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Darya [45]
2 years ago
5

Suppose a 5.00 l sample of o2 at a given temperature and pressure contains 1.08

Chemistry
1 answer:
arsen [322]2 years ago
5 0
Missing question: <span>A 5.00 L sample of O2 at a given temperature and pressure contains a 1.08x10^23 molecules. How many molecules would be contained in each of the following at the same temperature and pressure? </span>
a) 5.00 L H2.
<span>b) 5.00 L CO2.
Use </span>Avogadro's Law: The Volume Amount Law: <span>equal </span>volumes<span> of all gases, at the same temperature and pressure, have the same </span>number<span> of molecules. Because hydrogen and carbon(IV) oxide are gases, number of molecules are the same as number of oxygen molecules, so:
a) N(H</span>₂) = 1.08·10²³.
b) N(CO₂) = 1.08·10²³

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(a) What are the possible values of l for n = 4? (Enter your answers as a comma-separated list.)
vodka [1.7K]

Answer:

(a) 0,1,2,3      (b) -3,-2,-1,0,1,2,3              (c) 6               (d) 5

Explanation:

(a) for the principal quantum number 'n', the possible values of I = 0 to n-1. Thus, if the principal quantum number 'n' =4, I = 0,1,2,3.

(b) for a given number of 'I', the possible values of ml = -I to +I. Therefore, if I =3, then ml = -3,-2,-1,0,1,2,3

(c) 'I' which is the orbital angular momentum quantum number usually has values from 0,1,2,⋯,n−1. Therefore, for n greater than or 6, t would be greater than or equal to 5. Thus, the smallest possible value of n for which I can be 6 is 6.

(d) In a 3-dimensional figure,  If the z-component of the orbital angular momentum Lz for which I=5 is measured, The possible outcomes will be:

mħ = -5ħ, -4ħ, -3ħ, -2ħ, -1ħ, 0, 1ħ, 2ħ, 3ħ, 4ħ, 5ħ.

Thus, the smallest possible l that can have a z component of 5ℏ is 5.

4 0
2 years ago
You decide to establish a new temperature scale on which the melting point of ammonia (-77.75 ∘c) is 0∘a, and the boiling point
Hoochie [10]
First we need to know that the boiling point of water in C is 100 and we just need to solve for x in the equation:

-33.75-(-77.75) / 100 = 100-(-77.75) / x
44.4/100 = 177.75 / x
 x = 177.75*100/44.4 = 400.33

The boiling point of water in ∘a would be 400.33∘a.

7 0
2 years ago
Read 2 more answers
A bottle of antiseptic hydrogen peroxide (H2O2) is labeled 3.0% (v/v). How many mL H2O2 are in a 400.0 mL bottle of this solutio
PolarNik [594]

Answer:

= 12 mL H202

Explanation:

Given that, the concentration of H2O2 is given antiseptic = 3.0 % v/v

It implies that, 3ml  H2O2 is present in 100 ml of solution.

Therefore, to calculate the amount of H202 in 400.0 mL bottle of solution;

we have;

 (3.0 mL/ 100 mL) × 400 mL

= 12 mL H202

6 0
2 years ago
Consider the following equilibrium system: 3O2(g)  2O3(g); Keq = 1 Which equation compares the concentration of oxygen and ozone
Rashid [163]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

 <span>3O2(g) <--> 2O3(g); 

Keq = 1 = [O3]^2/[O2]^3 

So [O2]^3 = [O3]^2 

Thus A) is correct</span>
7 0
2 years ago
Read 2 more answers
Which quantity can vary among atoms of the same element?
Wewaii [24]
There is this thing called isotopes
it means that atoms of the same element can have a different number of neutrons.
if there is a change in the no. of neutrons, there will definitely be a change in the mass number.

so the answer is A) mass number
7 0
2 years ago
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