Answer:
Total Ionic equation:
H⁺(aq) + NO₃⁻ (aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + NO₃⁻ (aq)
Explanation:
Chemical equation:
HNO₃ + NaOH → NaNO₃ + H₂O
Balanced chemical equation:
HNO₃(aq) + NaOH(aq) → NaNO₃(aq) + H₂O(l)
Total Ionic equation:
H⁺(aq) + NO₃⁻ (aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + NO₃⁻ (aq)
Net ionic equation:
H⁺(aq) + OH⁻(aq) → H₂O(l)
The NO₃⁻ (aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.
Spectator ions:
These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation
Answer:
Explanation:
T₁ = 100 + 273 = 373K
T₂ = 273 + 119 = 392 K
V₁ = initial volume
V₂ = Final volume
P₁ = P₁
P₂ = .85P₁
Using gas law equation
V₂ = 1.236 V₁
% increase in volume
= V₂-V₁ / V₁ x 100
= (1.236 V₁ - V₁ / V₁)x 100
= .236 x 100
= 23.6 % .
Let's Assign Symbols to molecules like,
C₂O₄ = X
and
H₂O = Y
Then,
K [ Co (X)₂ (Y)₂ ]
As, Potassium (K) has a O.N = +1
To neutralize, the coordination sphere must have -1 oxidation number.
So,
[ Co (X)₂ (Y)₂ ] = -1
As,
O.N of X = -2
Then
O.N of (X)₂ = -4
Also,
O.N of H₂O is zero as it is neutral, So,
[Co - 4 + 0 ] = -1
Or,
Co = -1 + 4
Co = +3
Result:
Oxidation Number of Coordination Sphere is -1 and Oxidation Number of Cu is +3.
Answer:
Temperature at which molybdenum becomes superconducting is-272.25°C
Explanation:
Conductor are those hard substances which allows path of electric current through them. And super conductors are those hard substances which have resistance against the flow of electric current through them.
As given, molybdenum becomes superconducting at temperatures below 0.90 K.
Temperature in Kelvins can be converted in °C by relation:
T(°C)=273.15-T(K)
Molybdenum becomes superconducting in degrees Celsius.
T(°C)=273.15-0.90= -272.25 °C
Temperature at which molybdenum becomes superconducting is -272.25 °C
