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natta225 [31]
2 years ago
7

Select the correct characteristics describing normal-phase and reversed-phase chromatography. Normal-phase chromatography Revers

ed-phase chromatography (a) Polarity of phases: 1. Stationary phase is polar 2. Stationary phase is non polar b) Eluent strength of solvent. 1. Increases as solvent becomes more polar. 2. Increases as solvent becomes less polar c) Nature of solutes. 1. Polar 2. Non-polar d) Nature of solute interaction. 1. More soluble in mobile phase as the polarity of the mobile phase increases. 2. More soluble in mobile phase as the polarity of the mobile phase decreases. e) Polarity of phases: 1. Stationary phase is polar 2. Stationary phase is non-polar f) Eluent strength of solvent: 1. Increases as solvent becomes more polar. 2. Increases as solvent becomes less polar. g) Nature of solutes: 1. Polar 2. Non-Polar h) Nature of solute interaction: 1. More soluble in mobile phase as the polarity of the mobile phase increases. 2. More soluble in mobile phase as the polarity of the mobile
Chemistry
1 answer:
qwelly [4]2 years ago
3 0

Answer:

(a) Polarity of phase: 1. Stationary phase is polar

b) Eluent strength of solvent:  1. Increases as solvent becomes more polar

c) Nature of solutes.1. Polar

d) Nature of solute interaction:2. More soluble in mobile phase as the polarity of the mobile phase decreases

e) Polarity of phases: 1. Stationary phase is polar

f) Eluent strength of solvent: 1. Increases as solvent becomes more polar.

g) Nature of solutes: 1. Polar

h) Nature of solute interaction: 2. More soluble in mobile phase as the polarity of the mobile

Explanation:

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Oxide formation by heating element in oxygen atmosphere are best classified as which type of reaction?a. Synthesis b. Double dis
Bond [772]

Answer: a. Synthesis

Explanation:

a. Synthesis reaction is a chemical reaction in which two reactants are combining to form one product.

Example: Mg+O_2\rightarrow 2MgO  

Thus magnesium in its elemental form is combining with oxygen to form magnesium oxide.

b. Double displacement reaction is one in which exchange of ions take place.  

Example: 2NaOH(aq)+(NH_4)_2SO_4(aq)\rightarrow 2NH_4OH(aq)+Na_2SO_4(aq)

c. Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.

Example: Li_2CO_3\rightarrow Li_2O+CO_2

5 0
2 years ago
If 200 mL of water is evaporated from 400 mL of 0.5 M aqueous salt solution, what is the resulting concentration? 1. 2.5 × 10−1
ikadub [295]

Answer:

None of these

Explanation:

Using the dilution formula;

M1V1 = M2V2

where M1 is the initial concentration, V1 is the initial volume, M2 is the concentration attained while V2 is the new volume.

Therefore;

M2 = M1V1/V2

     = (400 mL × 0.5) / 200 mL

     = 1 M

Therefore, the resulting concentration is 1M

Thus, the correct answer is "none of these"

5 0
2 years ago
3350 J of heat is required to raise the temperature of a sample of AlF3 from 250C to 800C. What is the mass of the sample?
Aleonysh [2.5K]

Answer:

  1. Look up the specific heat capacity of AlF₃
  2. Calculate ΔT
  3. Calculate the mass of AlF₃

Explanation:

The formula for for the heat (q) absorbed by an object is

 q = mCΔT, where

m = the mass of the sample

 C = the specific heat capacity of the sample. and

ΔT = the change in temperature

1. What you must do

  • Look up the specific heat capacity of AlF₃
  • Calculate ΔT
  • Calculate the mass of AlF₃

2. Sample calculation

For this example, I assume that the specific heat capacity of AlF₃ is 1.16 J·K⁻¹mol⁻¹ .

(a) Calculate ΔT  

\Delta T = T_{\text{f}} - T_{\text{i}} = 800 \, ^{\circ}\text{C} -250 \, ^{\circ}\text{C} = 550 \, ^{\circ}\text{C}

(b) Calculate m

\begin{array}{rcl}\text{3350 J} & = & m \times 1.16 \text{ J}\cdot\text{K}^{-1} \text{mol}^{-1}\times \text{550 K}\\3350 & = & m \times \text{638 g}^{-1}\\m & = &\dfrac{3350}{\text{638 g}^{-1}}\\\\ & = & \text{ 5.2 g}\\\end{array}\\

6 0
2 years ago
Given the reaction: H2O2(l) ⇌ H2(g) + O2(g) The forward reaction is endothermic. Determine which of the following changes would
Vlad [161]

Answer:

I and IV

Explanation:

Increasing the number of particles at one side of the reaction (H2 in this case) results in the shifting of the equilibrium to the side with lesser number of particles, so in this case the equilibrium will shift to the left (towards the reactants)

A decrease in temperature will always function to favor the exothermic reaction, and since the backwards reaction is exothermic, the equilibrium will shift to the left (towards the reactants).

Option II and V will shift the equilibrium to the products, and adding a catalyst has no effect on the equilibrium.

<h3>Hope this helps!</h3>
8 0
2 years ago
A solution contains 0.115 mol h2o and an unknown number of moles of nacl. the vapor pressure of the solution at 30°c is 25.7 tor
Valentin [98]
According to Raoult's low:
We will use this formula: Vp(Solution) = mole fraction of solvent * Vp(solvent)
∴ mole fraction of solvent = Vp(Solu) / Vp (Solv)
when we have Vp(solu) = 25.7 torr & Vp(solv) = 31.8 torr 
So by substitution:
∴ mole fraction of solvent = 25.7 / 31.8 =0.808 
when we assume the moles of solute NaCl = X 
and according to the mole fraction of solvent formula:
mole fraction of solvent = moles of solvent / (moles of solvent + moles of solute)
by substitute:
∴ 0.808 = 0.115 / (0.115 + X)
 So X (the no.of moles of NaCl) = 0.027 m
8 0
2 years ago
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