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3241004551 [841]
2 years ago
9

For a particular reaction, the change in enthalpy is â9kJmole and the activation energy is 13kJmole. The enthalpy change (ÎH) an

d activation energy (Ea) for the catalyzed reaction could be which of the following? a. â9kJmole,5kJmole. b. â9kJmole,19kJmole.c. â14kJmole,5kJmole.d. â14kJmole,â13kJmole.
Chemistry
1 answer:
Svetllana [295]2 years ago
4 0

Answer:

The answer is Option a, that is "−9kJmole,5kJmole".

Explanation:

Please find the complete question in the attached file.

In the question, it uses the catalyst inside a process, which does not modify the process eigenvalues, however, it decreases the active energy with an enthalpy of -9kJmole, and also the power for activating decreases around 13 to 5 kJ mole, that's why the choice a is correct.

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Which diagram shows the correct way to represent an ionic compound of magnesium oxide?
Daniel [21]
The answer is ................................ c
8 0
2 years ago
What is the empirical formula? A compound is used to treat iron deficiency in people. It contains 36.76% iron, 21.11% sulfur, an
Mandarinka [93]

Answer: The empirical formula of the compound is Fe_1S_1O_4

Explanation:

Empirical formula is defined formula which is simplest integer ratio of number of atoms of different elements present in the compound.

Percentage of iron in a compound = 36.76 %

Percentage of sulfur in a compound = 21.11 %

Percentage of oxygen in a compound = 42.13 %

Consider in 100 g of the compound:

Mass of iron in 100 g of compound = 36.76 g

Mass of iron in 100 g of compound = 21.11 g

Mass of iron in 100 g of compound = 42.13 g

Now calculate the number of moles each element:

Moles of iron=\frac{36.76 g}{55.84 g/mol}=0.658 mol

Moles of sulfur=\frac{21.11 g}{32.06 g/mol}=0.658 mol

Moles of oxygen=\frac{42.13 g}{16 g/mol}=2.633 mol

Divide the moles of each element by the smallest number of moles to calculated the ratio of the elements to each other

For Iron element = \frac{0.658 mol}{0.658 mol}=1

For sulfur element = \frac{0.658 mol}{0.658 mol}=1

For oxygen element = \frac{2.633 mol}{0.658 mol}=4.001\approx 4

So, the empirical formula of the compound is Fe_1S_1O_4

4 0
2 years ago
Read 2 more answers
Ammonia (nh3(g), hf = –46.19 kj/mol) reacts with hydrogen chloride (hcl(g), hf = –92.30 kj/mol) to form ammonium chloride (nh4cl
steposvetlana [31]

Answer: The \Delta H_{rxn} for the given chemical reaction is -175.51 kJ/mol

Explanation: Enthalpy change of the reaction is defined as the amount of heat released or absorbed in a given chemical reaction.

Mathematically,

\Delta H_{rxn}=\Delta H_f_{(products)}-\Delta H_f_{(reactants)}

We are given a chemical reaction. The reaction follows:

NH_3(g)+HCl(g)\rightarrow NH_4Cl(s)

H_f_{(NH_3)}=-46.19kJ/mol

H_f_{(HCl)}=-92.30kJ/mol

H_f_{(NH_4Cl)}=-314.4kJ/mol

Enthalpy change for the reaction of he given chemical reaction is given by:

\Delta H_{rxn}=H_f_{(NH_4Cl)}-(H_f_{(NH_3)}+H_f_{(HCl)})

Putting the values in above equation, we get

\Delta H_{rxn}=-314.4-(-92.30-46.19)kJ/mol

\Delta H_{rxn}=-175.51kJ/mol

8 0
2 years ago
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Would an alkali metal make a good replacement for tin in a tin can? Explain.
Igoryamba

Answer:

No

Explanation:

If tin is heated, it can react with alkalis' with the release of hydrogen.

6 0
2 years ago
2 attempts left select the single best answer. The radii of the lithium and magnesium ions are 76 pm and 72 pm, respectively. Wh
Lina20 [59]

The ionic character of any compound depend on the lattice energy as well as the electronegativity of element present in that compound.

More would be the lattice energy more would be ionic nature of that compound.

The lattice energy of any compound is inversely proportional to the ionic radii cation and anion.

In given case the ionic radii of oxide in both oxides would be equal therefore the lattice energy only depend on the ionic radii of cation.

Lattice energy (U)     =   \frac{1}{Ionic radii}

As the radii of Magnesium less then radii of lithium therefore lattice energy of Magnesium oxide would be more than lithium oxide.

Hence, MgO would be more ionic in nature than Li_{2}O

8 0
2 years ago
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