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WITCHER [35]
1 year ago
6

Put the following elements into five pairs of elements that have similar chemical reactivity: F, Sr, P, Ca, O, Br, Rb, Sb, Li, S

Chemistry
1 answer:
kirill115 [55]1 year ago
7 0

Explanation:

Given elements:

  F, Sr, P, Ca, O, Br, Rb, Sb, Li, S

Elements with the same chemical reactivity will belong to the same group on the periodic table. This implies that elements in the same column will have the same reactivity;

  Li and Rb are both alkali metals in group 1

  Ca and Sr are both alkali earth metals in group 2

  F and Br are halogens in group 7

  O and S are group 6 elements

 P and Sb are both in group 5 on the periodic table

So these groupings show elements with the same chemical properties.

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When 64.0 g of methanol (CHOH) is burned, 1454 kJ of energy is produced. What is the heat of combustion for methanol?
andreev551 [17]

 The heat  of combustion  for  methanol   is 727  kj/mol


    <em><u>calculation</u></em>

 calculate the moles  of methanol (CH3OH)

moles = mass/molar  mass

molar mass of methanol =  12 +( 1 x3)  +16 + 1= 32 g /mol

moles is therefore= 64.0 g / 32 g/mol =  2 moles


Heat of combustion  is therefore = 1454 Kj / 2 moles =  727  Kj/mol

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1 year ago
when you burn a log in the fireplace, the resulting ashes have a mass less than that of the original log. Account for the differ
Margaret [11]
Some of the particles undergo a phase change and become a gas due to burning. An example would be CO2, which is lost in the air around/escapes into the atmosphere. Hope that helps!
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2 years ago
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Papessa [141]

Answer:

The molecular formula of cacodyl is C₄H₁₂As₂.

Explanation:

<u>Let's assume we have 1 mol of cacodyl</u>, in that case we'd have 209.96 g of cacodyl and the<u> following masses of its components</u>:

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Now we convert those masses into moles:

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Those amounts of moles represent the amount of each component in 1 mol of cacodyl, thus, the molecular formula of cacodyl is C₄H₁₂As₂.

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1 year ago
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Soda provides nutritional value that helps plants grow.

Explanation:

I just did this question and that’s what was right.

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