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1 year ago

How might you measure the amount of energy in the world's largest rice cake?

Chemistry

1 answer:

enot [183]1 year ago

7 0

Answer:

kindly check the explanation section.

Explanation:

The largest rice cake in the world was discovered in the year 2007 in South Korea with a weight of 8,113 lb. The amount of energy in the World's largest rice cake can be determined by using the formula below:

The energy in kJ =[ mass of water] x [specific heat capacity of water] x [change in temperature].

In order to determine experimentally in the laboratory and make use of the formula above. The first thing[STEP ONE] to do is to measure the mass of the rice cake and record it.

STEP TWO: measure a known amount of water in a boiling tube.

STEP THREE: Heat the rice cake until it catches fire with a Bunsen flame.

STEP FOUR: Use the rice cake that has already caught fire in step three above and use it to heat the water in step two until the fire burns out.

Repeat the process for three to four times and record your observations under the following headings;

[1]. Mass of cake, [2]. Temperature of water before burning, [3]. Temperature of water after burning and Temperature increase per gram of the rice cake.

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The Lewis dot notation for two atoms is shown.

NISA [10]

To help, I drew a diagram. This represents an ionic bond between Na and Cl. Na is giving his single electron to Cl, which is indicated by the arrow, to make Cl full with 8 electrons.

7 0

1 year ago

Read 2 more answers

Calculate the wavelength of the photon emitted when an electron makes a transition from n=6 to n=3. You can make use of the foll

Angelina_Jolie [31]

Answer: The wavelength of light is $1.094\times 10^{-6}m$

Explanation:

To calculate the wavelength of light, we use Rydberg's Equation:

$\frac{1}{\lambda}=R_H\left(\frac{1}{n_f^2}-\frac{1}{n_i^2} \right )$

Where,

$\lambda$ = Wavelength of radiation

$R_H$ = Rydberg's Constant = $1.097\times 10^7m^{-1}$

$n_f$ = Final energy level = 3

$n_i$ = Initial energy level = 6

Putting the values in above equation, we get:

$\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{3^2}-\frac{1}{6^2} \right )\\\\\lambda =\frac{1}{914617m^{-1}}=1.094\times 10^{-6}m$

Hence, the wavelength of light is $1.094\times 10^{-6}m$

6 0

2 years ago

Which elements do not strictly follow the octet rule when they appear in the Lewis structure of a molecule?

Virty [35]

Thee question is incomplete; the complete question is;

Which elements do not strictly follow the octet rule when they appear in the Lewis structure of a molecule?

Select one or more:

A: Chlorine

B: Carbon

C: Hydrogen

D: Sulfur

E: Fluorine

F: Oxygen

Answer:

chlorine

sulphur

Explanation:

The octet rule states that, for atoms to be stable, they must have eight electrons on their outermost shells.

This rule is not strictly followed by some elements such as sulphur and chlorine. The atoms of these elements can sometimes expand their octet by utilizing the d-orbitals found in the third principal energy level and beyond.

These leads to formation of compounds in which the central atom has more than eight electrons in its outermost shell.

5 0

1 year ago

7.00g of Compound X with molecular formula C5H10 are burned in a constant-pressure calorimeter containing 35.00kg of water at 25

horsena [70]

Answer:

The standard heat of formation of Compound X at 25°C is -3095.75 kJ/mol.

Explanation:

Mass of compound X = 7.00 g

Moles of compound X = $\frac{7.00 g}{70 g/mol}=0.100 mol$

Mass of water in calorimeter ,m= 35.00 kg = 35000 g

Change in temperature of the water in calorimeter = ΔT

ΔT = 2.113°C

Specific heat capacity of water ,c= 4.186 J/g °C

Q = m × c × ΔT

$Q=35000 g\times 4.186 J/g ^oC\times 2.113^oC=309,575.6 J=309.575 kJ$

Heat gained by 35 kg of water is equal to the heat released on burning of 0.100 moles of compound X.

Heat of formation of Compound X at 25°C:

$\frac{-Q}{\text{moles of compound X}}=\frac{-309.575 }{0.100 mol}$

= -3095.75 kJ/mol

6 0

1 year ago

Determine whether the stopcock should be completely open, partially open, or completely closed for each activity involved with t

densk [106]

Answer:

Close to the calculated endpoint of a titration - Partially open

At the beginning of a titration - Completely open

Filling the buret with titrant - Completely closed

Conditioning the buret with the titrant - Completely closed

Explanation:

'Titration' is depicted as the process under which the concentration of some substances in a solution is determined by adding measured amounts of some other substance until a rection is displayed to be complete.

As per the question, the stopcock would remain completely open when the process of titration starts. After the buret is successfully placed, the titrant is carefully put through the buret in the stopcock which is entirely closed. Thereafter, when the titrant and the buret are conditioned, the stopcock must remain closed for correct results. Then, when the process is near the estimated end-point and the solution begins to turn its color, the stopcock would be slightly open before the reading of the endpoint for adding the drops of titrant for final observation.

3 0

1 year ago