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Burka [1]
2 years ago
8

What is an azeotrope? 2. Under what conditions is it better to perform a steam distillation (instead of, say, a simple distillat

ion)? 3. During a steam distillation, how can you tell if the organic compound is still coming over (i.e., still being distilled)? 4. For this experiment, at the end of the steam distillation, the receiving flask should contain two layers of liquid. What is the chemical identity of these two liquids? 5. What is the purpose of adding 10% sodium carbonate solution to the distillate if it is acidic to litmus?
Chemistry
1 answer:
aleksandrvk [35]2 years ago
7 0

Answer:

Explanation:

1.)azeotrope is a mixture of two or more liquid components under constant boiling, it has a constant mole fraction composition of present component which can be homogeneous or heterogeneous.

2.)the condition which it's best performed when there's liquids that is non-volatile which boils higher than other liquids with at least 26 degrees .

steam azentropic distillation

3.During a steam distillation, How to know if the organic compound is still coming over is when you see the solution becoming cloudy or when there is existence of two layers.

4.)The end of the steam distillation, the receiving flask should contain two layers of liquid, and the chemical identity of these two liquids most contain

A.) Layers that are mostly water H2O

B.) Layers that are mostly products

5.)What is the purpose of adding 10% sodium carbonate solution to the distillate if it is acidic to litmus is to neutralize the distillate.

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Five darts strike near the center of the target. Who ever threw the darks is?
Burka [1]

Better than i am and very precice


7 0
2 years ago
Read 2 more answers
Consider the reaction: 2 Al + 3Br2 → 2 AlBr3 Suppose a reaction vessel initially contains 5.0 mole Al and 6.0 mole Br2. What is
timama [110]

Answer:

4 moles of AlBr_3 and 1 mole of Al will be present in the reaction vessel

Explanation:

The reaction given in the question is

2Al +  3 Br_2 ⇒ 2AlBr_3

According to the stoichiometric coefficients of the reaction, 2 moles of Al requires 3 moles of Br_2 so in this reaction, Br_2 is a limiting reagent. So we will consider that Al is in excess.

Now,

Since 3 moles of Br_2 requires 2 moles of Al

So, for 6 moles of Br_2 the moles of Al required = \frac{2}{3} \times 6 = 4 moles.

Moles of Al remaining after the completion of reaction = 5 - 4 = 1 mole.

Again,

Since 3 moles of Br_2 produces 2 moles of AlBr_3

So, moles of AlBr_3 produced by 6 moles of Br_2 = \frac{2}{3} \times 6 = 4 moles.

Therefore, after the completion of reaction, 4 moles of AlBr_3 and 1 mole of Al will be present in the reaction vessel.

5 0
2 years ago
How many chloride ions are in 0.486 moles of chloride ions?​
svetlana [45]

Answer:

Since in a chloride ion, we have an additional electron

you might think that it will affect the mass but the mass of an electron is almost negligible so we will ignore that

Amount of ions in 1 mol = 6.022 * 10^23

Amount of ions in 0.486 moles = 0.486 * (6.022*10^23)

Amunt of ions in 0.486 moles = 2.9 * 10^23 ions

Hence, option 1 is correct

6 0
2 years ago
Question 17 In the Haber reaction, patented by German chemist Fritz Haber in 1908, dinitrogen gas combines with dihydrogen gas t
mars1129 [50]

Answer:

Explanation:

N₂       + 3H₂     =     2 NH₃

1 vol                         2 vol

786 liters               1572 liters

786 liters of dinitrogen will result in the production of 1572 liters of ammonia

volume of ammonia V₁ = 1572 liters

temperature T₁ = 222 + 273 = 495 K

pressure = .35 atm

We shall find this volume at NTP

volume V₂ = ?

pressure = 1 atm

temperature T₂ = 273

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

\frac{.35\times 1572}{495} =\frac{1\times V_2}{ 273 }

V_2 =303.44 liter .

mol weight of ammonia = 17

At NTP mass of 22.4 liter of ammonia will have mass of 17 gm

mass of 303.44 liter of ammonia will be equal to (303.44 x 17) / 22.4 gm

= 230.28 gm

=.23 kg / sec .

Rate of production of ammonia = .23 kg /s .

5 0
2 years ago
4. A sample of silicon contains<br> 5.23 x 1011 atoms. Write this amount<br> as a whole number.
Marat540 [252]
The answer is 523000000000
8 0
2 years ago
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