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omeli [17]
2 years ago
9

THESE QUESTIONS ARE ELECTRICIAN REALATED

Chemistry
2 answers:
aleksandr82 [10.1K]2 years ago
8 0

SoRry im kind of new i dont know how to comment and ask questions

Vladimir [108]2 years ago
4 0

<span>1.      </span>A.

It is a technique typically engaged in electrical power and electronic devices, wherein the devices are run at less than their rated maximum power degeneracy, taking into account the case or body temperature, the ambient temperature and the type of cooling mechanism used.

<span>2.      </span>B.

In order to answer the question, you need to know the area of a circle.<span>
Area = pi * r^2
Area = 3.14 * (100/2) ^ 2
Area = 3.14 * 50^2
Area = 7850 mils^2 = 0.00785 in^2</span>

<span>3.      </span>A.

V / 15 A = 0.213 Ohm <span>
0.213 Ohm / 125 ft * 1000 ft = 1.71 Ohm / 1000 ft 
Closest gauge is #12 AWG (solid wire) 
#12 is 1.588 Ohm / ft, which is a 2.9775 V drop @ 15A</span>

<span>4.      </span>A.

RHW cale insulation can be used up to 167 degrees F.

<span>5.      </span>D.

This is a type of electrical connector used to fasten two or more low-voltage (or extra-low-voltage) electrical conductors.

<span>6.      </span>C. the ease with which a material allows electricity to move is called CONDUCTIVITY

<span>7.      </span>D.

Stranded conductors are not acceptable in the pressure terminals of a duplex receptacle. Aluminum conductors of suitable gauge for a 15 ampere duplex outlet will not fit in the pressure terminal holes. 

<span>8.      </span>D.

A 3/0 AWG THHN insulated Copper is rated at 225 amps and it falls under the 90 degree C table.

<span>9.      </span>D.

A #12 copper conductor with an insulation factor of 90 degrees C is rated at 20 amps. A #12 aluminum conductor with an insulation rating of 90 degrees C is rated at 15 amps. These conductors ratings only applies to three conductors in a rated at 15 amps. These conductors’ ratings only applies to three conductors in a raceway. From 7 to 24 conductors in a raceway, both aluminum and copper conductor's ratings have to be reduced by .70, so 15 amps x .7 = 10.5 amps and 20 amps x .7 = 14 amps respectively.

<span>10.  </span>A.

<span>NEC 310.15(B)(1) and (2), table 310.15(B)(2)(a), and table 310.15(B)(17).
Convert 158°F to C result is 70°C. 50 amps x .33 correction factor = 16.5 amps


</span>

<span>11.  </span>A.

<span>12.  </span>B.

Ideally, nm or armored cable should be installed in a wall stud at least 1 1/4 inches from the front edge of the stud.

<span>13.  </span>C.

Always use flux for electrical connections and never use acid flux on electrical connections

<span>14.  </span>D.

In wire gauge, the lower the number, the larger the diameter. So a 6 gauge is larger than 12 gauge, but smaller than 4 gauge.

<span>15.  </span>A.

<span>16.  </span>D.

<span>17.  </span>C.

Table 310-16 NEC

<span>18.  </span>A <span>
MCM means 1000's (M) of (C)ircular (M)ils</span>

<span>19.  </span>D.

Rubber tape is used to round sharp edges

<span>20.  </span>B.

<span>The larger the diameter, the larger the ampacity, or the ability to carry current.</span>

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This is the chemical formula for methyl acetate: CH32CO2. Calculate the mass percent of hydrogen in methyl acetate. Round your a
WITCHER [35]

<u>Answer:</u> The mass percent of hydrogen in methyl acetate is 8 %

<u>Explanation:</u>

The given chemical formula of methyl acetate is CH_3COOCH_3

To calculate the mass percentage of hydrogen in methyl acetate, we use the equation:

\text{Mass percent of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of methyl acetate}}\times 100

Mass of hydrogen = (6 × 1) = 6 g

Mass of methyl acetate = [(3 × 12) + (6 × 1) + (2 × 16)] = 74 g

Putting values in above equation, we get:

\text{Mass percent of hydrogen}=\frac{6g}{74g}\times 100=8.10\%=8\%

Hence, the mass percent of hydrogen in methyl acetate is 8 %

8 0
2 years ago
Which of the compounds above are strong enough acids to react almost completely with a hydroxide ion (pka of h2o = 15.74) or wit
luda_lava [24]

The compounds can react with OH⁻ and HCO₃⁻ only C₅H₆N pyridinium

<h3><em>Further explanation </em></h3>

In an acid-base reaction, it can be determined whether or not a reaction occurs by knowing the value of pKa or Ka from acid and conjugate acid (acid from the reaction)

Acids and bases according to Bronsted-Lowry

Acid = donor (donor) proton (H + ion)

Base = proton (receiver) acceptor (H + ion)

If the acid gives (H +), then the remaining acid is a conjugate base because it accepts protons. Conversely, if a base receives (H +), then the base formed can release protons and is called the conjugate acid from the original base.

From this, it can be seen whether the acid in the product can give its proton to a base (or acid which has a lower Ka value) so that the reaction can go to the right to produce the product.

The step that needs to be done is to know the pKa value of the two acids (one on the left side and one on the right side of the arrow), then just determine the value of the equilibrium constant

Can be formulated:

K acid-base reaction = Ka acid on the left : K acid on the right.

or:

pK = acid pKa on the left - pKa acid on the right

K = equilibrium constant for acid-base reactions

pK = -log K;

K~=~10^{-pK}

K value> 1 indicates the reaction can take place, or the position of equilibrium to the right.

There is some data that we need to complete from the problem above, which is the pKa value of some compounds that will react, namely:

pyridinium pKa = 5.25

acetone pKa = 19.3

butan-2-one pKa = 19

Let's look at the K value of each possible reaction:

pka H₂O = 15.74, pka of H₂CO₃ = 6.37)

  • 1. C₅H₆N pyridinium

* with OH⁻

C₅H₆N + OH- ---> C₅H₅N- + H₂O

pK = pKa pyridinium - pKa H₂O

pK = 5.25 - 15.74

pK = -10.49

K~=~10^{4.9}

K values> 1 indicate the reaction can take place

* with HCO3⁻

C₅H₆N + HCO₃⁻-- ---> C₅H₅N⁻ + H₂CO₃

pK = 5.25 - 6.37

pK = -1.12

K`=~10^{1.12]

Reaction can take place

  • 2. Acetone C₃H₆O

* with OH-

C₃H₆O + OH⁻ ---> C₃H₅O- + H₂O

pK = 19.3 - 15.74

pK = 3.56

K~=~10^{ -3.56}

Reaction does not happen

* with HCO₃-

C₃H₆O + HCO₃⁻ ----> C₃H₅O⁻ + H₂CO₃

pK = 19.3 - 6.37

pK = 12.93

K`=~10 ^{-12.93}

Reaction does not happen

  • 3. butan-2-one C₄H₇O

* with OH-

C₄H₇O + OH- ---> C₄H₆O- + H₂O

pK = 19 - 15.74

pK = 3.26

K~=~10^{-3.26}

Reaction does not happen

* with HCO₃⁻

C₄H₇O + HCO₃⁻ ---> C₄H₆O⁻ + H₂CO₃

pK = 19 - 6.37

pK = 12.63

K~=~ 10^{-12.63}

Reaction does not happen

So that can react with OH⁻ and HCO₃⁻ only C₅H₆N pyridinium

<h3><em>Learn more </em></h3>

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Keywords : acid base reaction, the equilibrium constant

5 0
2 years ago
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Calculate the daily aluminum production of a 150,000 [A] aluminum cell that operates at a faradaic efficiency of 89%. The cell r
Gala2k [10]

Explanation:

It is known that in one day there are 24 hours. Hence, number of seconds in 24 hours are as follows.

                             24 \times 3600 sec

Hence, total charge passed daily is calculated as follows.

                      150,000 \times 24 \times 3600 sec

And, number of Faraday of charge is as follows.

                    \frac{150,000 \times 24 \times 3600 sec}{96500}

                     = 134300.52 F

The oxidation state of aluminium in Al_{2}O_{3} is +3.

                       Al^{3+} + 3e^{-} \rightarrow Al(s)

So, if we have to produce 1 mole of Al(s) we need 3 Faraday of charge.

Therefore, from 134300.52 F the moles of Al obtained with 89% efficiency is calculated as follows.

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or,               = 3.9842 \times 10^{4} mol

Molar mass of Al = 27 g/mol

Therefore, mass in gram will be calculated as follows.

            Mass in grams = 3.9842 \times 10^{4} mol \times 27

                                     = 107.57 \times 10^{4} g

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Thus, we can conclude that the daily aluminum production of given aluminium is 1075.7 kg/day.

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2 years ago
During photosynthesis, sunlight shining on a plant is absorbed. Through several chemical reactions, the plant produces sugar, a
weeeeeb [17]
The change is thermal energy to chemical energy.  Sugar contains a lot of chemical potential energy which is why living things use it as a source of energy.  The process of photo synthesis takes light from the sun to convert carbon dioxide and water into sugar and oxygen.  That process is basically turning the thermal energy from the light into chemical energy in the sugar.

I hope this helps.  Let me know if anything is unclear.
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What will happen to a test dummy during a crash test if its seatbelt is not buckled? The test dummy will stop when the car stops
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<span>The test dummy will continue forward until it makes contact with another object.</span>
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