Hello!
To solve this problem we are going to use the
Henderson-Hasselbach equation and clear for the molar ratio. Keep in mind that we need the value for Acetic Acid's pKa, which can be found in tables and is
4,76:
![pH=pKa + log ( \frac{[CH_3COONa]}{[CH_3COOH]} )](https://tex.z-dn.net/?f=pH%3DpKa%20%2B%20log%20%28%20%5Cfrac%7B%5BCH_3COONa%5D%7D%7B%5BCH_3COOH%5D%7D%20%29%20)
![\frac{[CH_3COOH]}{[CH_3COONa}= 10^{(pH-pKa)^{-1}}=10^{(4-4,76)^{-1}}=5,75](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BCH_3COOH%5D%7D%7B%5BCH_3COONa%7D%3D%2010%5E%7B%28pH-pKa%29%5E%7B-1%7D%7D%3D10%5E%7B%284-4%2C76%29%5E%7B-1%7D%7D%3D5%2C75%20)
So, the mole ratio of CH₃COOH to CH₃COONa is
5,75Have a nice day!
When an element losses its electron its called a cation. When an element accepted that electron it called anion. This is called an ionic bond.
Answer:
a. the solution will be weakly basic.
b. Greater than 7 because CN⁻ is a stronger base than NH₄⁺ is an acid.
Explanation:
a. The fluoride ion (F⁻) reacts with water thus:
F⁻ + H₂O → HF + OH⁻
That means that fluoride ions produce OH⁻ ions in solution doing <em>the solution will be weakly basic.</em>
b. The acidic equilibrium of NH₄⁺ is:
NH₄⁺ ⇄ NH₃ + H⁺ with a ka of 5,6x10⁻¹⁰.
The basic equilibrium of CN⁻ is:
CN⁻ + H₂O → HCN + OH⁻ with a kb of 2x10⁻⁵
That means that the production of OH⁻ from CN⁻ is higher than production of H⁺ from NH₄⁺. The CN⁻ is a stronger base than NH₄⁺ is an acid.
Thus, the pH of a salt solution of NH₄CN would be <em>Greater than 7 because CN⁻ is a stronger base than NH₄⁺ is an acid.</em>
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I hope ot helps!
The graph is needed to answer this question.
Solubility may increase or decrease with temperature depending on the properties of the solute and the solvent.
It is quite common that the solubility of the ionic compounds, like KBr, in water increases with temperature.
Use your solubility curve for the KBr and you wiil see a line that starts at a solubility a little greater than 50 grams of the salt in 100 grams of water for temperaute 0°C and increase linearly until almost 100 grams of the salt in 100 grams of water at 100°C.
So, in this case you can affirm that the solubility of KBr increases with the temperature.
Answer: the second option: the solubility increases.
Answer:
The average kinetic energy of the gas particles is greater in container B because it has a higher temperature.
Explanation:
<em>The correct option would be that the average kinetic energy of the gas particles is greater in container B because it has a higher temperature.</em>
<u>According to the kinetic theory of matter, the temperate of a substance is a measure of the average kinetic energy of the molecules of substance. In other words, the higher the temperature of a substance, the higher the average kinetic energy of the molecules of the substance.</u>
In the illustration, the gas in container B showed a higher temperature than that of container A as indicated on the thermometer, it thus means that the average kinetic energy of the molecules of gas B is higher than those of gas A.
