answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natta225 [31]
1 year ago
7

Select the correct characteristics describing normal-phase and reversed-phase chromatography. Normal-phase chromatography Revers

ed-phase chromatography (a) Polarity of phases: 1. Stationary phase is polar 2. Stationary phase is non polar b) Eluent strength of solvent. 1. Increases as solvent becomes more polar. 2. Increases as solvent becomes less polar c) Nature of solutes. 1. Polar 2. Non-polar d) Nature of solute interaction. 1. More soluble in mobile phase as the polarity of the mobile phase increases. 2. More soluble in mobile phase as the polarity of the mobile phase decreases. e) Polarity of phases: 1. Stationary phase is polar 2. Stationary phase is non-polar f) Eluent strength of solvent: 1. Increases as solvent becomes more polar. 2. Increases as solvent becomes less polar. g) Nature of solutes: 1. Polar 2. Non-Polar h) Nature of solute interaction: 1. More soluble in mobile phase as the polarity of the mobile phase increases. 2. More soluble in mobile phase as the polarity of the mobile
Chemistry
1 answer:
qwelly [4]1 year ago
3 0

Answer:

(a) Polarity of phase: 1. Stationary phase is polar

b) Eluent strength of solvent:  1. Increases as solvent becomes more polar

c) Nature of solutes.1. Polar

d) Nature of solute interaction:2. More soluble in mobile phase as the polarity of the mobile phase decreases

e) Polarity of phases: 1. Stationary phase is polar

f) Eluent strength of solvent: 1. Increases as solvent becomes more polar.

g) Nature of solutes: 1. Polar

h) Nature of solute interaction: 2. More soluble in mobile phase as the polarity of the mobile

Explanation:

You might be interested in
The diagram below shows the different phase transitions that occur in matter. Which arrow represents the transition in which dew
oksian1 [2.3K]

Answer:

  • <u>The arrow labeled 4: from gas to liquid.</u>

Explanation:

<em>Dew</em> is a manifestation of water condensation.

The air that surrounds us contains water vapor (humidity) from the evaporatoin of the water in the rivers, lakes, and the water with which you water the plants of your garden.

During the night, and specially in the early morning, before dawn, the temperature of the air descends, and part of the vapor in the air condensates in tiny droplets that accumulate over the surface of the plant's leaves, and other solid surfaces like the winshields and hoods of the cars.

Then, the phase transition that occurs is from gas (vapor) to liquid, which is called condensation and represented with the arrow labeled 4 on the diagram.

3 0
1 year ago
Read 2 more answers
Suppose you are titrating vinegar, which is an acetic acid solution of unknown strength, with a sodium hydroxide solution accord
Marina CMI [18]

Answer:

M_{acid}=0.563M

Explanation:

Hello there!

In this case, given the neutralization of the acetic acid as a weak one with sodium hydroxide as a strong base, we can see how the moles of the both of them are the same at the equivalence point; thus, it is possible to write:

M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the molarity of the acid to obtain:

M_{acid}=\frac{M_{base}V_{base}}{V_{acid}} \\\\ M_{acid}=\frac{33.98mL*0.1656M}{10.0mL}\\\\ M_{acid}=0.563M

Regards!

5 0
2 years ago
A solution is prepared by dissolving 10.0 g of NaBr and 10.0 g of Na2SO4 in water to make a 100.0 mL solution. This solution is
Colt1911 [192]

Answer:

M_{Na^+}=1.36M

M_{Br^-}=1.58M

Explanation:

Hello,

At first, it turns out convenient to compute the total moles of sodium that will be dissolved into the solution by considering the added amounts of sodium bromide and sodium sulfate:

n_{Na^+}=n_{Na^+,NaBr}+n_{Na^+,Na_2SO_4}\\n_{Na^+,NaBr}=10.0gNaBr*\frac{1molNaBr}{103gNaBr}*\frac{1molNa^+}{1molNaBr}=0.0971molNa^+\\n_{Na^+,Na_2SO_4}=10.0gNa_2SO_4*\frac{1molNa_2SO_4}{142gNa_2SO_4}*\frac{2molNa^+}{1molNa_2SO_4} =0.141molNa^+\\n_{Na^+}=0.0971molNa^++0.141molNa^+\\n_{Na^+}=0.238molNa^+

Once we've got the moles we compute the final volume via:

V=100.0mL+75.0mL=175.0mL*\frac{1L}{1000mL}=0.1750L

Thus, the molarity of the sodium atoms turn out into:

M_{Na^+}=\frac{0.238mol}{0.1750L} =1.36M

Now, we perform the same procedure but now for the bromide ions:

n_{Br^-}=n_{Br^-,NaBr}+n_{Br^-,AlBr_3}\\n_{Br^-,NaBr}=10.0gNaBr*\frac{1molNaBr}{103gNaBr}*\frac{1molBr^-}{1molNaBr}=0.0971molBr^-\\n_{Br^-,AlBr_3}=0.0750L*0.800\frac{molAlBr_3}{L} *\frac{3molBr^-}{1molAlBr_3}=0.180molBr^- \\n_{Br^-}=0.0971molBr^-+0.180molBr^-\\n_{Br^-}=0.277molBr^-

Finally, its molarity results:

M_{Br^-}=\frac{0.277molBr^-}{0.1750L}=1.58M

Best regards.

7 0
2 years ago
DNA can be replicated through an in vivo mechanism or a polymerase chain reaction (PCR) mechanism. Match each description to the
umka2103 [35]

Complete question from other source attached

Answer:

Explanation:

Catalyzed by DNA polymerase - both. DNA polymerase catalyzes DNA replication in the cell. However, purified versions of the enzyme are also used to synthesise DNA as part of PCR reactions

involves leading strand synthesis only - PCR. In PCR, lagging strand synthesis is not carried out because the DNA is denatured (rendered single stranded). Therefore, each strand is replicated independently by leading strand synthesis

duplicates a small fragment of the genome - PCR. Usually, to carry out PCR, small sequences called primers are used that specify the region of DNA to be replicated

duplicates the entire genome - in vivo replication - when the DNA is replicated in vivo, the entire genome is replicated. This is carried out prior to cell division so that two daughter cells can each inherit a copy of the entire genome

7 0
2 years ago
Which of these did your answer include? High boiling and melting points: Hydrogen bonds increase the amount of energy required f
scZoUnD [109]

Here we have to get the right answers which include the given phrase.

The correct answers are as following:

High boiling and melting points: Hydrogen bond increase the amount of energy required for phase changes to occur, thereby raising the boiling and melting points.

High specific heat: Hydrogen bond increase the amount of energy required for molecules to increase the speed, thereby raising the specific heat.

High surface tension: Hydrogen bonds produce strong inter molecular attractions, which increase surface tension.

The incorrect answer:

Lower density as a solid than as a liquid: actually, density of solid is more than density of liquid as hydrogen bonds in solid produce strong inter molecular attractions among molecules, which aggregates molecules together, hence volume of associated molecules reduces. Therefore, density of solid is more than that of liquid.

7 0
2 years ago
Read 2 more answers
Other questions:
  • What is an example in which a scientists might calculate the mean of a data set
    10·1 answer
  • 2C6H5COOH + 15O2 → 14CO2 + 6H2O which of the following options gives the correct product:product ratio?
    12·1 answer
  • The technetium-99 nuclide radioactively decays by beta emission. write a balanced nuclear chemical equation that describes this
    8·1 answer
  • Are carboxylic acids of more than 10 carbons more soluble in polar or nonpolar solvents? Explain.
    15·1 answer
  • A 25.0-mL sample of a 1.20 M potassium chloride solution is mixed with 15.0 mL of a 0.900 M lead(II) nitrate solution and this p
    12·1 answer
  • If 252 grams of iron are reacted with 321 grams of chlorine gas, what is the mass of the excess reactant leftover after the reac
    14·2 answers
  • The reaction N2 + 3 H2 → 2 NH3 is used to produce ammonia. When 450. g of hydrogen was reacted with nitrogen, 1575 g of ammonia
    5·1 answer
  • A metal, M , of atomic mass 56 amu reacts with chlorine to form a salt that can be represented as MClx. A boiling point elevatio
    8·1 answer
  • f 23.6 mL of 0.200 M NaOH is required to neutralize 10.00 mL of a H3PO4 solution , what is the concentration of the phosphoric a
    9·2 answers
  • 0.15 gm of metallic oxide was dissolved in 100 ml of 0.1 N H2SO4 and 25.8 ml of 0.095N NaOH were used to neutralise the remainin
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!