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elena55 [62]
2 years ago
15

Which group or groups of atoms are the only atoms with f orbitals A. All atoms heavier than barium B. All atoms heavier than kry

pton C. All noble gases D. Lanthanides and actinides
Chemistry
1 answer:
Mashcka [7]2 years ago
6 0

Answer:

All atoms heavier than barium

Explanation:

In the periodic table, elements are divided into blocks. We have the;

s- block elements

p- block elements

d- block elements

f- block elements

However, immediately after Barium, we now encounter elements that have f-orbitals. Barium possesses a fully filled d-orbital. Hence after it, we see elements with 4f and 5f orbitals called the Lanthanides and actinides. The elements following the lanthanide and actinide series possess completely filled f-orbitals as inner orbitals.

Hence elements heavier than barium all possess f-orbitals.

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What is the total pressure of air in lungs of an individual with oxygen at 100. mmHg, nitrogen at 573 mmHg, carbon dioxide at 0.
ryzh [129]

Answer: The total pressure of air in lungs of an individual is 760.28 mm Hg

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_A+p_B+p_C...

Given : p_{total} =total pressure of gases = ?

p_{O_2} = partial pressure of oxygen = 100 mm Hg

p_{N_2} = partial pressure of nitrogen = 573 mm Hg

p_{CO_2} = partial pressure of Carbon dioxide = 0.053 atm = 40.28 mm Hg(1 atm = 760 mmHg)

p_{H_2O} = partial pressure of water vapor = 47 torr = 47 mm Hg  (1torr=1 mm Hg)

putting in the values we get:

p_{total}=(100+573+40.28+47)mmHg

p_{total}=760.28mmHg

Thus the total pressure of air in lungs of an individual is 760.28 mm Hg

5 0
2 years ago
when a volume of a gas is changed from __ L to 4.50 L, the temperature will change from 38.1 C to 15.0C
kow [346]
Assuming that the change of volumen was done at constant pressure and the quantity of gas did not change, you use Charles' Law of gases, which is valid for ideal gases:

V / T = constant => V1 / T1 = V2 / T2 => V1 = [V2 / T2] * T1.

Now plug in the numbers ,where T1 and T2 have to be in absolute scale.

T1 = 38.1 + 273.15 K = 311.25K

T2 = 15.0 + 273.15 K = 288.15K

V1 = 4.5L * 311.25K / 288.15 K = 4.86L.

Answer: 4.86
3 0
2 years ago
When filling a burette for a titration, adjust the burette so that______, preferably over a sink. Then,_______to add the titrant
artcher [175]

Answer:

Explanation:

When filling a burette for a titrant, adjust the burette so that the opening is near or below the eye leve preferably over the sink.

Then, use a funnel to add the titrant into the burette.

The titrant should be filled almost to the zero mark.

6 0
2 years ago
Mass in grams of 6.25 mol of copper (II) nitrate?
podryga [215]
Cu = 63.546
N= 14.001 g/mol
O= 15.999 g/mol * 3 = 47.997

Copper (II) Nitrate has a MW of 125.544 g/mol

6.25 x 125.544

= 784.65 <--- is your answer, if there were was a multiple choice or not :)
8 0
2 years ago
Read 2 more answers
The combustion of propane occurs when propane interacts with oxygen gas to produce water and carbon dioxide in the following rea
gtnhenbr [62]

Answer:

  • 20 atm

Explanation:

<u>1) Data:</u>

a) n = 2 moles

b) T = 373 K

c) V = 2.5 liter

d) P = ?

<u>2) Chemical principles and formula</u>

You need to calculate the pressure of the propane gas in the mixture before reacting. So, you can apply the partial pressure principle which states that each gas exerts a pressure as if it occupies the entire volume.

Thus, you just have to use the ideal gas equation: PV = nRT

<u>3) Solution:</u>

  • PV = nRT ⇒ P = nRT / V

P = 2 mol × 0.08206 atm-liter /K-mol × 373K / 2.5 liter = 24.5 atm

Since the number of moles are reported with one significant figure, you must round your answer to one significant figure, and that is 20 atm (20 is closer to 24.5 than to 30).

5 0
2 years ago
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