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Dennis_Churaev [7]
2 years ago
8

Calculate the mass percent of carbon (c) in carbon tetrachloride, (ccl4), if the molar mass of carbon tetrachloride is 153.8g.

Chemistry
2 answers:
baherus [9]2 years ago
3 0
<span>mass percent of carbon (c) in CCl</span>₄ = mass of C/mass of CCl₄
                                                        = 12 x 100/153.8 = 7.8%


NeTakaya2 years ago
3 0

<u>Answer:</u> The mass percent of carbon in carbon tetrachloride is 7.8 %.

<u>Explanation:</u>

In CCl_4, there are 1 carbon atoms and 4 chlorine atoms.

To calculate the mass percent of element in a given compound, we use the formula:

\text{Mass percent of carbon}=\frac{\text{Mass of carbon}}{\text{Molar mass of carbon tetrachloride}}\times 100

Mass of carbon = 12 g

Mass of carbon tetrachloride = 153.8 g

Putting values in above equation, we get:

\text{Mass percent of carbon}=\frac{12}{153.8}\times 100=7.80\%

Hence, the mass percent of carbon in carbon tetrachloride is 7.8 %.

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77julia77 [94]

Answer:

The amount of NaF produced is doubled.

(d) is correct option.

Explanation:

Given that,

A 2 mole sample of F₂ reacts with excess NaOH according to the equation.

The balance equation is

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If the reaction is repeated with excess NaOH but with 1 mole of F₂

The balance equation is

F_{2}+2NaOH\Rightarrow 2NaF +2OH

Hence, The amount of NaF produced is doubled.

(d) is correct option.

6 0
1 year ago
For a particular reaction, the change in enthalpy is â9kJmole and the activation energy is 13kJmole. The enthalpy change (ÎH) an
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Answer:

The answer is Option a, that is "−9kJmole,5kJmole".

Explanation:

Please find the complete question in the attached file.

In the question, it uses the catalyst inside a process, which does not modify the process eigenvalues, however, it decreases the active energy with an enthalpy of -9kJmole, and also the power for activating decreases around 13 to 5 kJ mole, that's why the choice a is correct.

4 0
2 years ago
Stabiliţi numerele de oxidare ale tuturor elementelor prezente în următoarele substanţe chimice, ţinând cont de principalele reg
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Answer:

a.

N = +2

O = -2

b.

Na = +1

O = -2

N = +5

c.

O = -2

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P = +5

d.

O = -2

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e

O = -2

Mn = +7

K = +1

f.

O = -2

K = +1

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g.

O = -2

Cl = +7

Cr = +1

h.

O = -2

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Cr = +5

i.

O = -2

H = +1

Cr = +3

k.

O = -2

H = +1

Cr = +1

Explanation:

A. NU

Numărul de oxidare a azotului = +2

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Numărul de oxidare al Al = +3

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g. HClO₄

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Numărul de oxidare al Cl = +7

Numărul de oxidare al Cr = +1

h. HClO₃

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Numărul de oxidare al lui H = +1

Numărul de oxidare al Cr = +5

i. HClO₂

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Numărul de oxidare al lui H = +1

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k. HClO

Numărul de oxidare de O = -2

Numărul de oxidare al lui H = +1

Numărul de oxidare al Cr = +1.

6 0
1 year ago
4.8g of calcium is added to 3.6g of water. The following reaction occurs
notka56 [123]
Q1)
the number of moles can be calculated as follows
number of moles = mass present / molar mass
number of moles is the amount of substance.
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0.12 mol of Ca is present 

q2)
next we are asked to calculate the number of moles of water present 
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sum of the products of the molar masses of the individual elements by the number of atoms 
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molar mass of H₂O is 18 g/mol 
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8 0
1 year ago
How many valence electrons are in chlorodifluoromethane
Elis [28]
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