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yulyashka [42]
1 year ago
14

Why did you blank with the 0.0020 M Fe(NO3)3 solution as opposed to just DI water? What does it do to your spectrum? What chemic

als create the absorbance of the standard solution in Test Tube #4)? How can you find the absorption of only the FeNCS2+ in the standard solution?
Chemistry
1 answer:
Vlad1618 [11]1 year ago
3 0

Answer:

The cuvette was blank with the solution so that the spectrometer will only read the solute absorbance. This also ensures that the spectrometer will ignore other absorbance fluctuations that normally occur due to the chemical make-up of water. The spectrometer only considered the absorbance of FeNCS^{2+} as indicated on the spectrum. The reaction between the Fe^{3+} and the SCN^{-} are both clear liquids that form the orange liquid product  FeNCS^{2+} which creates the absorbance spectrum. Because the color of the solution is orange, it reflects this and similar colors while absorbing blueish hues. We can find the absorption of only the FeNCS^{2+} by pre-rinsing the cuvette with each solution we intend to measure before placing it in the spectrometer. Also, wipe each cuvette with a kimwipe to remove all fingerprints that could effect the data collection.

Explanation:

The cuvette was blank with the solution so that the spectrometer will only read the solute absorbance. This also ensures that the spectrometer will ignore other absorbance fluctuations that normally occur due to the chemical make-up of water. The spectrometer only considered the absorbance of FeNCS^{2+} as indicated on the spectrum.

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What is the specific heat (J/g°C) of a metal object whose temperature increases by 3.0°C when 17.5 g of metal was heated with 38
Verizon [17]

Answer:

a. 0.73

Explanation:

Given data

  • Added heat (Q): 38.5 J
  • Change in the temperature (ΔT): 3.0°C
  • Mass of the metal (m): 17.5 g
  • Specific heat of the metal (c): ?

We can determine the specific heat of the metal using the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 38.5 J / 17.5 g × 3.0°C

c = 0.73 J/g.°C

6 0
1 year ago
A sample of H2SO4 contains 2.02 g of hydrogen, 32.07 g of sulfur, and 64.00 g of oxygen. How many grams of sulfur and grams of o
Gemiola [76]
From the chemical formula of sulfuric acid, we can see the molar ratio:

H : S : O 
2 : 1 : 4

Now, we convert the mass of hydrogen given into the moles of hydrogen. This is done using

Moles = mass / Mr
Moles = 7.27 / 1
Moles = 7.27

Therefore, the moles will be:

S = 7.27 / 2 = 3.64 moles
O = 7.27 * 2 = 14.54 moles

Now, the respective masses are:
S = 32 * 3.64 = 116.48 grams
O = 16 * 14.54 = 232.64 grams 
7 0
1 year ago
A buffer is prepared by mixing hypochlorous acid ( HClO ) and sodium hypochlorite ( NaClO ) . If a strong base, such as NaOH , i
Dafna1 [17]

<u>Answer:</u> The balanced chemical equation is written below.

<u>Explanation:</u>

We are given:

A weak acid that is hypochlorous acid (HClO) and basic salt that is sodium hypochlorite (NaClO)

When a strong base is added to the buffer, the hydroxide ion will be neutralized by hydrogen ions from the acid.

So, the buffer component that neutralizes the additional hydroxide ions in the solution is HClO

The chemical equation for the neutralization of hydroxide ion with acid follows:

HClO+OH^-\rightarrow H_2O+ClO^-

Hence, the balanced chemical equation is written below.

4 0
2 years ago
How many liters of a 0.225 M solution of KI are needed to contain 0.935 moles of KI?
Katyanochek1 [597]

Answer:

4.16L

Explanation:

From the question given, we obtained the following data:

Molarity = 0.225 M

Number of mole of KI = 0.935mole

Volume =?

Molarity = mole / Volume

Volume = mole /Molarity

Volume = 0.935/0.225

Volume = 4.16L

Therefore, 4.16L of KI is needed.

6 0
2 years ago
A 36 gram sample of water has an initial temperature of 22 degrees Celsius after the sample absorbs 1200joules of heat energy th
UkoKoshka [18]

<span>We can use the heat equation,
Q = mcΔT </span>

 

<span>Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g</span>⁻¹ °C⁻<span>¹) and ΔT is the temperature difference (°C).</span>


Let's assume that the finale temperature is T.

Q = 1200 J

<span> m = 36 g
c = 4.186 J/g °C</span>

ΔT = (T - 22) 

 

By applying the formula,

   1200 J = 36 g x 4.186 J/g °C x (T - 22)

  (T - 22) = 1200 J / (36 g x 4.186 J/g °C)

  (T - 22) = 7.96 °C

            T = (7.96 + 22) °C = 29.96 °C

            T = 30 °C 


Hence, the final temperature is 30 °C.

8 0
2 years ago
Read 2 more answers
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