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nadya68 [22]
2 years ago
10

1. If ice is heated at a constant pressure of 0.00512 atm, it will______ . 2. If ice is heated at a constant pressure of 1 atm,

it will_______ . 3. If the pressure of water vapor is increased at a constant temperature of 100 degrees Celsius, it will________ . 4. If the pressure of water vapor is increased at a constant temperature of -50 degrees Celsius, it will________ .
Chemistry
1 answer:
evablogger [386]2 years ago
5 0

Answer:

sublime, melt, condense, deposit

Explanation:

1. When ice is warmed at a steady pressure 0.00512 atm, it will be sublime.  

2. It will be melt when ice is warmed at a consistent pressure of 1 atm.

3. If water vapour pressure is continued to increase at a temperature of 100  C, it will be condense.  

4. If water vapour pressure is continued to increase at a temperature of -50 C, it will be deposited.

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ruslelena [56]
Transfer of electrons
6 0
2 years ago
The equilibrium constant for the reaction sr(s) + mg2+(aq) ⇌ sr2+(aq) + mg(s) is 2.69 × 1012 at 25°c. calculate e o for a cell m
Mariulka [41]
Sr(s)+Mg²+(aq)→Sr²+(aq)+Mg(s)
Number of e-'s transfered are, n=2. Equilibrium constant,
K=2.69×10∧12
ΔG=-2.303RT logK
R=gasconstant=8.314J/mol-k
T= temperature in K= 25 oC=25+273=298K
The value we get ΔG = -70922.3J. But ΔG = -nFE
n= number of e-'s transfered in the reaction =2
F= farady = 96500C
E=potential of the cell is what?
∴E = ΔG.nF
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8 0
2 years ago
How many grams of oxygen are in 56 g of c2h2o2?
jolli1 [7]
First, find percent of oxygen: atom/molecule... there are 2 atoms of Oxygen so: O2/C2H2O2 which is: 32g O2 / 58g C2H2O2 =32/58. 

<span>Next, multiply this by the total mass (56g C2H2O2) and the units will cancel out (g*g/g -> g) leaving you with the mass of Oxygen: </span>

<span>56g C2H2O2 * 32g O2/58g C2H2O2 = 56*32/58= 31g</span>
3 0
2 years ago
Read 2 more answers
A hypothetical substance has a melting point of −10°C and a boiling point of 155°C. If this substance is heated from 2°C to the
igor_vitrenko [27]

Answer:

The specific heat capacity of liquid and the het of vaporization is used.

.

Explanation:

Step 1: Data given

A substance at temperature 2°C.

The substance has a melting point of −10°C and a boiling point of 155°C.

The initial temperature is 2°C which is between the melting point (-10°C) and the boiling point (155°C). At 2°C, the substance is liquid.

At 155°C, the substance changes from liquid to gas.

To calculate the heat gained for the change of 2°C liquid to 155°C liquid, specific heat capacity of the liquid (C) is needed.

To calculate the heat gained for the change of liquid to 155°C gas, heat of vaporization (D) is needed.

The <u>specific heat of the solid is not used</u> because the substance is changed from liquid to gas. it doesn't come in the state of solid.

<u>Heat of fusion is not used</u>, because it's used when there is a change from its state from a solid to a liquid,

<u>The specific heat capacity of the gas is not used</u>, because the substance only formes gas after reaching 155 °C

5 0
2 years ago
What must the melting point of the mold be compared to the temperature at which class get soft and why
stiv31 [10]

The answer is that the mold melting point must be higher then molten glass, otherwise the mold would melt when molten glass is poured into it .


I hope this helps :)

7 0
2 years ago
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