00 = 2.30 L

We have to add 2.30 L of oxygen gas

4 0
2 years ago
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