What is the mass of 3.91 × 1024 molecules of seo2? the molar mass of seo2 is 110.96 g/mol?

Chemistry

2 answers:

frozen [14]2 years ago

8 0

Answer:

Mass of $3.91\times 10^{24}$ number of $SeO_{2}$ molecules is 720.3g

Explanation:

Mass of 1 mol of $SeO_{2}$ is 110.96 g

We know, 1 mol of molecule = $6.023\times 10^{23}$ number of molecules

So, mass of $6.023\times 10^{23}$ number of $SeO_{2}$ molecules is 110.96 g

Hence mass of $3.91\times 10^{24}$ number of $SeO_{2}$ molecules = $\frac{110.96\times 3.91\times 10^{24}}{6.023\times 10^{23}}g=720.3g$

3241004551 [841]2 years ago

4 0

The answer is 720.68, but to 3 sig. figs it would be 721. You get this by:

3.91x10^24 (1mol/ 6.02x10^3 molecules) (110.96/ 1mol)= 720.68

Hope that helps!

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If 200.0 g of copper(II) sulfate react with an excess of zinc metal, what is the theoretical yield of copper? 1.253 g 50.72 g 79

Helen [10]

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2) we need to convert the grams of CuSO₄ to moles using the molar mass.

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$200.0 g CuSO_4 ( \frac{1 mol}{160 grams} )= 1.25 mol CuSO_4$

3) convert moles of CuSO₄ to moles of Cu

$1.25 mol CuSO_4 ( \frac{1 mol Cu}{1 mol CuSO_4} )= 1.25 mol Cu$

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I did it step-by-step as the explanation but you can do all of this in one step.

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4 0

2 years ago

Identify the conjugate acid base pair <br> H3PO4(ag)+CO32=HCO3-(ag)+HPO42-(ag)

viktelen [127]

Answer:

H₃PO₄/H₂PO₄⁻ and HCO₃⁻/CO₃²⁻

Explanation:

An acid is a proton donor; a base is a proton acceptor.

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CO₃²⁻ is the base, because it accepts a proton from the phosphoric acid.

The conjugate base is what's left after the acid has given up its proton.

The conjugate acid is what's formed when the base has accepted a proton.