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lukranit [14]
2 years ago
5

Carbon dioxide, CO₂, changes from the solid phase to the gas phase at 1 atm and 194.5 K. In the solid phase, CO₂ is often called

dry ice. When dry ice sublimes in air at 298 K, the water vapor in the air can condense, forming a fog of small water droplets. This fog is often used for special effects at concerts and in movie-making.
1. State the direction of heat flow between the dry ice and the water vapor in the air.
2. At 1 atm and 298 K, compare the potential energies of the water molecules before and after the water vapor condenses.
3. At 1 atm and 190. K, compare the amount of thermal energy in a 1.0-kilogram block of dry ice to the amount of thermal energy in a 2.0-kilogram block of dry ice.
Chemistry
1 answer:
FinnZ [79.3K]2 years ago
5 0

Answer:

1. From water vapor to the dry ice;

2. The potential energy is higher before the water vapor condenses;

3. The thermal energy is higher in the 2.0 kg block.

Explanation:

1. The heat flows from the system with high temperature to the system with low temperature. The water vapor is at 298 K, and the dry ice is at 194.5 K.

2. The energy of the molecules is related to the temperature and the physics state. At the gas state, the molecules are more agitated, and the energy is higher than the liquid state. So, when the vapor condenses to a liquid, the energy decreases.

3. The thermal energy can be calculated by:

Q = m*c*ΔT

Where m is the mass, c is the specific heat, and ΔT the variation in the temperature. So, when the mass increase, thermal energy also increases.

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Answer: the original volume was 0.98L

Explanation:

V1 =?

T1 = 22k

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T2 = 85k

V1 /T1 = V2 /T2

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V1 = 22 x (3.8/85)

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3 0
1 year ago
Using the equation, C5H12 + 8O2 Imported Asset 5CO2 + 6H2O, if an excess of pentane (C5H12) were supplied, but only 4 moles of o
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Answer: 3 <span>moles of water would be produced in present case.
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Reason:
Reaction involved in present case is:
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In above reaction, 1 mole of C5H12 reacts with 8 moles of oxygen to give 6 moles of water.

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7 0
2 years ago
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certain alcohol contains only three elements, carbon, hydrogen, and oxygen. Combustion of a 40.00 gram sample of the alcohol pro
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Answer:

The answer to your question is:    C₂H₆O₁   = C₂H₆O

Explanation:

Data

CxHyOz

mass = 40 g  produced 76.40 g of CO2

                                       46.96 g of H2O

Empirical formula = ?

Process

                         CxHyOz    + O2    ⇒    CO2  + H2O

                         44g of CO2 --------------------  12 g of Carbon

                         76.40 g of CO2 --------------- x

                          x = 20.84 g of Carbon

                         12 g of Carbon ---------------  1 mol

                         20.84 g of C    ---------------   x

                         x = (20.84 x 1) / 12

                         x = 1.74 mol of Carbon

                        18 g of H2O --------------------  2 g of H

                        46.96 g of H2O --------------   x

                        x = (46.96 x 2) / 18

                        x = 5.22 g of H

                        1 g of H ------------------------  1 mol of H

                        5.22 g of H -------------------   x

                        x = 5.22 mol of H

Mass of Oxygen = 40 - 20.84 - 5.22g

                           = 13.94 g

                         16 g of Oxygen ----------------  1 mol

                         13.94 g of O --------------------   x

                         x = 0.87 mol of O

Divide by the lowest number of moles

Carbon = 1.74 / 0.87 = 2

Hydrogen = 5.22 / 0.87 = 6

Oxygen = 0.87 / 0.87 = 1

                           

Empirical formula

                                 C₂H₆O₁   = C₂H₆O

                         

3 0
1 year ago
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4 0
2 years ago
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