For a particular reaction, the change in enthalpy is â9kJmole and the activation energy is 13kJmole. The enthalpy change (ÎH) an
1 answer:
Answer:
The answer is Option a, that is "−9kJmole,5kJmole".
Explanation:
Please find the complete question in the attached file.
In the question, it uses the catalyst inside a process, which does not modify the process eigenvalues, however, it decreases the active energy with an enthalpy of -9kJmole, and also the power for activating decreases around 13 to 5 kJ mole, that's why the choice a is correct.
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Answer:
0.08097 grams of nitrate ions are there in the final solution.
Explanation:
Moles of cobalt(II) nitrate ,n=
Volume of the cobalt(II) nitrate solution, V = 100.0 mL = 0.1 L
Let the molarity of the solution be
A students then takes 4 .00 mL of solution and dilute it to 275 ml.
(molarity after dilution)
(after dilution)
Molarity of the of solution after dilution is 0.002375 M.
1 mol of cobalt(II) nitrate gives 2 moles of nitrate ions. Then 0.002375 M solution of cobalt (II) nitrate will give:
Moles of nitrate ions = n
Volume of the solution = 275 mL = 0.275 L
Molarity of the nitrate ions =
n = 0.001306 mol
Mass of 0.001306 moles of nitrate ions:
0.001306 mol × 62 g/mol= 0.08097 g
0.08097 grams of nitrate ions are there in the final solution.