Consider the elements in the periodic table. The stair-step line between the pink squares and the yellow squares separates the _
2 answers:
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Amines are derivatives of Ammonia (NH₃) in which atleast one hydrogen atom is replaced by an alkyl group. Amines are further classifies as;
Primary Amines:
In primary amines the nitrogen atom is attached to two hydrogen atoms and one alkyl group.
Secondary Amines:
In secondary amines the nitrogen atom is attached to two alkyl groups and one hydrogen atom.
Tertiary Amines:
In tertiary amines the nitrogen atom is attached to three alkyl groups, hence it has no hydrogen atom.
Below are three isomers of tertiary amines with molecular formula C₅H₁₃N.
Primary Amines:
In primary amines the nitrogen atom is attached to two hydrogen atoms and one alkyl group.
Secondary Amines:
In secondary amines the nitrogen atom is attached to two alkyl groups and one hydrogen atom.
Tertiary Amines:
In tertiary amines the nitrogen atom is attached to three alkyl groups, hence it has no hydrogen atom.
Below are three isomers of tertiary amines with molecular formula C₅H₁₃N.
Answer:
45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
V₁ = 25.0 L
V₂ = ?
P₁ = 2575 mm Hg
Also, P (atm) = P (mm Hg) / 760
P₁ = 2575 / 760 atm = 3.39 atm
P₂ = 1.35 atm
T₁ = 353 K
T₂ = 253 K
Using above equation as:
Solving for V₂ , we get:
<u>V₂ = 45.0 L</u>
45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.
Explanation:
Molarity of copper sulfate solution = 1.00 M
Volume of the copper sulfate solution = 50.0 mL = 0.050 L
Moles of copper sulfate = n
n = 0.050 L × 1.00 M= 0.050 mol
1 mol of copper sulfate has 1 mol of copper . Then 0.050 mol of copper sulfate has :
of copper
a) Mass of 0.050 moles of copper = 0.050 mol × 63.5 g/mol =3.175 g
b) The identity of the compound which formed after the reaction is copper hydroxide.
c) The complete equation for the reaction that occurs when copper sulfate and potassium hydroxide are mixed:
d) ..[1]
..[2]
Common ion both sides are removed. The net ionic equation is given as:
e) Volume of solution after mixing of both solution,V= 50 mL + 50ml = 100 mL
Mass of final solution ,m= 1 mL
Density of solution ,d= 1 g/mL (same as pure water)
Heat capacity of the solution = c = 4.186 J/g°C (same as pure water)
Change in temperature of the solution,ΔT = 27.7 °C- 21.5 °C=6.2°C
Enthalpy of the reaction = ΔH =
ΔH =
The ΔH for the reaction that occurs on mixing is 51.90 kJ/mol.