<span>I believe the correct 2nd reaction is:</span>
cof2(g)⇌1/2 co2(g)+1/2 cf4(g)
where we can see that it is exactly one-half of the
original
Therefore the new Kp is:
new Kp = (old Kp)^(1/2)
new Kp = (2.2 x 10^6)^(1/2)
<span>new Kp = 1,483.24 </span>
The oxidation state of hydrogen gas is 0 and oxidation state of hydrogen cation is +1.
There’s an increase in oxidation number therefore it’s an oxidation reaction.
Oxidation reactions give out electrons. The masses and charges on both sides should be balanced
Half reaction is
H2 —> 2H+ +2e
Answer: The enthalpy of the reaction is -109 kJ
Explanation:
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
(1)
(2)
The final reaction is:
Subtracting (2) from (1):

Thus the enthalpy of the reaction is -109 kJ
Answer: explained below
Explanation:
Matter can change form through physical and chemical changes, but through any of these changes, matter is conserved. The same amount of matter exists before and after the change—none is created or destroyed.