All categories

2 years ago

Identify the equations that represent reactions that could occur. Select all that apply.

Chemistry

2 answers:

Natalka [10]2 years ago

7 0

Explanation:

A reaction between two different reactants can only occur if more reactive cation replaces less reactive cation.

Therefore, the given reactions are as follows.

$BaCl_{2}(aq) + Na_{2}SO_{4}(aq) \rightarrow BaSO_{4}(s) + 2NaCl(aq)$

Here, reactive barium replaces less reactive sodium. Thus, there will be formation of barium sulphate and sodium chloride.

$NaBr(aq) + KCl(aq) \rightarrow NaCl(aq) + KCl(aq)$

Here, sodium replaces potassium and result in the formation of NaCl and KBr. But the reaction shows products NaCl and KCl which are not possible. Thus, this reaction will not occur.

$NH_{4}NO_{3}(aq) + AgClO_{3}(aq) \rightarrow AgNO_{3}(aq) + NH_{4}ClO_{3}(aq)$

Here, $NH_{4}$ replaces Ag and result in the formation of $AgNO_{3}$ and $NH_{4}ClO_{3}$ . Therefore, this reaction is possible.

$CH_{3}COOH(aq) + NaHCO_{3}(aq) \rightarrow CH_{3}COONa(aq) + CO_{2}(g) + H_{2}O(l)$

Here, hydrogen of acetic acid is replaced by sodium atom along with formation of carbon dioxide and water. Thus, this reaction is also possible.

$2NaOH(aq) + CaCl_{2}(aq) \rightarrow 2NaCl(aq) +Ca(OH)_{2}(s)$

Here, reactive Na atom replaces Ca atom and results in the formation of NaCl and calcium hydroxide. Thus, this reaction is also possible.

Therefore, identified equations that represent reactions that could occur are as follows.

$BaCl_{2}(aq) + Na_{2}SO_{4}(aq) \rightarrow BaSO_{4}(s) + 2NaCl(aq)$

$NH_{4}NO_{3}(aq) + AgClO_{3}(aq) \rightarrow AgNO_{3}(aq) + NH_{4}ClO_{3}(aq)$

$CH_{3}COOH(aq) + NaHCO_{3}(aq) \rightarrow CH_{3}COONa(aq) + CO_{2}(g) + H_{2}O(l)$

$2NaOH(aq) + CaCl_{2}(aq) \rightarrow 2NaCl(aq) +Ca(OH)_{2}(s)$

Tom [10]2 years ago

4 0

A reaction is apparently said to occur if it proceeds via the formation of a precipitate or a gaseous product, or a visible color change is observed after the reaction.

A) $BaCl_{2}(aq)+Na_{2}SO_{4}(aq)-->BaSO_{4}(s)+2NaCl(aq)$ : This reaction occurs as there is a formation of white precipitate of barium sulfate.

B) NaBr(aq)+KCl(aq)-->NaCl(aq)+KCl(aq): This reaction does not occur because all the ions just remain as spectator ions in the solution as the products are aqueous too.

C) $NH_{4}NO_{3}(aq)+AgClO_{3}(aq)-->AgNO_{3}(aq)+NH_{4}ClO_{3}(aq)$ : This reaction does not occur because all the ions just remain as spectator ions in the solution as the products are aqueous too.

D) $HCH_{3}COO(aq)+NaHCO_{3}(aq)-->NaCH_{3}COO(aq)+CO_{2}(g)+H_{2}O(l)$ :This reaction can be observed as this proceeds via the formation of gas bubbles of carbon dioxide.

E) $2NaOH(aq)+CaCl_{2}(aq)-->2NaCl(aq)+Ca(OH)_{2}(s)$ :This reaction occurs as there is a formation of white precipitate of barium hydroxide.

So the correct answers are:

A) $BaCl_{2}(aq)+Na_{2}SO_{4}(aq)-->BaSO_{4}(s)+2NaCl(aq)$

D) $HCH_{3}COO(aq)+NaHCO_{3}(aq)-->NaCH_{3}COO(aq)+CO_{2}(g)+H_{2}O(l)$

E) $2NaOH(aq)+CaCl_{2}(aq)-->2NaCl(aq)+Ca(OH)_{2}(s)$

You might be interested in

Dolomite is a mixed carbonate of calcium and magnesium. Calcium and magnesium carbonates both decompose upon heating to produce

Setler79 [48]

Answer:

72.03 %

Explanation:

Total mass of dolomite = 9.66 g

Let the mass of Magnesium carbonate = x g

The mass of calcium carbonate = 9.66 - x g

Calculation of the moles of Magnesium carbonate as:-

Molar mass of Magnesium carbonate = 122.44 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{x\ g}{84.3139\ g/mol}=\frac{x}{84.3139}\ mol$

Calculation of the moles of calcium carbonate as:-

Molar mass of calcium carbonate = 100.0869 g/mol

Thus,

$Moles= \frac{9.66 - x\ g}{100.0869\ g/mol}=\frac{9.66 - x}{100.0869}\ mol$

According to the reaction shown below:-

$MgCO_3\rightarrow MgO+CO_2$

$CaCO_3\rightarrow CaO+CO_2$

In both the cases, the oxides formed from the carbonates in the 1:1 ratio.

So, Moles of MgO = $\frac{x}{84.3139}\ mol$

Molar mass of MgO = 40.3044 g/mol

Thus, Mass = Moles*Molar mass = $\frac{x}{84.3139}\times 40.3044 \ g$

Moles of CaO = $\frac{9.66 - x}{100.0869}\ mol$

Molar mass of CaO = 56.0774 g/mol

Thus, Mass = Moles*Molar mass = $\frac{9.66 - x}{100.0869}\times 56.0774 \ g$

Given that total mass of the oxide = 4.84 g

Thus,

$\frac{x}{84.3139}\times 40.3044 +\frac{9.66 - x}{100.0869}\times 56.0774=4.84$

$\frac{40.3044x}{84.3139}+56.0774\times \frac{-x+9.66}{100.0869}=4.84$

$-694.1618435x+45673.48749\dots =40843.38968\dots$

$x=\frac{4830.09780\dots }{694.1618435}$

$x=6.9582$

Thus, the mass of Magnesium carbonate = 6.9582 g

$\%\ mass=\frac{Mass_{MgCO_3}}{Total\ mass}\times 100$

$\%\ mass=\frac{6.9582}{9.66}\times 100=72.03\ \%$

3 0

2 years ago

In order to reduce the exposure to organic solvents like turpentine, some art instructors recommend the students clean brushes a

kykrilka [37]

Generally speaking, organic molecules tend to dissolve in solvents that have similar physical properties. A good rule of thumb is that "like dissolves like". Meaning, polar compounds can dissolve polar compounds and nonpolar compounds can dissolve nonpolar compounds.

To apply this to the current problem, we are told that the brushes are being cleaned with vegetable oil or mineral oil. In this case, the oils are used as solvents. In order for these solvents to be effective, the compounds they are trying to dissolve must be similar in structure and properties to other oils. Therefore, vegetable oil or mineral oil will be most effective in removing oil-based paints, as these will have the similar properties needed to dissolve in the oil solvents.

6 0

2 years ago

List or draw two ways to visually represent C6H14

KonstantinChe [14]

There are several ways to visually represent compounds. For this particular organic compound, we can use the skeletal formula and the expanded formula. The skeletal makes use of lines to show which atoms are bonded to each other. The expanded formula shows the species of the atoms and their bonding with other atoms. I have attached the two representations.

6 0

2 years ago

Determine the normality of the following solutions note the species of interest is H 95 g of PO4 3- in 100mL solution

Aliun [14]

Answer : The normality of the solution is, 30.006 N

Explanation :

Normality : It is defined as the number of gram equivalent of solute present in one liter of the solution.

Mathematical expression of normality is:

$\text{Normality}=\frac{\text{Gram equivalent of solute}}{\text{Volume of solution in liter}}$

or,

$\text{Normality}=\frac{\text{Weight of solute}}{\text{Equivalent weight of solute}\times \text{Volume of solution in liter}}$

First we have to calculate the equivalent weight of solute.

Molar mass of solute $PO_4^{3-}$ = 94.97 g/mole

$\text{Equivalent weight of solute}=\frac{\text{Molar mass of solute}}{\text{charge of the ion}}=\frac{94.97}{3}=31.66g.eq$

Now we have to calculate the normality of solution.

$\text{Normality}=\frac{95g}{31.66g.eq\times 0.1L}=30.006eq/L$

Therefore, the normality of the solution is, 30.006 N

5 0

2 years ago

The table above summarizes data given to a student to evaluate the type of change that took place when substance X was mixed wit

Tamiku [17]

The question is incomplete, the complete question is;

The table above summarizes data given to a student to evaluate the type of change that took place when substance X was mixed with water. The student claimed that the data did not provide enough evidence to determine whether a chemical or physical change took place and that additional tests were needed. Which of the following identifies the best way to gather evidence to support the type of change that occurred when water and Xwere mixed?

A. Measuring the melting point of the mixture of water and X

B. Adding another substance to the mixture of water and X to see whether a solid forms

C Measuring and comparing the masses of the water, X, and the mixture of water and X

D Measuring the electrical conductivities of X and the mixture of water and X

Answer:

D Measuring the electrical conductivities of X and the mixture of water and X

Explanation:

Unfortunately, I am unable to reproduce the table here. However, from the table, the temperature of the of the mixture of the solid X and water was 101.6°C. This is above the boiling point of water and way below the temperature of the solid X.

This goes a long way to suggest that there was some kind of interaction between the water and X which accounted for the observed temperature of the system of X in water.

The only way we can be able to confirm if X actually dissolved in water is to measure the conductivity of the water. dissolved solids increase the conductivity of water.

6 0

1 year ago