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bezimeni [28]
2 years ago
14

Oxygen forms a number of compounds with sulfur, many of which are quite reactive. One such compound is 57.20 % by mass S . Calcu

late the number of grams of oxygen present in a sample of this compound that contains 50.00 grams of S .
Chemistry
2 answers:
nikklg [1K]2 years ago
3 0
Answer is: <span>number of grams of oxygen present in a sample is </span>37,41 g.
m(S) = 50 g.
mass percentage (S) = 57,20 % = 0,572.
mass percentage (O) = 100% - 57,20% 
mass percentage(O) = 42,8% = 0,428.
m(O) = ?.
make proportion 57,20% : 42,8% = 50 g : m(O)
57,2% · m(O) = 42,8% · 50 g.
m(O) = 42,8% · 50 g ÷ 57,2%.
m(O) = 37,41 g.
Andreyy892 years ago
3 0

Answer:

37.41 grams of oxygen present in a sample of this compound that contains 50.00 grams of S.

Explanation:

Mass of Sulfur present in the sample = 50.00 g

Mass of oxygen present in the sample = m

Total mass of the sample of the compound =  = 50.00 g + m

Percentage of sulfur by mass in the compound = 57.20%

\%(S)=\frac{\text{Mass of sulfur}}{\text{Total mass of the compound}}\times 100

57.20\%=\frac{50.00 g}{50.00g + m}\times 100

m = 37.41 g

37.41 grams of oxygen present in a sample of this compound that contains 50.00 grams of S.

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Consider the elements in Group 14. Which element has the highest electron affinity? A) Carbon B) Germanium C) Lead D) Silicon
svlad2 [7]

Electron affinity is a measure of the tendency of a neutral atom  to gain electrons and form a negative ion. It can be represented by a general equation:

X + e- → X-

The value of electron affinity decreases on moving down a group. This is because on moving down a group the atomic size increases as a result the added electron feels less pull or attraction towards the nucleus.

In group 14, Carbon 'C' is the first member and therefore will have the highest electron affinity.

Ans : A) Carbon

3 0
2 years ago
A piece of lead loses 78.0 J ofheat and experiences a decrease in temperature of 9.0C the specific heat of lead is .130J/gC what
Ratling [72]
The  mass of  the piece  of  lead   is    calculated  using the  below  formula
Q(heat)= mC delta T

Q = 78.0  j
M=mass =?
C=specific heat capacity (   0.130 j/g/c
delat T=change in temperature =  9.0 c

by  making  M  the  subject  of  the formula
M = Q/ c delta T

M=  78.0 j/ 0.130 j/g/c  x  9.0 c =  66.7 g  of  lead
3 0
2 years ago
This problem has been solved! See the answer Determine Um (mode ), average U, and Urms for a group of ten automobiles clocked by
lara31 [8.8K]

Explanation:

The mode is the most common number.

Um = 55

The mean is the sum of the numbers divided by the quantity.

Uavg = (38 + 44 + 45 + 48 + 50 + 55 + 55 + 57 + 58 + 60) / 10

Uavg = 51

The RMS (root mean square) is the square root of the sum of the squares of the numbers divided by the quantity.

Urms = √[(38² + 44² + 45² + 48² + 50² + 55² + 55² + 57² + 58² + 60²) / 10]

Urms = 51.451

4 0
2 years ago
Why did you blank with the 0.0020 M Fe(NO3)3 solution as opposed to just DI water? What does it do to your spectrum? What chemic
Vlad1618 [11]

Answer:

The cuvette was blank with the solution so that the spectrometer will only read the solute absorbance. This also ensures that the spectrometer will ignore other absorbance fluctuations that normally occur due to the chemical make-up of water. The spectrometer only considered the absorbance of FeNCS^{2+} as indicated on the spectrum. The reaction between the Fe^{3+} and the SCN^{-} are both clear liquids that form the orange liquid product  FeNCS^{2+} which creates the absorbance spectrum. Because the color of the solution is orange, it reflects this and similar colors while absorbing blueish hues. We can find the absorption of only the FeNCS^{2+} by pre-rinsing the cuvette with each solution we intend to measure before placing it in the spectrometer. Also, wipe each cuvette with a kimwipe to remove all fingerprints that could effect the data collection.

Explanation:

The cuvette was blank with the solution so that the spectrometer will only read the solute absorbance. This also ensures that the spectrometer will ignore other absorbance fluctuations that normally occur due to the chemical make-up of water. The spectrometer only considered the absorbance of FeNCS^{2+} as indicated on the spectrum.

3 0
1 year ago
Steam initially at 0.3 MPa, 2500 C is cooled at constant volume. (a) At what temperature will steam become saturated vapour? [12
Scilla [17]

Answer:

a. 123.9°C

b.

c.

Explanation:

Hello, I'm attaching a picture with the numerical development of this exercise.

a. Since the steam is overheated vapour, the specific volume is gotten from the corresponding table. Then, as it became a saturated vapour, we look for the interval in which the same volume of state 1 is, then we interpolate and get the temperature.

b. Now, at 80°C, since it is about a rigid tank (constant volume for every thermodynamic process), the specific volume of the mixture is 0.79645 m^3/kg as well, so the specific volume for the liquid and the vapour are taken into account to get the quality of 0.234.

c. Now,since this is an isocoric process, the heat transfer per kg of steam is computed as the difference in the internal energy, considering the initial condition (showed in a. part) and the final one computed here.

** The thermodynamic data were obtained from Cengel's thermodynamics book 7th edition.

Best regards.

7 0
2 years ago
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