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Anastaziya [24]
2 years ago
10

How many molecules are in 70.7 grams of C4H10?

Chemistry
2 answers:
My name is Ann [436]2 years ago
8 0

Answer: 7.34 x 10∧23 molecules are in 70.7grams of C4H10

Explanation:

First,we convert to moles using the molar mass of Butane( C4H10).

The molar mass of Butane ( C4H10) = 58.12g/mol

It means;

58.12g  of C4H10 --------> 1 mole of C4H10

Therefore; 70.7g of C4H10 --------->  1/ 58.12 x 70.7 = 1.22moles

Using the Avogadro's number;

1 mole of C4H10 contains 6.02 x 10∧23 molecules.

1.22 moles would contain; 1.22 x 6.02 x 10∧23 = 7.34 x 6.02 x 10∧23 molecules

OlgaM077 [116]2 years ago
6 0

Answer:

1.216mol

Explanation:

The molar mass of C₄H₁₀ is (12 x4)+ (1x 10) = 48 + 10 = 58g

1 grams C4H10 is equal to 0.017205129881525 mole.

70.7 grams = 70.7 x 0.017205129881525  = 1.216mol

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Write equations that show the processes that describe the first, second, and third ionization energies for a gaseous gadolinium
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Answer:

Gd → Gd⁺ + 1e⁻, Gd⁺ → Gd⁺² + 1e⁻, Gd⁺² → Gd⁺³ + 1e⁻

Explanation:

The ionization energy is the energy necessary to remove one electron of the atom, transforming it in a cation. The first ionization energy is the energy necessary to remove the first electron, the second energy, to remove the second electron, and then successively.

Thus, for gadolinium (Gd)

Fisrt ionization:

Gd → Gd⁺ + 1e⁻

Second ionization:

Gd⁺ → Gd⁺² + 1e⁻

Third ionization:

Gd⁺² → Gd⁺³ + 1e⁻

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Carl's chemistry teacher asked him to make a 1 M sodium chloride solution. Carl measured 58.44 grams NaCl, added it to a volumet
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What is the empirical formula of a compound containing 5.03 grams carbon, 0.42 grams hydrogen, and 44.5 grams chlorine?
Thepotemich [5.8K]

Answer:

CHCl₃

Explanation:

Given parameters:

Carbon = 5.03g

Hydrogen = 0.42g

Chlorine = 44.5g

The empirical formula shows the simplest formula of a compound.

To deduce the empirical, we need two pieces of information:

> Mass of the elements or the percentage composition of the compound

>The relative atomic masses of the elements

In order to derive the empirical formula from these parameters,

>>> find the number of moles of elements by dividing the mass given by the relative atomic mass of the respective atom

>>> Divide through by the smallest mole

>>> Approximate or multiply by a factor that would make it possible for whole numbers to be obtained

From the question, we have been given the mass of each element.

Now using the period table, we can obtain the relative atomic masses of each atom:

Carbon = 12gmol⁻¹

Hydrogen = 1gmol⁻¹

Chlorine = 37.5gmol⁻¹

C H Cl

Mass(in g) 5.03 0.42 44.5

Moles 5.03/12 0.42/1 44.5/37.5

0.42 0.42 1.19

Dividing

by

smallest 0.42/0.42 0.42/0.42 1.19/0.42

Mole ratio 1 1 2.83

Approximate 1 1 3

The empirical formula is CHCl₃

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