List or draw two ways to visually represent C6H14
1 answer:
There are several ways to visually represent compounds. For this particular organic compound, we can use the skeletal formula and the expanded formula. The skeletal makes use of lines to show which atoms are bonded to each other. The expanded formula shows the species of the atoms and their bonding with other atoms. I have attached the two representations.
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Answer:
The new molar concentration of CO at equilibrium will be :[CO]=1.16 M.
Explanation:
Equilibrium concentration of all reactant and product:
Equilibrium constant of the reaction :
K = 4
Concentration at eq'm:
0.24 M 0.24 M 0.48 M 0.48 M
After addition of 0.34 moles per liter of and
are added.
(0.24+0.34) M (0.24+0.34) M (0.48+x)M (0.48+x)M
Equilibrium constant of the reaction after addition of more carbon dioxide and water:
Solving for x: x = 0.68
The new molar concentration of CO at equilibrium will be:
[CO]= (0.48+x)M = (0.48+0.68 )M = 1.16 M
Answer: 3
Explanation: This is a radioactive decay and all the radioactive process follows first order kinetics.
Equation for the reaction of decay of radioisotope follows:
By the stoichiometry of above reaction,
1 mole of is produced by 1 mole
So, 0.17 moles of will be produced by =
Amount of
decomposed will be = 0.17 moles
Initial amount of will be = Amount decomposed + Amount left = (0.17 + 0.024)moles =0.194 moles
where,
a = amount of reactant left after n-half lives = 0.024
= Initial amount of the reactant = 0.194
n = number of half lives= ?
Putting values in above equation, we get:
Therefore, 3 half lives have passed.