Answer:
The number of copper atoms 12.405 ×10²³ atoms.
The number of silver atoms 13.13 ×10²³ atoms.
Beaker B have large number of atoms.
Explanation:
Given data:
In beaker A
Number of moles of copper = 2.06 mol
Number of atoms of copper = ?
In beaker B
Mass of silver = 222 g
Number of atoms of silver = ?
Solution:
For beaker A.
we will solve this problem by using Avogadro number.
The number 6.022×10²³ is called Avogadro number and it is the number of atoms in one mole of substance.
While we have to find the copper atoms in 2.06 moles.
So,
63.546 g = 1 mole = 6.022×10²³ atoms
For 2.06 moles.
2.06 × 6.022×10²³ atoms
The number of copper atoms 12.405 ×10²³ atoms.
For beaker B:
107.87 g = 1 mole = 6.022×10²³ atoms
For 222 g
222 g / 101.87 g/mol = 2.18 moles
2.18 mol × 6.022×10²³ atoms = 13.13 ×10²³ atoms
Answer:
the amount of matter in the bowling ball remains the same
Explanation:
The reason why the mass of the bowling ball on earth and moon remains the same is that matter in the bowling ball remains the same.
Mass of any substance is the amount of matter it contains.
- Since there is no loss in matter, the mass of the bowling ball anywhere in the universe will be the same.
- Only the weight changes due to differences in gravity.
Answer:
B
Explanation:
The compound corresponds to a molecule AX4E where A is the Central atom, X are the other atoms present and E is the lone pair of electrons.
The shape of this molecule is based on a trigonal bipyramid since the molecule contains five electron domains.
Since there are four bond pairs and one lone pair, the molecular geometry is see-saw with equatorial bond angle <120° and axial bond angle <90°.
For AX4E (five electron pairs), the lone pair should occupy an equatorial position instead of an axial position since the equatorial position has two neighboring electron pairs that are positioned at about 90° apart from each other and two other neighboring electron pairs that are positioned at 120° from each other. The axial position has 3 neighboring electron pairs positioned at 90° from each other and another neighboring electron pair positioned at 120°. Hence the equatorial position experiences lesser repulsion compared to the axial position.
Hence in the structure pictured in the question, position B is a preferred position for the lone pair instead of position A.
To counter the removal of A the equilibrium change by <u>s</u><em>hifting toward the left</em>
<em> </em><u><em>explanation</em></u>
<u><em> </em></u>If the reaction is at equilibrium and we alter the condition a new equilibrium state is created
<u><em> </em></u>The removal of A led to the shift of equilibrium toward the left since it led to less molecules in reactant side which favor the backward reaction.( equilibrium shift to the left)
Answer:
D. The atoms are arranged with alternating positive and negative charges. When struck, the lattice shifts putting positives against positives and negatives against negatives.
Explanation:
Metallic crystals takes their properties as a result of metallic bonds in between the atoms.
Metallic bond is actually the attraction between the positive nuclei of all the closely packed atoms in the lattice and the electron cloud jointly formed by all the atoms by losing their outermost shell electrons this is by virtue of their low ionization energy.
Physical properties of metals such as malleability, ductility, electrical conductivity, etc can be accounted for by metallic bonds.
