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Dennis_Churaev [7]
2 years ago
8

Calculate the mass percent of carbon (c) in carbon tetrachloride, (ccl4), if the molar mass of carbon tetrachloride is 153.8g.

Chemistry
2 answers:
baherus [9]2 years ago
3 0
<span>mass percent of carbon (c) in CCl</span>₄ = mass of C/mass of CCl₄
                                                        = 12 x 100/153.8 = 7.8%


NeTakaya2 years ago
3 0

<u>Answer:</u> The mass percent of carbon in carbon tetrachloride is 7.8 %.

<u>Explanation:</u>

In CCl_4, there are 1 carbon atoms and 4 chlorine atoms.

To calculate the mass percent of element in a given compound, we use the formula:

\text{Mass percent of carbon}=\frac{\text{Mass of carbon}}{\text{Molar mass of carbon tetrachloride}}\times 100

Mass of carbon = 12 g

Mass of carbon tetrachloride = 153.8 g

Putting values in above equation, we get:

\text{Mass percent of carbon}=\frac{12}{153.8}\times 100=7.80\%

Hence, the mass percent of carbon in carbon tetrachloride is 7.8 %.

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Answer:

1. Cu

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3. 2 electrons.

Explanation:

Step 1:

The equation for the reaction is given below:

3Cu(s) + 8HNO3(aq) -> 2NO(g) 3Cu(NO3)2(aq) + 4H2O(l)

Step 2:

Determination of the change of oxidation number of each element present.

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Cu = 0 (ground state)

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The oxidation number of Cu changed from 0 to +2

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1. The oxidation number of Hydrogen is always +1 except in hydride where it is - 1

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Step 3:

Answers to the questions given above

From the above illustration,

1. Cu is oxidize because its oxidation number increased from 0 to +2 as it loses electron.

2. Cu is the reducing agent because it reduces the oxidation number of N from +5 to +2.

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Answer:

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Hello,

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