Answer:
1.06 mL of toluene will be needed.
Explanation:
Equi-molar mixture means equal moles of all the components.
as given the volume of ethyl acetate = 1mL
Density of ethyl acetate = 0.898 g/mL
The relation between density, mass and volume is :
mass=volumeXdensity
mass of ethyl acetate present = 1mL X 0.898g/mL = 0.598 grams
the moles are related to mass as:
For ethyl acetate molar mass = 4X12+8X1+2X16= 88g/mol
moles of ethyl acetate will be:
So we need 0.01 moles of toluene also
For 0.01 moles the mass of toluene required = 0.01 X molar mass of toluene
mass required = 0.01 X 92=0.92grams
for 0.92 grams of toluene volume required will be:
Answer:
GP.E = 5880 j
Explanation:
Given data:
Mass = 75 kg
height = 8 m
Potential energy = ?
Solution:
The formula for gravitational potential energy is
GPE = mgh
m = mass in kilogram
g = acceleration due to gravity
h = height in meter above the ground
Formula:
GP.E = mgh
Now we will put the values in formula.
g = 9.8 m/s²
GP.E = 75 Kg × 9.8 m/s²× 8 m
GP.E = 5880 Kg.m²/s²
Kg.m²/s² = j
GP.E = 5880 j
Answer:
Mass= 2.77g
Explanation:
Applying
P=2.09atm, V= 1.13L, R= 0.082, T= 291K, Mm of N2= 28
PV=nRT
NB
Moles(n) = m/M
PV=m/M×RT
m= PVM/RT
Substitute and Simplify
m= (2.09×1.13×28)/(0.082×291)
m= 2.77g
<u>Answer:</u> The number of carbon, hydrogen and oxygen atoms on the left side of the reaction are 12, 28 and 38 respectively
<u>Explanation:</u>
In a chemical equation, the chemical species are termed as reactants or products.
Reactants are defined as the species which react in the reaction and are written on the left side of the reaction arrow.
Products are defined as the species which are produced in the reaction and are written on the right side of the reaction arrow.
For the given chemical equation:
On the reactant side:
Number of carbon atoms = (6 × 2) = 12
Number of hydrogen atoms = (14 × 2) = 28
Number of oxygen atoms = (2 × 19) = 38
Hence, the number of carbon, hydrogen and oxygen atoms on the left side of the reaction are 12, 28 and 38 respectively
<span>Empirical formula for C2H4(OH)2 is</span><span>
C1H3O1
</span>
