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Aleksandr-060686 [28]
2 years ago
13

The value of resistance r was determined by measuring current I flowing through the resistance with an error E1=±1.5% and power

loss p in it with an error E2=±1.0%. Determine the maximum possible relative error to be expected on measuring resistance r, calculated from the formula r=p/I²​
Chemistry
1 answer:
frozen [14]2 years ago
5 0

Answer:5

Explanation:help me to solve

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A student in a chemistry laboratory has access to two acid solutions. The first one is 20% acid and the second solution is 45% a
Ksju [112]

Volume of each solution : 60 ml 20% and 40 ml 45%

<h3>Further explanation</h3>

Given

20% and 45% acid

100 ml of 30% acid

Required

Volume of each solution

Solution

Molarity from 2 solutions :

Vm Mm = V₁. M₁ + V₂. M₂  

m = mixed solution

V = volume

M = molarity

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V₂ = (100 - x) ml

Input the value :

100 . 0.3 = x . 0.2 + (100-x) . 0.45

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7 0
2 years ago
A bottle of antiseptic hydrogen peroxide (H2O2) is labeled 3.0% (v/v). How many mL H2O2 are in a 400.0 mL bottle of this solutio
PolarNik [594]

Answer:

= 12 mL H202

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Given that, the concentration of H2O2 is given antiseptic = 3.0 % v/v

It implies that, 3ml  H2O2 is present in 100 ml of solution.

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