All categories

2 years ago

A 0.500 L bottle of water contains 8.82 × 10–7 mL of benzene. What is the concentration of benzene in ppmv?

Chemistry

2 answers:

KatRina [158]2 years ago

8 0

Answer:

the answer is 0.00176 ppmv

Explanation:

trust me bro, im asian

Art [367]2 years ago

3 0

0.00176 ppmv

This is the answer for ed

You might be interested in

Describe two shortcomings of the pennium model for isotopes

umka21 [38]

let me know when u find out plz because i would like to know as well its one of my chemistry qustions in an assiment. :)

3 0

2 years ago

How many grams of sodium acetate ( molar mass = 83.06 g/mol ) must be added to 1.00 Liter of a 0.200 M acetic acid solution to m

Pie

<u>Answer:</u> The mass of sodium acetate that must be added is 30.23 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of acetic acid solution = 0.200 M

Volume of solution = 1 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of acetic acid}}{1L}\\\\\text{Moles of acetic acid}=(0.200mol/L\times 1L)=0.200mol$

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{salt}]}{[\text{acid}]})$

$pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of acetic acid = 4.74

$[CH_3COONa]=?mol$

$[CH_3COOH]=0.200mol$

pH = 5.00

Putting values in above equation, we get:

$5=4.74+\log(\frac{[CH_3COONa]}{0.200})$

$[CH_3COONa]=0.364mol$

To calculate the mass of sodium acetate for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of sodium acetate = 83.06 g/mol

Moles of sodium acetate = 0.364 moles

Putting values in above equation, we get:

$0.364mol=\frac{\text{Mass of sodium acetate}}{83.06g/mol}\\\\\text{Mass of sodium acetate}=(0.364mol\times 83.06g/mol)=30.23g$

Hence, the mass of sodium acetate that must be added is 30.23 grams

7 0

2 years ago

Consider this reaction: 2H+ + CO32- → H2O + CO2. Identify each of the following as a product, a reactant, or a coefficient.

givi [52]

Identify each of the following as a product or a coefficient in reaction below

<h2> 2H^+ + CO3^2- → H2O + CO2</h2><h2 /><h2 /><h3> <u><em>reactant are</em></u></h3><h2> H^+ and CO3^2-</h2>

<u><em>Reason: </em></u>Reactant of a chemical reaction are found in the left side. They are initially present in a chemical reaction which are consumed to form product.

<h3> <em><u>Product are</u></em></h3>

H2O and CO2

<u><em>Reason</em></u>: They are found in the right side of the reaction. Product are produced in a chemical reaction.

<em><u>coefficient</u></em>

<em><u> </u></em><em><u> </u></em>is 2

Coefficient is the number found in front of a formula.
Therefore 2 is the coefficient since it is found in front of H^+

5 0

2 years ago

Read 2 more answers

Motohiro felt chilled by the rainy afternoon. He decided to make a cup of hot tea. He let the tea leaves steep too long and the

kati45 [8]

Answer: the correct one would be option B.

Explanation:

8 0

2 years ago

Initially, 50.0 g iron(iii) chloride is present. what amount of fecl3 is this, in moles?

nekit [7.7K]

One mole of a compound contains the mass equivalent to the molecular mass or relative formula mass of the compound.
1 mole of iron iii chloride contains a mass of 162.2 g.
Therefore, 50 g will contain 50 g/162.2 g = 0.3083 moles
= 0.3083 moles of Fe2Cl3

8 0

2 years ago