answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ValentinkaMS [17]
1 year ago
6

At a certain temperature K = 1.1 X 10^3 L/mol for the reaction given below. Calculate the concentrations of Fe3+, SCN?, and FeSC

N2+ at equilibrium if 0.020 mol of Fe(NO3)3 is added to 1.0 L of 0.10 M KSCN. (Neglect any volume change.)Fe3+(aq) + SCN ?(aq) FeSCN2+(aq)Fe3+____________MSCN- ______________MFeSCN2+ ____________M
Chemistry
1 answer:
lianna [129]1 year ago
6 0

Answer:

Explanation:

Fe⁺³ + SCN⁻ =  FeSCN²⁺

x           x                x

If x mole of Fe⁺³ reacted , unreacted Fe⁺³ = .02 - x

Remaining SCN⁻  unreacted = .1 - x

K_c =   [ FeSCN²⁺] / [Fe⁺³] [ SCN⁻]

1.1 x 10³ =  x  / ( .02 - x ) (.1 - x )

1100 = x / .002 - .12x ( neglecting x² )

x = .0165

Concentration of Fe⁺³ = .02 - x = .0035 M

Concentration of SCN⁻ = .1 - x = .0835 M

Concentration of FeSCN²⁺ = x = .0165M

You might be interested in
At a given temperature, you have a mixture of benzene (vapor pressure of pure benzene = 745 torr) and toluene (vapor pressure of
swat32
Ideal solutions obey Raoult's law, which states that:

P_i = x_i*(P_pure)_i

where
P_i is the partial pressure of component i above a solution
x_i is the mole fraction of component i in the solution
(P_pure)_i is the vapor pressure of pure component i

In this case,

P_benzene = 0.59 * 745 torr = 439.6 torr
P_toluene = (1-0.59) * 290 torr = 118.9 torr

The total vapor pressure above the solution is the sum of the vapor pressures of the individual components:

P_total = (439.6 + 118.9) torr = 558.5 torr

Assuming the gas phase also behaves ideally, the partial pressure of each gas in the vapor phase is proportional to its molar concentration, so the mole fraction of toluene in the vapor phase is:

118.9 torr/558.5 torr = 0.213
8 0
2 years ago
At –45oC, 71 g of fluorine gas take up 6843 mL of space. What is the pressure of the gas, in kPa?
Anika [276]
The moles of fluorine present are 71/19 = 3.74
Now, we know that one mole of gas at 273 K and 101.3 kPa (S.T.P.) occupies 22.4 liters
Volume of 3.74 moles at S.T.P = 3.74 x 22.4
Volume = 83.776 L = 83,776 mL

Now, we use Boyle's law, that for a given amount of gas,
PV = constant

P x 6843 = 101.3 x 83776
P = 1,240 kPa
4 0
2 years ago
Use the thermodynamic data at 298 k below to determine the ksp for barium carbonate, baco3 at this temperature. substance: ba2+(
jeka57 [31]

Answer : the correct answer for ksp = 1.59 * 10⁻⁹

Following are the steps to calculate the ksp of reaction

BaCO₃ →Ba ²⁺ + CO₃²⁻ :

Step 1 : To find ΔG° of reaction :

ΔG° of reaction can be calculates by taking difference between ΔG° of products and reactants as :

ΔG° reaction =Sum of ΔG° ( products ) - Sum of Δ G° ( reactants ) .

Given : ΔG° for Ba²⁺ ( product )= -560.7 \frac{KJ}{Mol}

ΔG° for CO₃²⁻ (product ) =- 528.1 \frac{KJ}{Mol}

ΔG° BaCO₃ ( reactant) = –1139 \frac{KJ}{Mol}

Plugging value in formula :

ΔG° for reaction = ( ΔG° of Ba ²⁺ + ΔG° of CO₃²⁻ ) - (ΔG° of BaCO₃ )

⁻ = ( -560.7 \frac{KJ}{Mol} + 528.1 \frac{KJ}{Mol} ) - ( -1139 \frac{KJ}{Mol} )

= ( -1088.8 \frac{KJ}{Mol}) - (-1139 \frac{KJ}{Mol} )

= - 1088.8 \frac{KJ}{Mol} + 1139 \frac{KJ}{Mol}

ΔG° of reaction = 50.2 \frac{KJ}{Mol}

Step 2: To calculate ksp from ΔG° of reaction .

The relation between Ksp and ΔG° is given as :

ΔG° = -RT ln ksp

Where ΔG° = Gibb's Free energy R = gas constant T = Temperature

Ksp = Solubility constant product .

Given : ΔG° of reaction = 50.2 \frac{KJ}{Mol}

T = 298 K R = 8.314 \frac{J}{Mol * K}

Plugging values in formula

50.2 \frac{KJ}{mol}  =  -  8.314 \frac{J}{mol * K} * 298 K * ln  ksp

50.2 \frac{KJ}{mol}  =  - 2477.572 \frac{J}{mol} * ln K

((Converting 2477 \frac{J}{mol}  to \frac{KJ}{mol}

Since , 1 KJ = 1000 J So , 2477 \frac{J}{mol}  * \frac{1 KJ}{1000J}  = 2.477 \frac{KJ}{mol} ))

Dividing both side by - 2.477 \frac{KJ}{mol}

\frac{50.2\frac{KJ}{mol}}{-2.477 \frac{KJ}{mol}} = \frac{-2.477 \frac{KJ}{mol}}{-2.477 \frac{KJ}{mol}} * ln ksp

ln ksp = ln ksp = -20.27 \frac{KJ}{mol}

Removing ln :

ksp = 1. 59 * 10⁻⁹

8 0
2 years ago
X-rays have a wavelength small enough to image individual atoms, but are challenging to detect because of their typical frequenc
Cerrena [4.2K]

Explanation:

Given: \lambda = 8.38\:\text{nm} = 8.38×10^{-9}\:\text{m}

Its frequency \nu is defined as

\nu = \dfrac{c}{\lambda} = \dfrac{3×10^8\:\text{m/s}}{8.38×10^{-9}\:\text{m}}

\:\:\:\:= 3.58×10^{16}\:\text{Hz}

7 0
1 year ago
A block of copper of unknown mass has an initial temperature of 65.4 degress celcuis. THe copper is immersed in a beaker contain
Zigmanuir [339]

Answer:

The answer to your question is: m = 37.88 g

Explanation:

Data

                  Copper                   Water

mass               ?                          95.7 g

Cp               0.092 cal/g°C        1 cal/g°C

T1                65.4°C                     22.7°C

T2                24.2°C                    24.2°C

Formula

                   Q copper = Q water

Q = mCp(T2 - T1)

                  - m(0.092)(24.2 - 65.4) = 95.7(1)(24.2 - 22.7)

                   m = 95.7(1)(24.2 - 22.7) /- (0.92)(24.2 - 65.4)

                   m = 143.55 / 3.79

                   m = 37.88 g

6 0
2 years ago
Other questions:
  • Starting with 1.5052g of BaCl2•2H2O and excessH2SO4, how many grams of BaSO4 can be formed?
    5·2 answers
  • 0.01 M HCl solution has a pH of 2. Suppose that during the experiment, both the universal pH indicator and the cabbage indicator
    14·4 answers
  • How would you prepare 100 ml of 0.4 M MgSO4 from a stock solution of 2 M MgSO4?
    11·1 answer
  • A. what are substances called whose water solutions conduct electricity?
    12·1 answer
  • Three 1.0-l flasks, maintained at 308 k, are connected to each other with stopcocks. initially the stopcocks are closed. one of
    12·1 answer
  • A cubic box with sides of 20.0 cm contains 2.00 × 1023 molecules of helium with a root-mean-square speed (thermal speed) of 200
    12·1 answer
  • A 1.80 g sample of barium chloride hydrate, BaCl2 ⋅ xH2O is treated with excess sulfuric acid, forming a BaSO4 precipitate which
    6·2 answers
  • Mori walks into a restaurant. Upon smelling the food cooking, her mouth starts to water. Which system in the body detected the i
    7·2 answers
  • The process of water migrating from areas of low electrolyte concentration to area of high electrolyte concentration is called —
    5·1 answer
  • Which of the following is a class 3 surgical candidate
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!