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hoa [83]
2 years ago
7

I am giving brainiest! All I need are the last two questions at the bottom the rest of this info is to help solve them. I hope I

am not asking for too much, thank you.
Molecular Structure Lab Report: Determining Polarity

Instructions: For this investigative phenomenon, you will investigate why certain substances, such as oil and vinegar, don't mix. To do so, you will combine various compounds, compare their solubility, and determine their polarity. Fill in each section of this lab report and submit it to your instructor for grading.

Title: Determining polarity


Objective(s): To test the solubility of different mixtures through polarity


Hypothesis:

Create a hypothesis that predicts the polarity of iodine solution, vinegar, vegetable oil, salt, water, and rubbing alcohol.

If the Iodine solution(or any other solution used in this experiment) is mixed with water, then we can determine through its solubility whether it is polar, nonpolar or ionic, because water widely known as polar and polar compounds cannot mix with nonpolar.


Procedures:

This lab already includes materials and a summary of steps to follow. List and explain your controlled variables, independent variable, and dependent variable for this lab.

Materials


deionized (distilled) water

rubbing alcohol

vegetable oil

iodine solution

sodium chloride (salt)

acetic acid (vinegar)

test tubes or clear plastic cups

tablespoon and teaspoon

stirring sticks

permanent marker for labeling



Safety

Always wear eye protection and use gloves when handling chemicals in a laboratory area.

Students should wash their hands thoroughly before leaving the laboratory area.

Dispose of any chemicals by washing used test tubes with soap and water or washing used cups then throwing them away in a trash bin.

Variables:

Remember, controlled variables are factors that remain the same throughout the experiment. An independent (test) variable changes so that the experimenter can see the effect on other variables. The dependent (outcome) variable will change in response to the test variable.

Controlled variables:water

Independent Variable:iodine solution

Dependent Variable:solubility(is it soluble or not)


Table 2:

(Hint: Like substances dissolve like substances, and polar solvents dissolve ionic compounds.)

Solute

Solvent

Soluble or insoluble?

Is the solute polar, nonpolar, or ionic?

Is the solvent polar, nonpolar, or ionic?

Vinegar

Water

soluble

polar

polar


Iodine solution

Water

insoluble

nonpolar

polar


Rubbing alcohol

Vegetable oil

insoluble

polar

nonpolar


Salt

Vegetable oil

insoluble

ionic

nonpolar


Water

Rubbing alcohol

soluble

polar

polar


Vinegar

Rubbing alcohol

soluble

polar

polar


Iodine solution

Vinegar

insoluble

nonpolar

polar


Vegetable oil

Vinegar

insoluble

nonpolar

polar


Were any of your substances difficult to identify as polar, nonpolar, or ionic? Explain.



How do models help scientists predict the polarity of molecules?
Chemistry
1 answer:
andriy [413]2 years ago
5 0

Answer:

the polarity of a molecule tells wherrher the electron cloud is equally distributed across the atom whithin the molecule, or whether an electronegative atom is effect the electron density. The distribution of the electrons will affect the behavior and reactivity of the molecule.

Explanation:

water and oil do not mix well, despite the fact that they are both homogenous solutions on their own

You might be interested in
How many liters of a 0.352 M solution of Ca(SO4) would contain 62.1 g of Ca(SO4)?​
konstantin123 [22]

Answer:

1.3 L.

Explanation:

  • Molarity is the no. of moles of solute per 1.0 L of the solution.

<em>M = (no. of moles of CaSO₄)/(Volume of the solution (L))</em>

<em></em>

M = 0.352 M.

no. of moles of CaSO₄ = mass/molar mass = (62.1 g / 136.14 g/mol) = 0.456 mol,

Volume of the solution = ??? L.

∴ (0.352 M) = (0.456 mol)/(Volume of the solution (L))

<em>∴ (Volume of the solution (L) </em>= (0.456 mol)/(0.352 M) = <em>1.296 L ≅ 1.3 L.</em>

4 0
2 years ago
Identify the oxidizing and reducing agents in the following: 2H+(aq) + H2O2(aq) + 2Fe2+(aq) → 2Fe3+(aq) + 2H2O(l)
schepotkina [342]

Answer :  The oxidizing and reducing agents are, H_2O_2 and Fe^{2+}.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given redox reaction is:

2H^+(aq)+H_2O_2(aq)+2Fe^{2+}(aq)\rightarrow 2Fe^{3+}(aq)+2H_2O(l)

The half oxidation-reduction reactions are:

Oxidation reaction : Fe^{2+}\rightarrow Fe^{3+}+1e^-

Reduction reaction : O^-+1e^-\rightarrow O^{2-}

The oxidation state of oxygen in H_2O_2 and H_2O is, (-1) and (-2) respectively.

In this reaction, 'Fe' is oxidized from oxidation (+2) to (+3) and 'O' is reduced from oxidation state (-1) to (-2). Hence, 'Fe^{2+}' act as a reducing agent and 'H_2O_2' act as a oxidizing agent.

Thus, the oxidizing and reducing agents are, H_2O_2 and Fe^{2+}.

7 0
2 years ago
A kettle of water is at 14.5°C. Its temperature is then raised to 50.0°C by supplying it with 5,680 joules of heat. The specific
Tamiku [17]

Answer:- 38.2 g.

Solution:- The equation used for solving this type of calorimetry problems is:

q=mc\Delta T

where, q is the heat energy, m is mass, c is specific heat and delta T is the change in temperature.

Water temperature is increasing from 14.5 degree C to 50.0 degree C.

\Delta T=50.0-14.5  = 35.5 degree C

q is given as 5680 J and specific heat value is 4.186\frac{J}{g.^0C} .

The equation could be rearranged for m as:

m=\frac{q}{c*\Delta T}

Let's plug in the values in it:

m=\frac{5680}{4.186*35.5}

m = 38.2 g

So, the mass of water in the kettle is 38.2 g.


4 0
2 years ago
Read 2 more answers
A compound that is composed of carbon, hydrogen, and oxygen contains 70.6% C, 5.9% H, and 23.5% O by mass. The molecular weight
zhannawk [14.2K]

Answer: The molecular formula will be C_8H_8O_2

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C= 70.6 g

Mass of H = 5.9 g

Mass of O = 23.5 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{70.6g}{12g/mole}=5.9moles

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.9g}{1g/mole}=5.9moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{23.5g}{16g/mole}=1.5moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{5.9}{1.5}=4

For H = \frac{5.9}{1.5}=4

For O =\frac{1.5}{1.5}=1

The ratio of C : H: O= 4: 4:1

Hence the empirical formula is C_4H_4O

The empirical weight of C_4H_4O = 4(12)+4(1)+1(16)= 68g.

The molecular weight = 136 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{136}{68}=2

The molecular formula will be=2\times C_4H_4O=C_8H_8O_2

4 0
2 years ago
En una determinación cuantitativa se utilizan 17.1 mL de Na2S2O3 0.1N para que reaccione todo el yodo que se encuentra en una mu
lozanna [386]

Answer:

La cantidad de yodo en la muestra es 0.217 g

Explanation:

Los parámetros dados son;

Normalidad de la solución de Na₂S₂O₃ = 0.1 N

Volumen de la solución de Na₂S₂O₃ = 17.1 mL

Masa de muestra = 0.376 g

La ecuación de reacción química se da de la siguiente manera;

I₂ + 2Na₂S₂O₃ → 2 · NaI + Na₂S₄O₆

Por lo tanto, el número de moles de sodio por 1 mol de Na₂S₂O₃ en la reacción = 1 mol

Por lo tanto, la normalidad por mol = 1 M × 1 átomo de Na = 1 N

Por lo tanto, 0.1 N = 0.1 M

El número de moles de Na₂S₂O₃ en 17,1 ml de solución 0,1 M de Na₂S₂O₃ se da de la siguiente manera;

Número de moles de Na₂S₂O₃ = 17.1 / 1000 × 0.1 = 0.00171 moles

Lo que da;

Un mol de yodo, I₂, reacciona con dos moles de Na₂S₂O₃

Por lo tanto;

0,000855 moles de yodo, I₂, reaccionan con 0,00171 moles de Na₂S₂O₃

La masa molar de yodo = 253.8089 g / mol

La masa de yodo en la muestra = 253.8089 × 0.000855 = 0.217 g.

5 0
2 years ago
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