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seropon [69]
2 years ago
8

Formulating an Investigative Question In this experiment, you will use a track and a toy car to explore the concept of movement.

You will measure the time it takes the car to travel certain distances, and then complete some calculations. In the space below, write a scientific question that you will answer by doing this experiment.
Chemistry
1 answer:
Solnce55 [7]2 years ago
3 0

Answer:

A scientific question to be asked is; <em>What is the average speed of the toy car?</em>

Explanation:

A scientific question is a question which is well defined, the values in the question can be measured, and the inputs and outputs related to the question are controllable

The parameters measured in the experiment are;

The time elapsed during the movement of the car, <em>Δt</em>

The distance the car moves, <em>d</em>

From the obtained measurements, the value can be calculated is the average speed of the toy car as follows;

The \ average \ speed \ of \ the \ toy \ car, \ v_{avg} = \dfrac{d}{\Delta t}

Therefore, a scientific question to be asked that will be answered by doing the experiment is; What is the average speed of the toy car?

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Answer:

0.077 M

Explanation:

Data Given :

The concentration of half normal (NaCl) saline = 0.45g / 100 g

So,

Volume of Solution = 100 g = 100 mL

Volume of Solution in Liter = 100 mL / 1000

Volume of Solution = 0.1 L

molar mass of NaCl = 58.44 g/mol

Molarity:

Molarity is the representation of the solution. It is amount of solute in moles per liter of solution and represented by M

Formula used for Molarity

                M = moles of solute / Liter of solution . . . . . . . . . . (1)

Now to find number of moles of Nacl

                no. of moles of NaCl = mass of NaCl / molar mass

                no. of moles of NaCl = 0.45g / 58.44 g/mol

               no. of moles of NaCl = 0.0077 g

Put values in the eq (1)

                  M = moles of solute / Liter of solution . . . . . . . . . . (1)

                  M = 0.0077 g / 0.1 L

                  M = 0.077 M

So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M

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