answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Neporo4naja [7]
2 years ago
10

n the table below, write the density of each object. Then predict whether the object will float or sink in each of the fluids. W

rite “Float” or “Sink” in each empty box of the table. Object Object density Liquid density 0.5 g/mL 1.0 g/mL 2.0 g/mL 1 1.4 sink sink float 2 3 0.8 sink float float 4 5
Chemistry
1 answer:
Scrat [10]2 years ago
3 0

Answer:

0.5 g/mL----- float

1.0 g/mL---- float

2.0 g/mL-----sink

Explanation:

Those objects will float whose density is less or equal to water density due to lower mass while those object will sink whose density is greater than water because the mass of the object is greater than water. So the density of the object i. e. 0.5 g/mL and 1.0 g/mL will float in the liquid because its density is lower than water which is 1 g/mL while the density of an object i. e. 2.0 g/mL is denser than water so it will sink.

You might be interested in
(f) what is the observed rotation of 100 ml of a solution that contains 0.01 mole of d and 0.005 mole of l? (assume a 1-dm path
never [62]
<span>Answer: .01 moles of D to .005 moles of L ~ so, .01+.005 = .015 total; using this total value, divide the portions of D and L. so .01/.015 to .005/.015 ~ 67% D to 33% L. And thus, the enantiomer excess will be 34%.</span>
4 0
2 years ago
Read 2 more answers
The volume of distilled water that should be added to 10.0 mL of 6.00 M HCl(aq) in order to prepare a 0.500 M HCl(aq) solution i
bija089 [108]

Answer:

110ml

Explanation:

<em>Using the dilution equation, C1V1 = C2V2</em>

<em>Where C1 is the initial concentration of solution</em>

<em>C2 is final concentration of solution</em>

<em>V1 is intital volume of solution</em>

<em>V2 is final volume of solution.</em>

From the question , C1=6M, C2=0.5M, V1=10ml, V2=?

V2 =\frac{C1V1}{C2}

V2 =\frac{10*6}{0.5}

V2 =120ml

volume of water added = final volume -initial volume

                                    = 120-10

                                   =110ml

3 0
2 years ago
If a large marshmallow has a volume of 2.75 in3 and density of 0.242 g/cm3, how much would it weigh in grams? 1 in3=16.39 cm3.
Anestetic [448]
<span>
•   </span>Volume of the marshmallow:

V = 2.75 in^3          (but, 1 in^3 = 16.39 cm^3)

V = 2.75 × 16.39 cm^3

V = 2.75 × 16.39 cm^3

V = 45.0725 cm^3


•   Density:

d = 0.242 g/cm^3


<span>•  </span>Mass:

m = d × V

m = (0.242 g/cm^3) × (45.0725 cm^3)

m = (0.242 g/cm^3) × (45.0725 cm^3)

m = 10.907545 g

m ≈ 10.9 g   <——<span>—  this is the answer.


I hope this helps. =)
</span>
4 0
2 years ago
acetaminophen is a stronger acid than methanol, and sodium methoxide is a stronger base than. write an acid base equilibrium rea
torisob [31]

Answer:

The equilibrium shifts to the right that is the forward reaction.

Explanation:

The chemical compound known as "Acetaminophen" is a chemical compound that is generally known to a layman as Paracetamol and it belongs to the drug class known as anagelsics which helps in the treatment of pain or say in the reduction of pain. Acetaminophen has the chemical Formula to be C8H9NO2, with the Molar mass of 151.163 g/mol and Boiling point of 420 °C.

The reaction between Acetaminophen and sodium methoxide gives methanol and acetaminophen sodium salt. Therefore, the acid base equilibrium reaction of these species is given as;

C8H9NO2 + CH3ONa <========> CH3OH + acetaminophen sodium salt.

The equilibrium shifts to the right that is the forward reaction.

8 0
2 years ago
What is the value of ΔGo in kJ at 25 oC for the reaction between the pair: Mn(s) and Ag+(aq) to give Ag(s) and Mn2+(aq) Use the
Leni [432]

Answer:  -3.8\times 10^{5}J

Explanation:

Mn+2Ag^{+}\rightarrow Mn^{2+}+2Ag

Here Mn undergoes oxidation by loss of electrons, thus act as anode. silver undergoes reduction by gain of electrons and thus act as cathode.

E^0=E^0_{cathode}- E^0_{anode}

Where both E^0 are standard reduction potentials.

E^0_{[Mn^{2+}/Mn]}= -1.18V

E^0_{[Ag^{2+}/Ag]}=+0.80V

E^0=E^0_{[Ag^{+}/Ag]}- E^0_{[Mn^{2+}/Mn]}

E^0=+0.80- (-1.18V)=1.98V

The standard emf of a cell is related to Gibbs free energy by following relation:

\Delta G^0=-nFE^0

\Delta G^0 = gibbs free energy

n= no of electrons gained or lost  = 2

F= faraday's constant

E^0 = standard emf  = 1.98V

\Delta G^0=-2\times 96500\times (1.98)=-3.8\times 10^{5}J

Thus the value of \Delta G^0 is -3.8\times 10^{5}J

8 0
2 years ago
Other questions:
  • Which statement best compares the energy involved in melting with the energy involved in boiling for a given liquid?
    6·2 answers
  • Ricardo finds an online site about the gas laws. The site shows the equation below for Charles’s law.
    10·2 answers
  • A ground state hydrogen atom absorbs a photon of light having a wavelength of 93.73 nm. It then gives off a photon having a wave
    10·1 answer
  • What is irreversible head loss?
    15·1 answer
  • Freon-12, CF2Cl2, which has been widely used in air conditioning systems, is considered a threat to the ozone layer in the strat
    8·2 answers
  • A piece of iron metal is heated to 155 degrees C and placed into a calorimeter that contains 50.0 mL of water at 18.7 degrees C.
    14·1 answer
  • The pOH of a solution is 6.0. Which statement is correct? Use p O H equals negative logarithm StartBracket upper O upper H super
    7·1 answer
  • Commercially available hot packs are simple in design: a pouch with water on one side, isolated by a barrier from a specific sal
    7·1 answer
  • If the heat released during condensation goes only to warming the iron block, what is the final temperature (in ∘C) of the iron
    5·1 answer
  • Maria wants to enter the science fair at her school. She has a list of ideas for her project. Which questions could be answered
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!