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Talja [164]
2 years ago
13

Identify the equations that represent reactions that could occur. Select all that apply.

Chemistry
2 answers:
Natalka [10]2 years ago
7 0

Explanation:

A reaction between two different reactants can only occur if more reactive cation replaces less reactive cation.

Therefore, the given reactions are as follows.

  • BaCl_{2}(aq) + Na_{2}SO_{4}(aq) \rightarrow BaSO_{4}(s) + 2NaCl(aq)

Here, reactive barium replaces less reactive sodium. Thus, there will be formation of barium sulphate and sodium chloride.

  • NaBr(aq) + KCl(aq) \rightarrow NaCl(aq) + KCl(aq)

Here, sodium replaces potassium and result in the formation of NaCl and KBr. But the reaction shows products NaCl and KCl which are not possible. Thus, this reaction will not occur.

  • NH_{4}NO_{3}(aq) + AgClO_{3}(aq) \rightarrow AgNO_{3}(aq) + NH_{4}ClO_{3}(aq)

Here, NH_{4} replaces Ag and result in the formation of AgNO_{3} and NH_{4}ClO_{3}. Therefore, this reaction is possible.

  • CH_{3}COOH(aq) + NaHCO_{3}(aq) \rightarrow CH_{3}COONa(aq) + CO_{2}(g) + H_{2}O(l)

Here, hydrogen of acetic acid is replaced by sodium atom along with formation of carbon dioxide and water. Thus, this reaction is also possible.

  • 2NaOH(aq) + CaCl_{2}(aq) \rightarrow 2NaCl(aq) +Ca(OH)_{2}(s)

Here, reactive Na atom replaces Ca atom and results in the formation of NaCl and calcium hydroxide. Thus, this reaction is also possible.

Therefore, identified equations that represent reactions that could occur are as follows.

  • BaCl_{2}(aq) + Na_{2}SO_{4}(aq) \rightarrow BaSO_{4}(s) + 2NaCl(aq)
  • NH_{4}NO_{3}(aq) + AgClO_{3}(aq) \rightarrow AgNO_{3}(aq) + NH_{4}ClO_{3}(aq)
  • CH_{3}COOH(aq) + NaHCO_{3}(aq) \rightarrow CH_{3}COONa(aq) + CO_{2}(g) + H_{2}O(l)
  • 2NaOH(aq) + CaCl_{2}(aq) \rightarrow 2NaCl(aq) +Ca(OH)_{2}(s)
Tom [10]2 years ago
4 0

A reaction is apparently said to occur if it proceeds via the formation of a precipitate or a gaseous product, or a visible color change is observed after the reaction.

A)BaCl_{2}(aq)+Na_{2}SO_{4}(aq)-->BaSO_{4}(s)+2NaCl(aq): This reaction occurs as there is a formation of white precipitate of barium sulfate.

B) NaBr(aq)+KCl(aq)-->NaCl(aq)+KCl(aq): This reaction does not occur because all the ions just remain as spectator ions in the solution as the products are aqueous too.

C) NH_{4}NO_{3}(aq)+AgClO_{3}(aq)-->AgNO_{3}(aq)+NH_{4}ClO_{3}(aq): This reaction does not occur because all the ions just remain as spectator ions in the solution as the products are aqueous too.

D)HCH_{3}COO(aq)+NaHCO_{3}(aq)-->NaCH_{3}COO(aq)+CO_{2}(g)+H_{2}O(l):This reaction can be observed as this proceeds via the formation of gas bubbles of carbon dioxide.

E) 2NaOH(aq)+CaCl_{2}(aq)-->2NaCl(aq)+Ca(OH)_{2}(s):This reaction occurs as there is a formation of white precipitate of barium hydroxide.

So the correct answers are:

A)BaCl_{2}(aq)+Na_{2}SO_{4}(aq)-->BaSO_{4}(s)+2NaCl(aq)

D)HCH_{3}COO(aq)+NaHCO_{3}(aq)-->NaCH_{3}COO(aq)+CO_{2}(g)+H_{2}O(l)

E) 2NaOH(aq)+CaCl_{2}(aq)-->2NaCl(aq)+Ca(OH)_{2}(s)

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Karo-lina-s [1.5K]

Answer:

Pb(NO3)2

Cd(NO3)2

Na2SO4

Explanation:

In the first part, addition of HCl leads to the formation of PbCl2 which is poorly soluble in water. This is the first precipitate that is filtered off.

When the pH is adjusted to 1 and H2S is bubbled in, CdS is formed. This is the second precipitate that is filtered off.

After this precipitate has been filtered off and the pH is adjusted to 8, addition of H2S and (NH4)2HPO4 does not lead to the formation of any other precipitate.

The yellow flame colour indicates the presence of Na^+ which must come from the presence of Na2SO4.

5 0
1 year ago
What is the enthalpy of reaction for the
nexus9112 [7]

Answer:

\boxed{\text{656.3 kJ/mol}}

Explanation:

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is:

\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})

                         CaCO₃(s) ⟶ CaO(s) + CO₂(g)

ΔH°f/kJ·mol⁻¹:    -1207.1          -157.3    -393.5

\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [-157.3 + (-393.5)] - (-1207.1)\\& = & -550.8 +1207.1\\& = & \textbf{656.3 kJ/mol}\\\end{array}\\\\\text{The enthalpy of decomposition is } \boxed{\textbf{656.3 kJ/mol}}

3 0
1 year ago
Read 2 more answers
What is the mass of 2.5 moles of hydrogen fluoride gas HF
Nady [450]

Answer:

You will get 5.0 g of hydrogen.

Explanation:

As with any stoichiometry problem, we start with the balanced equation.

Sn

l

+

2HF

→

SnF

2

+

H

2

Moles of H

2

=

2.5

mol Sn

×

1 mol H

2

1

mol Sn

=

2.5 mol H

2

Mass of H

2

=

2.5

mol H

2

×

2.016 g H

2

1

mol H

2

=

5.0 g H

2

7 0
2 years ago
The symbol for xenon (Xe) would be a part of the noble gas notation for the element antimony. cesium. radium. uranium.
nlexa [21]
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It means that you use the symbol of the previous noble gas as part of the electron configuration of an element.

The gas noble previous to antimony is Kr, so you do not use Xe to write the electron configuration of Sb.

The gas noble previous to radium is Rn, so you do not use Xe to wirte the electron configuration of Ra.

The gas noble previous to uranium is Rn, so you do  not use Xe to write the electron configuration of U.

The gas noble previous to cesium is Xe, so you use Xe to write the noble notation for Sb. This is it: Cs: [Xe] 6s.

Answer: cesium



The ga
8 0
1 year ago
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In a two-step synthesis where the first reaction has a 55% yield and the second reaction has a 24% yield, the overall percent yi
nekit [7.7K]

Answer:

13,2 %.

Explanation:

Overall yield = 0.55 * 0.24

= 0.132

= 13,2 %.

7 0
1 year ago
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