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ololo11 [35]
2 years ago
6

The wavelength of light is 310. nm; calculate the frequency.

Chemistry
2 answers:
Leto [7]2 years ago
5 0

Explanation:

It is given that wavelength of light is 310 nm or 310 \times 10^{-9} m. Relation between wavelength, speed of light and frequency is as follows.

                   \nu = \frac{c}{\lambda}

where,      \nu = frequency

                     c = speed of light = 3 \times 10^{8} m/s

                \lambda = wavelength

Hence, putting the given values into the above formula as follows.

             \nu = \frac{c}{\lambda}

            \nu = \frac{3 \times 10^{8} m/s}{310 \times 10^{-9} m}

                       = 9.67 \times 10^{14} per second

Thus, we can conclude that the frequency of given light is 9.67 \times 10^{14} per second.

kondor19780726 [428]2 years ago
4 0
Frequency = velocity of propagation / wavelength. 

<span>For light, we assume it is moving in a vacuum, so vp is 3e8 m/s. The wavelength of 310nm is 310e-9 meters. Then we plug the numbers in, and we get (3e8 m/s) / (310e-9 m) = 967.742e12 Hz because 1/s is the same as cycles/sec, which is a Hertz.</span>
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Answer:

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Explanation:

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<u>PROTECTION OF COMMUNITY FROM SOIL EROSION -</u>

  • <u>Maintaining a good, perennial cover for plants  -:</u> Your perennial garden's care and upkeep need not be difficult or overwhelming. A blend of certain simple horticultural values with common sense and a good eye is a great part of good gardening.
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Virty [35]

Thee question is incomplete; the complete question is;

Which elements do not strictly follow the octet rule when they appear in the Lewis structure of a molecule?

Select one or more:

A: Chlorine

B: Carbon

C: Hydrogen

D: Sulfur

E: Fluorine

F: Oxygen

Answer:

chlorine

sulphur

Explanation:

The octet rule states that, for  atoms to be stable, they must have eight electrons on their outermost shells.

This rule is not strictly followed  by some elements such as sulphur and chlorine. The atoms of these elements can sometimes expand their octet by utilizing the d-orbitals found in the third principal energy level and beyond.

These leads to formation of compounds in which the central atom has more than eight electrons in its outermost shell.

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ch4aika [34]
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mina [271]
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</span>1.40x10^23 molecules of N2 ( 1 mol / 6.022 x 10^23 molecules ) ( 28.02 g / mol ) = 6.51 g N2
7 0
1 year ago
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