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babunello [35]
2 years ago
12

Methyl tertiary-butyl ether (MTBE) is an organic compound that has been in use since the late 1970s. Read the article to learn m

ore about MTBE. After reading, identify and describe the author’s purpose for writing the article. Be sure to use four details from the article to support your answer. Click here to read "The Rise and Fall of MTBE.”
Chemistry
1 answer:
tamaranim1 [39]2 years ago
7 0
H h I ointment o on NB j. Non b kkkk NB nis o ok kno kno
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Which species does not have a noble gas electron
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S, sulfur does not have a noble gas electron.
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2 years ago
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What is the oxidation number for iodine in Mg(IO3)2 ?
navik [9.2K]
The oxidation number of iodine is 5 in Mg(IO3)2 which can be calculated as 
   Mg(IO3)2
   MgI2O6
As we know that
Mg has +2
O has -2
So,
   (+2) + 2I + 6 (-2)=0
   2 + 2I - 12 =0
   10+ 2I =0
    10 = 2I
     I =5

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1 year ago
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Solids retain their shape and size, if kept constant temperature and pressure. At a constant temperature and pressure, liquids r
Gnoma [55]
At a constant temperature and pressure, liquids retain their volume
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2 years ago
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A chemical reaction is done in the setup shown , resulting in a change of mass. What will happen if the same reaction is done in
irina1246 [14]
<h2>Answer:</h2>

The mass of the system will remain the same if there is no conversion of mass to energy in the reaction.

<h3>Explanation:</h3>
  • If the system is closed, then according to the law of mass conservation the mass of the reaction system will remain the same.
  • <u><em>Law of conservation of the mass: In simple words, it is described as the mass of a closed system can never be changed, it may transfer from one form to another or change into energy.</em></u>
  • But if the reaction involves energy transfer like heat or light production, in this case, the mass can be changed.
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2 years ago
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Calculate ΔH∘ in kilojoules for the reaction of acetylene (C2H2) (ΔH∘f=227.4kJ/mol) with O2 to yield carbon dioxide (CO2) (ΔH∘f=
Korolek [52]

Answer: The value of \Delta H^o for the reaction is, -2512.4 kJ

Explanation:

The chemical equation for the combustion of acetylene follows:

2C_2H_2(g)+5O_2(g)\rightarrow 4CO_2(g)+2H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(3\times \Delta H^o_f_{(CO_2(g))})+(4\times \Delta H^o_f_{(H_2O(g))})]-[(1\times \Delta H^o_f_{(C_2H_2(g))})+(5\times \Delta H^o_f_{(O_2(g))})]

We are given:

\Delta H^o_f_{(H_2O(g))}=-241.8kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_f_{(C_2H_2(g))}=227.4kJ

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(4\times (-393.5))+(2\times (-241.8))]-[(2\times (227.4)+(5\times (0))]\\\\\Delta H^o_{rxn}=-2512.4kJ

Therefore, the value of \Delta H^o for the reaction is, -2512.4 kJ

5 0
2 years ago
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