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Naily [24]
2 years ago
5

Which of the following factors used in a dimensional analysis calculation have a finite number of significant figures (in other

words, they are not exact numbers) that might limit the precision of the calculated value?
A. A conversion factor for time of (60 min/1 hour)
B. A conversion factor for distance of (1000 m/1 km)
C. A measurement of speed equaling (27.7 km/hour)
D. None of the above
Chemistry
1 answer:
lys-0071 [83]2 years ago
8 0

Answer: Option C

A measurement of speed equaling (27.7 km/hour)

Explanation:

It is measurement of speed equaling (27.7 km/hour) because it is a factor used in dimensional analysis because it is a problem solving method that involve the use of number or expression which can be multiplied without affecting or causing a change in the value of the expression.

27.7km/he is not the exact number that can limit the precision of the calculated value or accurate value.

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A slug takes 4.25 minutes to travel 11.2 centimeters. What is the speed of the slug in minutes per second?
nexus9112 [7]

Answer:

4.39 ×  10^{-4} m/sec

Explanation:

7 0
2 years ago
A quantity of 85.0 mL of 0.900 M HCl is mixed with 85.0 mL of 0.900 M KOH in a constantpressure calorimeter that has a heat capa
bogdanovich [222]

Explanation:

The given data is as follows.

         V_{1} = 85.0 ml,        M_{1} = 0.9 M

         V_{2} = 85.0 ml,        M_{1} = 0.9 M

Hence, number of moles of HCl and KOH will be the same because both the solutions have same volume and molarity.

So,     No. of moles = Molarity × Volume

                                = 0.9 M \times 0.085 L        (as 1 L = 1000 ml so, 85 ml = 0.085 L)

                                = 0.076 mol

As 1 mole gives 56.2 kJ/mol of heat of neutralization. Hence, calculate the heat of neutralization given by 0.076 moles as follows.

              56.2 kJ/mol \times 0.076 mol

                    = 4.271 kJ

or,                 = 4271 J     (as 1 kJ = 1000 J)

Therefore,    heat released = - heat of gained by calorimeter

Since, it is given that density of the solution is similar to the density of water which is 1 g/ml.

Hence,     mass of HCl = density × Volume of HCl

                                      = 1.00 g/ml × 85.0 ml

                                       = 85 g

Similarly,    mass of KOH = = density × Volume of HCl

                                      = 1.00 g/ml × 85.0 ml

                                       = 85 g

Hence, total mass of the solution = 85 g + 85 g

                                                        = 170 g

Also,                   q = mC \Delta T

                     4271 J = 170 g \times 325 J/^{o}C \times (T_{f} - 18.24)^{o}C    

                     0.0773 = T_{f} - 18.24

                    T_{f} = 18.317^{o}C  

Thus, we can conclude that final temperature of the mixed solution is 18.317^{o}C.

6 0
2 years ago
Water at 4.4°C is to flow through a horizontal, commercial steel pipe having a length of 305 m at the rate of 150 gal/min. If a
Pavel [41]

Answer:

d = 70.5 mm

Explanation:

given,

length of pipe = 305 m

discharge rate = 150 gal/min

pipe diameter = ?

1 gal/min = 6.30902 ×  10⁻⁵ m³/s

150 gal/min = 150 × 6.30902 ×  10⁻⁵ m³/s

                   = 9.46 × 10⁻³ m³/s

h = \dfrac{flv^2}{2gd}

h = \dfrac{flv^2}{2gd}

Q = A V

h = \dfrac{fl(\dfrac{Q}{A})^2}{2gd}

h = \dfrac{fl(\dfrac{Q}{\dfrac{\pi}{4}d^2})^2}{2gd}

h= \dfrac{8flQ^2}{\pi^2gd^5}

f = 0.048 from moody chart using P/D = 0.00015

\dfrac{1}{d^5}= \dfrac{6.1\times \pi^2\times 9.8}{8\times 0.048\times 305\times 0.00946^2}

d = 70.5 mm

Diameter of the pipe is equal to 70.5 mm

7 0
2 years ago
Sodium hydroxide reacts with carbon dioxide to form sodium carbonate and water: 2 naoh(s) + co2(g) → na2co3(s) + h2o(l) how many
kow [346]
No of moles of naoh = 2.40 ÷ (23+16+1) = 0.06mol

no of moles of na2co3 = 0.06 ÷ 2 = 0.03mol

mass of na2co3 = 0.03 × (23×2+12+16×3) = 0.03 × 106 = 3.18g
8 0
2 years ago
Read 2 more answers
The pressure and temperature inside a bike tire is 10 atm and 10k respectively. What will the pressure become in the tire when t
igomit [66]

Answer:

P_2=20atm

Explanation:

Hello,

In this case, we apply the Gay-Lussac's law which allows us to understand the pressure-temperature behavior as a directly proportional relationship:

\frac{P_1}{T_1}= \frac{P_2}{T_2}

Thus, we solve for the final pressure P2 to obtain it as shown below:

P_2=\frac{P_1T_2}{T_1}=\frac{10atm*20K}{10K} \\\\P_2=20atm

Hence, we notice that the temperature doubles as well as the pressure.

Best regards.

3 0
2 years ago
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