<h3><u>Answer</u>;</h3>
= 4.68 K
<h3><u>Explanation</u>;</h3>
According to the combined gas law;
P1V1/T1 = P2V2/T2
Given; P1 = 125 Psi
V1 = 75 L
T1 = 288 K
P2 = 25 PSI
V2 =6.1 L
Therefore;
T2 = P2V2T1/P1V1
= (25×6.1 ×288)/(125×75)
= 4.6848
= 4.68 K
Answer:
Explanation:
Given:
Initial volume of the balloon V1 = 348 mL
Initial temperature of the balloon T1 = 255C
Final volume of the balloon V2 = 322 mL
Final temperature of the balloon T2 =
To calculate T1 in kelvin
T1= 25+273=298K
Based on Charles law, which states that the volume of a given mass of a ideal gas is directly proportional to the temperature provided that the pressure is constant. It can be applied using the below formula
T2=( V2*T1)/V1
T2=(322*298)/348
Hence, the temperature of the freezer is 276 K
The answer is 2.135 mol/Kg
Given that molarity is 2M, that is, 2 moles in 1 liter of solution.
Density of solution is 1.127 g/ml
Volume of solution is 1L or 1000 ml
mass of solution (m) = density × volume
m₁ = density × volume = 1.127 × 1000 = 1127 g
mass of solute, m₂ = number of moles × molar mass
m₂ = 2 × 95.211
m₂ = 190.422 g
mass of solvent = m₁ - m₂
= 1127 - 190.422
= 936.578 g
= 0.9366 Kg
molality = number of moles of solute / mass of solvent (in kg)
= 2 / 0.9366
= 2.135 mol/Kg
Answer:
we will except an increase in the polarity of the system and this will cause the Non-polar spot to be near the solvent front, while the polar spot will run at an approximate speed of 0.5 Rf
Explanation:
when we run a TLC plate in a 50/50 mixture of hexanes and ethyl acetate we will except an increase in the polarity of the system and this will cause the Non-polar spot to be near the solvent front, while the polar spot will run at an approximate speed of 0.5 Rf
The speed of the polar spot depends largely on the level of polarity, an increase in the polarity will see both spots of Neat hexane run when we run a TLC plate in a 50/50 mixture of hexanes and ethyl acetate
Answer:
0.01125 moles of 
can be produced from 115 mL of 0.218 M 
.
Explanation:
Moles of 
= n
Volume of the solution = 115 mL = 0.115 L ( 1 mL=0.001 L)
Molarity of the solution = 0.218 M
According to reaction, 3 moles gives 1 mole of 
.Then 0.03379 moles of will give :
0.01125 moles of can be produced from 115 mL of 0.218 M .
