AgI has a higher melting point than vanillin because it is an ionic compound. The bonds are held more tightly together than in vanillin because it is a covalent compound. Ionic bonds have a higher melting point because the electrons are being transferred from one atom to the other.
Answer:
kindly check the EXPLANATION SECTION
Explanation:
In order to be able to answer this question one has to consider the neutron proton ratio. Considering this ratio will allow us to determine the stability of a nuclei. The most important rule that helps us in determination of stability is that when the Neutron- Proton ratio of any nuclei ranges from to 1 to 1.5, then we say the nuclei is STABLE.
Also, we need to understand that when the Neutron- Proton ratio is LESS THAN 1 or GREATER THYAN 1.5, then we say the nuclei is UNSTABLE.
So, let us check which is stable and which is unstable:
a. 4 protons and 5 neutrons = Neutron- proton ratio = N/P = 5/4= stable.
b. 7 protons and 7 neutrons = Neutron- proton ratio = N/P = 7/7= 1 = stable.
c. 2 protons and 3 neutrons = Neutron- proton ratio = N/P = 3/5 =0.6 =unstable.
d. 3 protons and 0 neutrons = Neutron- proton ratio = N/P = 0/3= 0= unstable.
e. 6 protons and 5 neutrons = Neutron- proton ratio = N/P = 5/6= 0.83 = unstable.
f. 9 protons and 9 neutrons = Neutron- proton ratio = N/P = 9/9 = 1 = stable.
g. 8 protons and 7 neutrons = Neutron- proton ratio = N/P = 7/8 =0.875 = unstable.
h. 1 proton and 0 neutrons = Neutron- proton ratio = N/P = 0/1 =0 = unstable
Explanation:
From the source, The student recrystallized biphenyl by using benzene. Biphenyl is non polar and so is benzene. Biphenyl is very soluble in benzene at low as well as high temperature. Thus, it do not recrystallize as like dissolves like and gives a very poor yield.
The good recovery of the product is dependent on compound having high solubility at the high temperatures and having low solubility at the low temperatures.
The answer is 2.135 mol/Kg
Given that molarity is 2M, that is, 2 moles in 1 liter of solution.
Density of solution is 1.127 g/ml
Volume of solution is 1L or 1000 ml
mass of solution (m) = density × volume
m₁ = density × volume = 1.127 × 1000 = 1127 g
mass of solute, m₂ = number of moles × molar mass
m₂ = 2 × 95.211
m₂ = 190.422 g
mass of solvent = m₁ - m₂
= 1127 - 190.422
= 936.578 g
= 0.9366 Kg
molality = number of moles of solute / mass of solvent (in kg)
= 2 / 0.9366
= 2.135 mol/Kg
<span>Answer</span>=.000978802802moles H2SO4
How I Got My Answer
<span>Molar mass
</span>H2SO4= 98.079g/mol
What I have
.0960g H2SO4
Equation
.0960g*1mol/98.079g= .000978802802mol H2SO4