Explanation:
Vapor pressure is defined as the pressure exerted by vapors or gas on the surface of a liquid.
Vapor pressure is inversely proportional to the number of solute particles. Hence, more will be the solute particles lower will be the vapor pressure and vice-versa.
(a) 
It dissociates to give two particles.
(b) 
Total number of particles it give upon dissociation are 1 + 2 = 3. Hence, it gives 3 particles.
(c) 
Total number of particles it give upon dissociation are 1 + 3 = 4. Hence, it gives 4 particles.
(d) Surcose being a cobvalent compound doe not dissociate into ions. Therefore, there will be only 1 particle is present.
(e) 
Total number of particles it give upon dissociation are 1 + 1 = 2. Hence, it gives 2 particles.
Answer: There are 20 carbons atoms, 62 oxygen atoms and 44 carbon atoms on the left side of the equation.
Explanation:
In the given chemical reaction:
Reactants side = Left side
Number of atoms =
Coefficient × Number of atoms of an element in a unit molecular formula
Number of carbon atoms = 2 × 10 = 20
Number of oxygen atoms = 31 × 2 = 62
Number of hydrogen atoms = 2 × 22 = 44
Answer:
The pH of 0.1 M BH⁺ClO₄⁻ solution is <u>5.44</u>
Explanation:
Given: The base dissociation constant: 
= 1 × 10⁻⁴, Concentration of salt: BH⁺ClO₄⁻ = 0.1 M
Also, water dissociation constant: 
= 1 × 10⁻¹⁴
<em><u>The acid dissociation constant </u></em>(
)<em><u> for the weak acid (BH⁺) can be calculated by the equation:</u></em>
<em><u>Now, the acid dissociation reaction for the weak acid (BH⁺) and the initial concentration and concentration at equilibrium is given as:</u></em>
Reaction involved: BH⁺ + H₂O ⇌ B + H₃O+
Initial: 0.1 M x x
Change: -x +x +x
Equilibrium: 0.1 - x x x
<u>The acid dissociation constant: </u>![K_{a} = \frac{\left [B \right ] \left [H_{3}O^{+}\right ]}{\left [BH^{+} \right ]} = \frac{(x)(x)}{(0.1 - x)} = \frac{x^{2}}{0.1 - x}](https://tex.z-dn.net/?f=K_%7Ba%7D%20%3D%20%5Cfrac%7B%5Cleft%20%5BB%20%5Cright%20%5D%20%5Cleft%20%5BH_%7B3%7DO%5E%7B%2B%7D%5Cright%20%5D%7D%7B%5Cleft%20%5BBH%5E%7B%2B%7D%20%5Cright%20%5D%7D%20%3D%20%5Cfrac%7B%28x%29%28x%29%7D%7B%280.1%20-%20x%29%7D%20%3D%20%5Cfrac%7Bx%5E%7B2%7D%7D%7B0.1%20-%20x%7D)
<u>Therefore, the concentration of hydrogen ion: x = 3.6 × 10⁻⁶ M</u>
Now, pH = - ㏒ [H⁺] = - ㏒ (3.6 × 10⁻⁶ M) = 5.44
<u>Therefore, the pH of 0.1 M BH⁺ClO₄⁻ solution is 5.44</u>
Sodium Chloride because its still a liquid at the 773 temperature mark<span />
The equilibrium constant Kc for this reaction is calculated as follows
from the equation N2 + 3H2 =2 NH3
qc = (NH3)2/{(N2)(H2)^3}
Qc is therefore = ( 0.001)2 /{(0.1) (0.05)^3} = 0.08
