Answer is: volume of CO₂ is 0,113 dm³.
Ideal gas law = pV = nRT.
p = 850 PSI = 5860543,6992 Pa.
Psi <span>is the abbreviation of pound per square inch.
T = 21</span>°C = 294,15 K.
n = 0,273 mol.
R = 8,314 J/K·mol.
V = nRT ÷ p
V = 0,273 mol · 8,314 J/K·mol · 294,15 K ÷ 5860543,6992 Pa.
V = 0,00011 m³ = 0,113 dm³.
Answer:
If fixed amount of gas is heated then the volume will increase because the heat will cause the molecules of gas to move freely and increase the kinetic energy.
Explanation:
If fixed amount of gas is heated then the volume will increase because the heat will cause the molecules of gas to move freely and increase the kinetic energy.
According to the Charle's law
The volume of given amount of gas is directly proportional to the temperature at constant pressure and number of moles of gas.
Mathematical expression;
V ∝ T
V = kT
V/T = k
if volume is changed from V1 to V2 and temperature change from T1 to T2 then,
V1/T1 = k V2/T2= k
V1/T1 = V2/T2
How many times has it halved?
24/2 = 12
12/2 = 6
6/2 = 3
It halved three times.
It halves once every 6 hours.
18 hours have passed.
Answer:
V2 = 6616 L
Explanation:
From the question;
Initial volume = 40L
Initial Pressure, P1 = 159atm
Initial Temperature T1 = 25 + 273 = 298K (Upon converting to Kelvin unit)
Final Volume, V2 = ?
Final Pressure, P2 = 1 atm
Final Temperature T2 = 37 + 273= 310K (Upon converting to Kelvin unit)
These quantities are related by the equation;
P1V1 / T1 = P2V2 / T2
V2 = T2 * P1 * V1 / T1 * P2
V2 = 310 * 159 * 40 / (298 * 1)
V2 = 6616 L
The chemical reaction would be written as
2 AsF3<span> + 3 CCl4 = 2 AsCl3 + 3 CCl2F2
</span>
We use the given amounts of the reactants to first find the limiting reactant. Then use the amount of the limiting reactant to proceed to further calculations.
150 g AsF3 ( 1 mol / 131.92 g) = 1.14 mol AsF3
180 g CCl4 (1 mol / 153.82 g) = 1.17 mol CCl4
Therefore, the limiting reactant would be CCl4 since it would be consumed completely. The theoretical yield would be:
1.17 mol CCl4 ( 3 mol CCl2F2 / 3 mol CCl4 ) = 1.17 mol CCl2F2
