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IRISSAK [1]
2 years ago
11

A plastic cup is filled with 15.5 grams of water. The cup is sealed and placed in the freezer. The water freezes and turns to ic

e. The next day, the ice is taken out of the cup and massed. What is the mass of the ice?
Chemistry
1 answer:
HACTEHA [7]2 years ago
7 0
It should be the same

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What is the energy of x radiation with a 1 x 10^-6 wavelength?
const2013 [10]

Answer:

Use E = h*c / lambda, where h is Planck's constant, c is the speed of light, and lambda is the wavelength.  

E = (6.626 * 10^-34 J*s x 3.00 * 10^8 m/s) / (1*10^-6 m) = 1.99 * 10^-19 J

Explanation:

6 0
2 years ago
Determine the PH at the point in the titration of 40.0ml of 0.200M HC4H7o2 with 0.100 M Sr(OH)2 after 100ml of the strong base h
Dmitriy789 [7]

Answer:

Check the explanation

Explanation:

Mols HC4H7O2 = (volume in L)*(molarity) = (40.0 mL)*(0.200 M)

= (40.0 mL)*(1 L)/(1000 mL)*(0.200 M)

= 8.00*10-3 mol.

Mols Sr(OH)2 corresponding to 10.0 mL of 0.100 M solution =

(volume in L)*(molarity)

= (10.0 mL)*(0.100 M)

= (10.0 mL)*(1 L)/(1000 mL)*(0.100 M)

= 1.00*10-3 mol.

Consider the ionization of Sr(OH)2 as below.

Sr(OH)2 (aq) ----------> Sr2+ (aq) + 2 OH- (aq)

As per the stoichiometric equation,

1 mol Sr(OH)2 = 2 mols OH-.

Therefore,

0.0010 mol Sr(OH)2 = [0.0010 mol Sr(OH)2]*(2 mols OH-)/[1 mole Sr(OH)2]

= 0.0020 mol

= 2.00*10-3 mol

Set up the ICE charts as below.

HC4H7O2 (aq) + OH- (aq) ------------> H2O (l) + C4H7O2- (aq)

Before (mol)        8.00*10-3         2.00*10-3                           -                -

Change (mol)      -2.00*10-3       -2.00*10-3                           -        +2.00*10-3

After (mol)           6.00*10-3                0                                  -          2.00*10-3

The change in a pure substance, e.g., H2O is not considered in an acid-base reaction.

Volume of the solution = (40.0 + 10.0) mL = 50.0 mL = (50.0 mL)*(1 L)/(1000 mL) = 0.05 L.

The initial concentrations are obtained by dividing the numbers of moles by the volume, 0.05 L.

Set up the ICE charts as below.

HC4H7O2 (aq) + OH- (aq) ------------> H2O (l) + C4H7O2- (aq)

Initial (M)             0.160               0.0400                             -                -

Change (M)        -0.0400            -0.0400                            -           +0.0400

Equilibrium (M) 0.120                     0                                  -            0.0400

The acid-ionization constant is written as

Ka = [H3O+][C4H7O2-]/[HC4H7O2] = 1.5*10-5

Plug in the known values and get

Ka = [H3O+]*(0.0400)/(0.120) = 1.5*10-5

======> [H3O+] = (1.5*10-5)*(0.120)/(0.0400) (ignore units)

======> [H3O+] = 4.5*10-5

The proton concentration of the solution is 4.5*10-5 M.

pH = -log (4.5*10-5 M)

= 4.346

≈ 4.35 (ans).

8 0
2 years ago
Convert 1.3902 hectoliters to centiliters.
hram777 [196]
<span>The answer is 13,902 centiliters.

</span>
8 0
2 years ago
Read 2 more answers
Element X reacts with copper to form the compounds CuX and CuX2. In which group on the Periodic Table is element X found?
lapo4ka [179]
Cu has two possible charges: plus 1 and plus 2. Thus, when copper is combined with an anion (negatively charged ion), the anion carries a subscript of one or two. This is shown in the given, Moreover, the given shows copper carries a subscript only of one. This means the anion has an original charge of negative one. These elements belong to the halogen family (Group 17).
5 0
2 years ago
If an atom has sp3d2 hybridization in a molecule:
never [62]

Answer:

a. the maximum number of σ bonds that the atom can form is 4

b. the maximum number of p-p bonds that the atom can form is 2

Explanation:

Hybridization is the mixing of at least two nonequivalent orbitals, in this case, we have the mixing of one <em>s, 3 p </em> and <em> 2 d </em> orbitals. In hybridization the number of hybrid orbitals generated  is equal to the number of pure atomic orbital, so we have 6 hybrid orbital.

The shape of this hybrid orbital is octahedral (look the attached image) , it has 4 orbital located in the plane and 2 orbital perpendicular to it.

This shape allows the formation of maximum 4 σ bond, because σ bonds are formed by orbitals overlapping end to end.

And maximum 2 p-p bonds, because p-p bonds are formed by sideways overlapping orbitals. The atom can form one with each one of the orbitals located perpendicular to the plane.

4 0
2 years ago
Read 2 more answers
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