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8090 [49]
2 years ago
12

A sample of water with a mass of 587.00 kg is heated with 87 kJ of energy to a temperature of 518.4 K. The specific heat of wate

r is 1 J-1 kg K-1. What is the initial temperature of the water?

Chemistry
2 answers:
Tems11 [23]2 years ago
7 0

The correct specific heat capacity of water is <em>4.187 kJ/(kg.K)</em>.

q = mCΔT

ΔT = q/mC = 87 kJ/[587.00 kg x 4.187 kJ/(kg.K)] = 87 kJ/(2547.8 kJ/K)

= 0.035 K

Ti = Tf - ΔT = 518.4 K - 0.0354 K = 518.365 K


uysha [10]2 years ago
7 0

Answer:

370.2 K

Explanation:

The explanation is in the attached image

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Carbon dioxide, CO₂, changes from the solid phase to the gas phase at 1 atm and 194.5 K. In the solid phase, CO₂ is often called
FinnZ [79.3K]

Answer:

1. From water vapor to the dry ice;

2. The potential energy is higher before the water vapor condenses;

3. The thermal energy is higher in the 2.0 kg block.

Explanation:

1. The heat flows from the system with high temperature to the system with low temperature. The water vapor is at 298 K, and the dry ice is at 194.5 K.

2. The energy of the molecules is related to the temperature and the physics state. At the gas state, the molecules are more agitated, and the energy is higher than the liquid state. So, when the vapor condenses to a liquid, the energy decreases.

3. The thermal energy can be calculated by:

Q = m*c*ΔT

Where m is the mass, c is the specific heat, and ΔT the variation in the temperature. So, when the mass increase, thermal energy also increases.

5 0
2 years ago
To maximize the yield in a certain manufacturing process, a solution of a weak monoprotic acid that has a concentration between
stira [4]

Answer: C 115 ml

Explanation:

If you have a solution of a monoprotic acid, it means that it has the form HA (just one Hydrigen atom). Therefore, one molecule of acid is going to react with just one molecule of  NaOH.

So, if you have a solution of 100 ml of 0,2 HA acid, it is going to react with a 100 ml of 0,2 M NaOH solution. Beacause we know that the acid can be a little more concentrated than 0,2 M (0,2-0,3), it probably needs a little more than 100 ml of NaOH to react.  So, the answer is C.

in 100 ml of 0,2M acid you can find 0,002 mol of HA

in 100 ml of 0,3 M acid you can find 0,003 mol of HA

in 100 ml of 0,2 M NaOH you can find 0,002 mol of NaOH

the answer can not be 200 because in 200 ml of 0,2 M NaOH there are 0,004 mol of NaOH, which is more than 0,003 mol.

0 0
2 years ago
Perform the following conversion: 6.1 × 103 K (the surface temperature of the Sun) to °F and °C. Pay attention to the number of
Keith_Richards [23]

Answer:

\°C=5.8x10^3\°C

\°F=1.1x10^4\°F

Explanation:

Hello,

In this case, for the calculation of the temperature in degree Celsius we subtract 273.15 to the given temperature in kelvins:

\°C=6100-273.15\\\\\°C=5.8x10^3\°C

Next, by applying the following equation we compute it in degree Fahrenheit:

\°F=(5.8x10^{3}*9/5) + 32\\\\\°F=1.1x10^4\°F

Clearly, since the initial unit has two significant figures the computed units also show two significant figures.

Regards.

5 0
2 years ago
The U.S. Mint produces a dollar coin called the American Silver Eagle that is made of nearly pure silver. This coin has a diamet
Rudik [331]

Answer:

The value of the silver in the coin is 35.3 $

Explanation:

First of all, let's calculate the volume of the coin.

2π . r² . thickness = volume

r = diameter/2

r = 41 mm/2 = 20.5 mm

2 . π . (20.5 mm)² .  2.5 mm = 6601 mm³

Now, this is the volume of the coin, so we must find out how many grams are on it.

6601 mm³ / 1000 = 6.60 cm³

Let's apply density.

D = Mass / volume

10.5 g/cm³ = mass /6.60 cm³

10.5 g/cm³ . 6.60 cm³ = mass

69.3 g = mass

Each gram has a cost of 0.51$

69.3 g . 0.51$ = 35.3 $

7 0
2 years ago
A well-insulated, closed device claims to be able to compress 100 mol of propylene, acting as a SoaveRedlich-Kwong gas and with
Setler79 [48]

Explanation:

The given data is as follows.

    Moles of propylene = 100 moles,    T_{i} = 300 K

    T_{f} = 800 K,    V_{i} = 2 m^{3}

    V_{f} = 0.02 m^{3},   C_{p} of propylene = 100 J/mol

Now, we assume the following assumptions:

Since, it is a compression process therefore, work will be done on the system. And, work done will be equal to the heat energy liberating without any friction.

            W = mC_{p} \Delta T

     100 moles \times 100 J/mol K (800 - 300) K

                 = 5 \times 10^{6} J

                 = 5 MJ

Thus, we can conclude that a minimum of 5 MJ work is required without any friction.

3 0
2 years ago
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