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omeli [17]
2 years ago
9

THESE QUESTIONS ARE ELECTRICIAN REALATED

Chemistry
2 answers:
aleksandr82 [10.1K]2 years ago
8 0

SoRry im kind of new i dont know how to comment and ask questions

Vladimir [108]2 years ago
4 0

<span>1.      </span>A.

It is a technique typically engaged in electrical power and electronic devices, wherein the devices are run at less than their rated maximum power degeneracy, taking into account the case or body temperature, the ambient temperature and the type of cooling mechanism used.

<span>2.      </span>B.

In order to answer the question, you need to know the area of a circle.<span>
Area = pi * r^2
Area = 3.14 * (100/2) ^ 2
Area = 3.14 * 50^2
Area = 7850 mils^2 = 0.00785 in^2</span>

<span>3.      </span>A.

V / 15 A = 0.213 Ohm <span>
0.213 Ohm / 125 ft * 1000 ft = 1.71 Ohm / 1000 ft 
Closest gauge is #12 AWG (solid wire) 
#12 is 1.588 Ohm / ft, which is a 2.9775 V drop @ 15A</span>

<span>4.      </span>A.

RHW cale insulation can be used up to 167 degrees F.

<span>5.      </span>D.

This is a type of electrical connector used to fasten two or more low-voltage (or extra-low-voltage) electrical conductors.

<span>6.      </span>C. the ease with which a material allows electricity to move is called CONDUCTIVITY

<span>7.      </span>D.

Stranded conductors are not acceptable in the pressure terminals of a duplex receptacle. Aluminum conductors of suitable gauge for a 15 ampere duplex outlet will not fit in the pressure terminal holes. 

<span>8.      </span>D.

A 3/0 AWG THHN insulated Copper is rated at 225 amps and it falls under the 90 degree C table.

<span>9.      </span>D.

A #12 copper conductor with an insulation factor of 90 degrees C is rated at 20 amps. A #12 aluminum conductor with an insulation rating of 90 degrees C is rated at 15 amps. These conductors ratings only applies to three conductors in a rated at 15 amps. These conductors’ ratings only applies to three conductors in a raceway. From 7 to 24 conductors in a raceway, both aluminum and copper conductor's ratings have to be reduced by .70, so 15 amps x .7 = 10.5 amps and 20 amps x .7 = 14 amps respectively.

<span>10.  </span>A.

<span>NEC 310.15(B)(1) and (2), table 310.15(B)(2)(a), and table 310.15(B)(17).
Convert 158°F to C result is 70°C. 50 amps x .33 correction factor = 16.5 amps


</span>

<span>11.  </span>A.

<span>12.  </span>B.

Ideally, nm or armored cable should be installed in a wall stud at least 1 1/4 inches from the front edge of the stud.

<span>13.  </span>C.

Always use flux for electrical connections and never use acid flux on electrical connections

<span>14.  </span>D.

In wire gauge, the lower the number, the larger the diameter. So a 6 gauge is larger than 12 gauge, but smaller than 4 gauge.

<span>15.  </span>A.

<span>16.  </span>D.

<span>17.  </span>C.

Table 310-16 NEC

<span>18.  </span>A <span>
MCM means 1000's (M) of (C)ircular (M)ils</span>

<span>19.  </span>D.

Rubber tape is used to round sharp edges

<span>20.  </span>B.

<span>The larger the diameter, the larger the ampacity, or the ability to carry current.</span>

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Julli [10]

Well, first we must remember that

pK_{a}+pK_{b}=14

This is because

K_{a}*K_{b}=10^{-14}

-log(K_{a}*K_{b})=-log(10^{-14})\\-logK_{a}+-logK_{b}=-log(10^{-14})\\pK_{a}+pK_{b}=14

So then

pK_{b}=14-pK_{a}=14-3.2=1.8

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The reaction is:

4 PCl3 (g) ---> P4(s) + 6 Cl2(g).

Now, you need to convert the mass of PCl3 into number of moles, for which you use the molar mass of PCl3 in this way:

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i think thats answer may i get brainlest?

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Looking at the electron configuration of the atoms; 1s2 2s2 2p4, we can see that these are atoms of elements in group 16. The elements in group 16 has a general outer electronic configuration of ns2np4. They have a valency of 2.

When two atoms of this element approach each other, they will combine in a covalent bond to form a compound. If this element is depicted as X, the compound formed is X2.

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