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White raven [17]
2 years ago
13

Complete this sentence: Atoms emit visible and ultraviolet light A. as electrons jump from lower energy levels to higher levels.

B. as the atoms condense from a gas to a liquid. C. as electrons jump from higher energy levels to lower levels. D. as they are heated and the solid melts to form a liquid. E. as the electrons move about the atom within an orbit.
Chemistry
1 answer:
Aleks04 [339]2 years ago
4 0

Answer:

C. as electrons jump from higher energy levels to lower levels

Explanation:

Atoms of elements are capable of emitting photons i.e. light energy. They, however, only do so when they become excited at first. They remain excited for a short while and then begin to move from their excited electron level to a lower level.

As they move from high electron level to low electron level, atoms emit light energy in form of visible, ultraviolet light in a process called SPONTANEOUS EMISSION. Therefore, according to this question, atoms emit visible and ultraviolet light as electrons jump from higher energy levels to lower levels.

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A compound that is composed of carbon, hydrogen, and oxygen contains 70.6% C, 5.9% H, and 23.5% O by mass. The molecular weight
zhannawk [14.2K]

Answer: The molecular formula will be C_8H_8O_2

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C= 70.6 g

Mass of H = 5.9 g

Mass of O = 23.5 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{70.6g}{12g/mole}=5.9moles

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.9g}{1g/mole}=5.9moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{23.5g}{16g/mole}=1.5moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{5.9}{1.5}=4

For H = \frac{5.9}{1.5}=4

For O =\frac{1.5}{1.5}=1

The ratio of C : H: O= 4: 4:1

Hence the empirical formula is C_4H_4O

The empirical weight of C_4H_4O = 4(12)+4(1)+1(16)= 68g.

The molecular weight = 136 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{136}{68}=2

The molecular formula will be=2\times C_4H_4O=C_8H_8O_2

4 0
2 years ago
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