<span>3-Methylbutyl propanoate can be synthesized by reacting Propionic Acid with 3-Methylbutanol in the presence of Acid. This reaction is called as Esterification. The synthesis of
</span><span>3-Methylbutyl propanoate is shown below,</span>
By Tri chlorination, three chlorine atoms can replace the 3 hydrogen atoms in propane molecule to give tri-chlorinated products according to the attached picture.
<h3>
Answer:</h3>
28.96 kJ/°C
<h3>
Explanation:</h3>
We are given;
- Enthalpy change (ΔH) = −3226.7 kJ/mol
- The reaction is exothermic since the heat change is negative;
- Mass of benzoic acid = 3.1007 g
- Temperature change (21.84°C to 24.67°C) = 2.83°C
We are required to find the heat capacity of benzoic acid;
<h3>Step 1: Moles of benzoic acid </h3>
Moles = Mass ÷ molar mass
Molar mass of benzoic = 122.12 g/mol
Therefore;
Moles = 3.1007 g ÷ 122.12 g/mol
= 0.0254 moles
<h3>Step 2: Determine the specific heat capacity </h3>
Heat change for 1 mole = 3226.7 kJ
Moles of Benzoic acid = 0.0254 moles
But;
Specific heat capacity × ΔT = Moles × Heat change
cΔT = nΔH
Therefore;
Specific heat capacity,c = nΔH ÷ ΔT
= (3226.7 kJ × 0.0254 moles) ÷ 2.83°C
= 28.96 kJ/°C
Therefore, the specific heat capacity of benzoic acid is 28.96 kJ/°C
Answer:
6.074 X 10¹⁸ molecules.
Explanation:
Molecular mass(MM) of this compound C₂₇H₄₆O
= 27*(MM of C) + 46*(MM of H) + (MM of O)
= 27*(12.0107) + 46* (1.00784) + (15.999)
= 324.2889 + 46.36064 + 15.999
=386.64854 g
The mass of a mole of any compound is called it's molar mass. 1 molar mass has 6.022 X 10²³, or Avogadro's number, C₂₇H₄₆O molecules.
If 386.64854 g of C₂₇H₄₆O has 6.022 X 10²³ molecules of cholesterol, then
3.9mg or 0.0039g of C₂₇H₄₆O will have how many molecules?..
Using unitary method:
Number of molecules = 
= 6.074 X 10¹⁸ molecules.
3.98 x 10⁻¹⁹ Joule
<h3>Further explanation</h3>
<u>Given:</u>
The green light has a frequency of about 6.00 x 10¹⁴ s⁻¹.
<u>Question:</u>
The energy of a photon of green light (in joules).
<u>The Process:</u>
The energy of a photon is given by 
- E = energy in joules
- h = Planck's constant 6.63 x 10⁻³⁴ Js
- f = frequency of light in Hz (sometimes the symbol f is written as v)
Let us find out the energy of the green light emitted per photon.

Thus, we get a result of 
- - - - - - - - - -
Notes
- When an electron moves between energy levels it must emit or absorb energy.
- The energy emitted or absorbed corresponds to the difference between the two allowed energy states, i.e., as packets of light called photons.
- A higher energy photon corresponds to a higher frequency (shorter wavelength) of light.
<h3>Learn more</h3>
- The energy of the orange light emitted per photon brainly.com/question/2485282#
- Determine the density of our sun at the end of its lifetime brainly.com/question/5189537
- Find out the kinetic energy of the emitted electrons when metal is exposed to UV rays brainly.com/question/5416146
Keywords: green light, frequency, the energy, a photon, Planck's constant, electrons, emitted, wavelength, joules