Answer:
sublime, melt, condense, deposit
Explanation:
1. When ice is warmed at a steady pressure 0.00512 atm, it will be sublime.
2. It will be melt when ice is warmed at a consistent pressure of 1 atm.
3. If water vapour pressure is continued to increase at a temperature of 100 C, it will be condense.
4. If water vapour pressure is continued to increase at a temperature of -50 C, it will be deposited.
Answer:
Explanation:
As per Boltzman equation, <em>kinetic energy (KE)</em> is in direct relation to the <em>temperature</em>, measured in absolute scale Kelvin.
Then, <em>the temperature at which the molecules of an ideal gas have 3 times the kinetic energy they have at any given temperature will be </em><em>3 times</em><em> such temperature.</em>
So, you must just convert the given temperature, 32°F, to kelvin scale.
You can do that in two stages.
- First, convert 32°F to °C. Since, 32°F is the freezing temperature of water, you may remember that is 0°C. You can also use the conversion formula: T (°C) = [T (°F) - 32] / 1.80
- Second, convert 0°C to kelvin:
T (K) = T(°C) + 273.15 K= 273.15 K
Then, <u>3 times</u> gives you: 3 × 273.15 K = 819.45 K
Since, 32°F has two significant figures, you must report your answer with the same number of significan figures. That is 820 K.
You multiply avogadro's number to what you were given.
8.30x10^23 * 6. 0221409x10^23
=1.357*10^25
That should be the right answer but I'm not sure. It has been awhile since I have done this.
The question is incomplete, here is the complete question:
A chemist measures the amount of bromine liquid produced during an experiment. She finds that 766.g of bromine liquid is produced. Calculate the number of moles of bromine liquid produced. Round your answer to 3 significant digits.
<u>Answer:</u> The amount of liquid bromine produced is 4.79 moles.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:

We are given:
Given mass of liquid bromine = 766. g
Molar mass of liquid bromine,
= 159.8 g/mol
Putting values in above equation, we get:

Hence, the amount of liquid bromine produced is 4.79 moles.
Answer:
We have to add 2.30 L of oxygen gas
Explanation:
Step 1: Data given
Initial volume = 4.00 L
Number of moles oxygen gas= 0.864 moles
Temperature = constant
Number of moles of oxygen gas increased to 1.36 moles
Step 2: Calculate new volume
V1/n1 = V2/n2
⇒V1 = the initial volume of the vessel = 4.00 L
⇒n1 = the initial number of moles oxygen gas = 0.864 moles
⇒V2 = the nex volume of the vessel
⇒n2 = the increased number of moles oxygen gas = 1.36 moles
4.00L / 0.864 moles = V2 / 1.36 moles
V2 = 6.30 L
The new volume is 6.30 L
Step 3: Calculate the amount of oxygen gas we have to add
6.30 - 4.00 = 2.30 L
We have to add 2.30 L of oxygen gas