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Eddi Din [679]
1 year ago
10

How is the periodic law demonstrated in halogens

Chemistry
2 answers:
Zina [86]1 year ago
4 0

Answer:

The periodic law demonstrated in halogens by:

All halogens have the same number of valence electrons and similar chemical properties

Explanation:

  • The halogen are located in the group of seven A of the periodic table example of halogen are iodine and chlorine.
  • The halogens are the reactive non-metals in the periodic table, it reacts with alkali metals.
  • Halogen responds with iron, iron wool outbreak into flames when it responds with fluorine gas.
  • Halogen range from solid to liquid to gaseous at room temperature.

inn [45]1 year ago
3 0
Halogens is defined as the group of 7 periodic table. As, every periodic table contains 7 valence electrons and they only need 1 more to complete an outer shell, that is why they are extremely reactive. And according to the law that recurring patterns of the properties of elements arise when they are arranged in order of increasing atomic number. As the halogen all act very similarly with each other in chemical reaction, it is true.
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The pressure of a 609.64 gram sample of F2 in a 88.84 L container is measured to be 2770.96 torr. What is the temperature of thi
Oxana [17]

Answer : The temperature of the gas is, 245.9 K

Explanation :

To calculate the temperature of gas we are using ideal gas equation:

PV=nRT\\\\PV=\frac{w}{M}RT

where,

P = pressure of gas = 2770.96 torr = 3.646 atm

Conversion used : (1 atm = 760 torr)

V = volume of gas = 88.84 L

T = temperature of gas = ?

R = gas constant = 0.0821 L.atm/mole.K

w = mass of gas = 609.64 g

M = molar mass of F_2 gas = 38 g/mole

Now put all the given values in the ideal gas equation, we get:

(3.646atm)\times (88.84L)=\frac{609.64g}{38g/mole}\times (0.0821L.atm/mole.K)\times (T)

T=245.9K

Therefore, the temperature of the gas is, 245.9 K

4 0
2 years ago
The specific rotation of (R) carvone is (+) 61°. The optical rotation of a sample of a mixture of R &S carvone is measured a
shusha [124]

Answer:

See explanation

Explanation:

% optical purity = specific rotation of mixture/specific rotation of pure enantiomer  * 100/1

specific rotation of mixture = 23°

specific rotation of pure enantiomer = 61°

Hence;

% optical purity = 23/61 * 100 = 38 %

More abundant enantiomer = 100% - 38 % = 62%

Hence the pure  (S) carvone is (-) 62° is the more abundant enantiomer.

Enantiomeric excess = 62 - 50/50 * 100 = 24%

Hence

(R) - carvone  =  38 %

(S) - carvone = 62%

7 0
1 year ago
Read 2 more answers
Δs is negative for the reaction __________.
pickupchik [31]
ΔS =S(products) -S(reactants)

Where ΔS is the change of  entropy in a reactions

a. ΔS = (2) - (2+1) = -1
b. ΔS = (1+1) -(1) = 1
c. ΔS = (1+2) - (1) = 2
d. ΔS = (2) - (2+1) = -1
e. ΔS = (1) - (1) = 0

ΔS is negative for reaction a. and d.
6 0
2 years ago
Naomi is investigating the properties of a solid material. It takes 120 joules to raise the temperature of 10 grams of the mater
MrRissso [65]
When heat energy is supplied to a material it can raise the temperature of mass of the material.
Specific heat is the amount of energy required by 1 g of material to raise the temperature by 1 °C.
equation is 
H = mcΔt
H - heat energy 
m - mass of material 
c - specific heat of the material 
Δt - change in temperature
substituting the values in the equation 
120 J = 10 g x c x 5 °C
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3 0
2 years ago
An organic acid is composed of carbon (68.84%), hydrogen (4.96%), and oxygen (26.20%). Its molar mass is 122.12 g/mol. Determine
nekit [7.7K]

Answer:

The molecular formula of the compound is C_{7}H_{6}O_{2}.

Explanation:

Let consider that given percentages are mass percentages, so that mass of each element are determined by multiplying molar massof the organic acid by respective proportion. That is:

Carbon

m_{C} = \frac{68.84}{100}\times \left(122.12\,\frac{g}{mol} \right)

m_{C} = 84.067\,g

Hydrogen

m_{H} = \frac{4.96}{100}\times \left(122.12\,\frac{g}{mol} \right)

m_{H} = 6.057\,g

Oxygen

m_{O} = \frac{26.20}{100}\times \left(122.12\,\frac{g}{mol} \right)

m_{O} = 31.995\,g

Now, the number of moles (n), measured in moles, of each element are calculated by the following expression:

n = \frac{m}{M}

Where:

m - Mass of the element, measured in grams.

M- Molar mass of the element, measured in grams per mol.

Carbon (m_{C} = 84.067\,g, M_{C} = 12.011\,\frac{g}{mol})

n = \frac{84.067\,g}{12.011\,\frac{g}{mol} }

n = 7

Hydrogen (m_{H} = 6.057\,g, M_{H} = 1.008\,\frac{g}{mol})

n = \frac{6.057\,g}{1.008\,\frac{g}{mol} }

n = 6

Oxygen (m_{O} = 31.995\,g, M_{O} = 15.999\,\frac{g}{mol})

n = \frac{31.995\,g}{15.999\,\frac{g}{mol} }

n = 2

For each mole of organic acid, there are 7 moles of carbon, 6 moles of hydrogen and 2 moles of oxygen. Hence, the molecular formula of the compound is:

C_{7}H_{6}O_{2}

8 0
1 year ago
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