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Talja [164]
2 years ago
13

Identify the equations that represent reactions that could occur. Select all that apply.

Chemistry
2 answers:
Natalka [10]2 years ago
7 0

Explanation:

A reaction between two different reactants can only occur if more reactive cation replaces less reactive cation.

Therefore, the given reactions are as follows.

  • BaCl_{2}(aq) + Na_{2}SO_{4}(aq) \rightarrow BaSO_{4}(s) + 2NaCl(aq)

Here, reactive barium replaces less reactive sodium. Thus, there will be formation of barium sulphate and sodium chloride.

  • NaBr(aq) + KCl(aq) \rightarrow NaCl(aq) + KCl(aq)

Here, sodium replaces potassium and result in the formation of NaCl and KBr. But the reaction shows products NaCl and KCl which are not possible. Thus, this reaction will not occur.

  • NH_{4}NO_{3}(aq) + AgClO_{3}(aq) \rightarrow AgNO_{3}(aq) + NH_{4}ClO_{3}(aq)

Here, NH_{4} replaces Ag and result in the formation of AgNO_{3} and NH_{4}ClO_{3}. Therefore, this reaction is possible.

  • CH_{3}COOH(aq) + NaHCO_{3}(aq) \rightarrow CH_{3}COONa(aq) + CO_{2}(g) + H_{2}O(l)

Here, hydrogen of acetic acid is replaced by sodium atom along with formation of carbon dioxide and water. Thus, this reaction is also possible.

  • 2NaOH(aq) + CaCl_{2}(aq) \rightarrow 2NaCl(aq) +Ca(OH)_{2}(s)

Here, reactive Na atom replaces Ca atom and results in the formation of NaCl and calcium hydroxide. Thus, this reaction is also possible.

Therefore, identified equations that represent reactions that could occur are as follows.

  • BaCl_{2}(aq) + Na_{2}SO_{4}(aq) \rightarrow BaSO_{4}(s) + 2NaCl(aq)
  • NH_{4}NO_{3}(aq) + AgClO_{3}(aq) \rightarrow AgNO_{3}(aq) + NH_{4}ClO_{3}(aq)
  • CH_{3}COOH(aq) + NaHCO_{3}(aq) \rightarrow CH_{3}COONa(aq) + CO_{2}(g) + H_{2}O(l)
  • 2NaOH(aq) + CaCl_{2}(aq) \rightarrow 2NaCl(aq) +Ca(OH)_{2}(s)
Tom [10]2 years ago
4 0

A reaction is apparently said to occur if it proceeds via the formation of a precipitate or a gaseous product, or a visible color change is observed after the reaction.

A)BaCl_{2}(aq)+Na_{2}SO_{4}(aq)-->BaSO_{4}(s)+2NaCl(aq): This reaction occurs as there is a formation of white precipitate of barium sulfate.

B) NaBr(aq)+KCl(aq)-->NaCl(aq)+KCl(aq): This reaction does not occur because all the ions just remain as spectator ions in the solution as the products are aqueous too.

C) NH_{4}NO_{3}(aq)+AgClO_{3}(aq)-->AgNO_{3}(aq)+NH_{4}ClO_{3}(aq): This reaction does not occur because all the ions just remain as spectator ions in the solution as the products are aqueous too.

D)HCH_{3}COO(aq)+NaHCO_{3}(aq)-->NaCH_{3}COO(aq)+CO_{2}(g)+H_{2}O(l):This reaction can be observed as this proceeds via the formation of gas bubbles of carbon dioxide.

E) 2NaOH(aq)+CaCl_{2}(aq)-->2NaCl(aq)+Ca(OH)_{2}(s):This reaction occurs as there is a formation of white precipitate of barium hydroxide.

So the correct answers are:

A)BaCl_{2}(aq)+Na_{2}SO_{4}(aq)-->BaSO_{4}(s)+2NaCl(aq)

D)HCH_{3}COO(aq)+NaHCO_{3}(aq)-->NaCH_{3}COO(aq)+CO_{2}(g)+H_{2}O(l)

E) 2NaOH(aq)+CaCl_{2}(aq)-->2NaCl(aq)+Ca(OH)_{2}(s)

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Calculate the energy difference for a transition in the paschen series for a transition from the higher energy shell n=4. expres
Troyanec [42]
Electrons are orbiting around the nucleus in a specific energy level as described in Bohr's atomic model. There are 7 energy levels all in all; 1 being the strongest and nearest to the nucleus, and 7 being the weakest and farthest away from the nucleus. Electron can transfer from one energy level to another. If it increases energy, it absorbs energy. If it goes down an energy level, it emits energy in the form of light. This light can be measure in wavelength through the Rydberg equation:

1/λ =R(1/n₁² -1/n₂²), where
λ is the wavelength
R is the Rydberg constant equal to 1.097 × 10⁻7<span> per meter
n</span>₁ and n₂ are the energy levels such that n₂>n₁

In the Paschen series is an emission spectrum of hydrogen when the energy level is at least n=4. So, this covers n=4 to n=7.

1/λ =(1.097 × 10⁻7)(1/4² -1/7²)
λ  = 216.57 ×10⁻⁶ m or 216.57 μm
5 0
2 years ago
In the manufacture of paper, logs are cut into small chips, which are stirred into an alkaline solution that dissolves several o
Kitty [74]

Answer:

The estimated feed rate of logs is 14.3 logs/min.

Explanation:

The product of the process is 2000 tons/day of dry wood pulp, of 85 wt% of cellulose. That represents (2000*0.85)=1700 tons/day of cellulose.

That cellulose has to be feed by the wood chips, which had 47 wt% of cellulose in its composition. That means you need (1700/0.47)=3617 tons/day of wood chips to provide all that cellulose.

Th entering flow is wood chips with 45 wt% of water. This solution has an specific gravity of 0.640.

To know the specific gravity of the wood chips we have to write a volume balance. We also know that Mw=0.45*M and Mc=0.55*M.

V=V_c+V_w\\\\M/\rho=M_c/\rho_c+Mw/\rho_w\\\\M/\rho=0.55*M/\rho_c+0.45*M/\rho_w\\\\1/\rho=0.55/\rho_c +0.45/\rho_w\\\\0.55/\rho_c=1/\rho-0.45/\rho_w\\\\0.55/\rho_c=1/(0.64*\rho_w)-0.45/\rho_w=(1/\rho_w)*(\frac{1}{0.64}-\frac{0.45}{1}  )\\\\0.55/\rho_c=1.1125/\rho_w\\\\\rho_c=\frac{0.55}{1.1125}*\rho_w= 0.494*\rho_w

The specific gravity of the wood chips is 0.494.

The average volume of a log is

V_l=(\pi*D^{2} /4)*L=(3.1416*\frac{8^{2}  \, in^{2} }{4} )*9ft*(\frac{12 in}{1ft})= 21714 in^{3}=12.57 ft^{3}

The weight of one log is

M=\rho*V=0.494*\rho_w*12.57  ft^{3}\\\\M=0.494*62.4\frac{lbm}{ft^{3} }*12.57ft^{3}\\\\M=387.5lbm

To provide 3617 ton/day of wood chips, we need

n=\frac{supply}{M_{log}}=\frac{3617 tons/day}{387.5 lbm}*\frac{2204lbm}{1ton}\\\\n=20573 logs/day=14.3 logs/min

The feed rate of logs is 14.3 logs/min.

7 0
2 years ago
Read 2 more answers
4.82 g of an unknown metal is heated to 115.0∘C and then placed in 35 mL of water at 28.7∘C, which then heats up to 34.5∘C. What
nikitadnepr [17]

<u>Answer:</u> The specific heat of metal is 2.34 J/g°C

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 35 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{35mL}\\\\\text{Mass of water}=(1g/mL\times 35mL)=35g

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]      ......(1)

where,

q = heat absorbed or released

m_1 = mass of metal = 4.82 g

m_2 = mass of water = 35 g

T_{final} = final temperature = 34.5°C

T_1 = initial temperature of metal = 115°C

T_2 = initial temperature of water = 28.7°C

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

4.82\times c_1\times (34.5-110)=-[35\times 4.186\times (34.5-28.7)]

c_1=2.34J/g^oC

Hence, the specific heat of metal is 2.34 J/g°C

4 0
2 years ago
What element is used in bright flashing advertising signs
Sergeu [11.5K]
The element used in advertising signs is neon.
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2 years ago
Gold has always been a highly prized metal, and it has been widely used from the beginning of history as a store of value. It do
Greeley [361]

Answer: The balanced equation is

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The function of HCl in a solution of Aqua regia, that is used to dissolve gold is to dissolve other metals like quartz or iron stone that surround the gold.

Explanation: To balance the equation, we check the ratio of each element in the reacting side and the product side ( left and right hand side). Let their ratio be equal be adding moles to the compound of the element or the element it's self in either side of the equation.

HCl which is called hydrochloric acid, is an acid that does not react with gold, but it react with every other substance, like your skin, metals etc. it is used to clean a gold, by dipping the gold inside it, all the metals on the surface of the gold will dissolve.

When dissolving a gold in aqua regia solution, HCL is added to prepare this solution because it will help to dissolve all other substance on the surface of the gold.

8 0
1 year ago
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