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Viefleur [7K]
1 year ago
14

Find the empirical formula of each of the following compounds. Given mass or for each element in a sample of the compound 3,611

g Ca; 6.389 g C1
Chemistry
1 answer:
KengaRu [80]1 year ago
8 0

Answer:

CaCl₂  

Step-by-step explanation:

The <em>empirical formula</em> is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Ca to Cl.

Data:

Mass of Ca = 3.611 g

Mass of Cl = 6.389 g

Calculations

Step 1. <em>Calculate the moles of each element </em>

Moles of Ca = 3.611 g Ca × (1 mol Ca/(40.08 g Ca)= 0.090 10 mol Ca

Moles of Cl = 6.389 g Cl  

Step 2. <em>Calculate the molar ratio of the elements </em>

Divide each number by the smallest number of moles

Ca:Cl = 0.090 10:0.1802 = 1:2.000

Step 3. Round the molar ratios to the nearest integer

Ca:Cl = 1:2.000 ≈ 1:2


Step 4: <em>Write the empirical formula </em>

EF = CaCl₂

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More here: https://www.hasd.org/faculty/AndrewSchweitzer/spectroscopy.pdf

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Uranium–232 has a half–life of 68.9 years. A sample from 206.7 years ago contains 1.40 g of uranium–232. How much uranium was or
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The equation used to calculate half life for first order kinetics:

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