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Murljashka [212]
1 year ago
6

Why does increasing the number of trials increase confidence in the results of the experiment?

Chemistry
2 answers:
valkas [14]1 year ago
5 0
<span>It rises confidence for the reason that the more times you conduct the similar experiment over and over should either demonstrate your hypothesis right and wrong and remove any random incidences that might touch your results. Meaning it permits to have a more accurate measure or conclusion.</span>
Pavel [41]1 year ago
4 0

The answer is...

Sample Response:  Increasing the number of trials reduces the impact of any one imprecise measurement. Using an average value for data points provides a better representation of the true value.

I just took the test.

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How many atoms of oxygen are in 75.6g of silver nitrate (AgNO3)?​
vodomira [7]

Answer:

1.50x10^21 molecules O2

Explanation:

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1 year ago
93.2 mL of a 2.03 M potassium fluoride (KF) solution
Marrrta [24]

Answer:

1.98 M

Explanation:

Given data

  • Initial volume (V₁): 93.2 mL
  • Initial concentration (C₁): 2.03 M
  • Volume of water added: 3.92 L

Step 1: Convert V₁ to liters

We will use the relationship 1 L = 1000 mL.

93.2mL \times \frac{1L}{1000mL} = 0.0932 L

Step 2: Calculate the final volume (V₂)

The final volume is the sum of the initial volume and the volume of water.

V_2 = 0.0932L + 3.92 L = 4.01L

Step 3: Calculate the final concentration (C₂)

We will use the dilution rule.

C_1 \times V_1 = C_2 \times V_2\\C_2 = \frac{C_1 \times V_1}{V_2} = \frac{2.03 M \times 3.92L}{4.01L} = 1.98 M

3 0
1 year ago
Read 2 more answers
William adds two values, following the rules for using significant figures in computations. He should write the sum of these two
Lunna [17]
<span>when it comes to adding or subtracting numbers, his final answer should have the same number of decimal places as the least precise value.
For example if you add 2 numbers; 10.443 + 3.5 , 10.443 has 3 decimal places and 3.5 has only one decimal place.
Therefore 3.5 is the less precise value.
So when adding these 2 values the final answer should have only one decimal place.
after adding we get 13.943 but it can have upto one decimal place. then the second decimal place is less than 5 so the answer should be rounded off to 13.9.
the answer is the same number of decimal places as the least precise value</span>
6 0
1 year ago
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A 8.5-liter sample of a gas at 2.0 atm and 300.0 K has 1.2 moles of the gas. If 0.65 mole of the gas is added to the sample at t
hodyreva [135]

Did you take the test? what was the answer Im stuck on this one too

7 0
1 year ago
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What is the value of ΔGo in kJ at 25 oC for the reaction between the pair: Mn(s) and Ag+(aq) to give Ag(s) and Mn2+(aq) Use the
Leni [432]

Answer:  -3.8\times 10^{5}J

Explanation:

Mn+2Ag^{+}\rightarrow Mn^{2+}+2Ag

Here Mn undergoes oxidation by loss of electrons, thus act as anode. silver undergoes reduction by gain of electrons and thus act as cathode.

E^0=E^0_{cathode}- E^0_{anode}

Where both E^0 are standard reduction potentials.

E^0_{[Mn^{2+}/Mn]}= -1.18V

E^0_{[Ag^{2+}/Ag]}=+0.80V

E^0=E^0_{[Ag^{+}/Ag]}- E^0_{[Mn^{2+}/Mn]}

E^0=+0.80- (-1.18V)=1.98V

The standard emf of a cell is related to Gibbs free energy by following relation:

\Delta G^0=-nFE^0

\Delta G^0 = gibbs free energy

n= no of electrons gained or lost  = 2

F= faraday's constant

E^0 = standard emf  = 1.98V

\Delta G^0=-2\times 96500\times (1.98)=-3.8\times 10^{5}J

Thus the value of \Delta G^0 is -3.8\times 10^{5}J

8 0
1 year ago
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