Thermal energy will flow from an object high temperature to an object of low one. In this case, the thermal energy will flow from object B to object A.
Answer:
Option C = 4.25 g
Explanation:
Ounce and grams are unit of mass. Ounce is larger unit while gram is smaller unit. The one ounce is consist of 28.35 g or we can say that one ounce is equal to 28.35 g. In order to convert the given ounce value into grams the value is multiply with 28.35 g.
Given data:
Mass = 0.15 ounce
Mass in gram = ?
Solution:
One ounce is equal to 28.35 g, so
0.15 × 28.35 = 4.25 g
The answer is 2.135 mol/Kg
Given that molarity is 2M, that is, 2 moles in 1 liter of solution.
Density of solution is 1.127 g/ml
Volume of solution is 1L or 1000 ml
mass of solution (m) = density × volume
m₁ = density × volume = 1.127 × 1000 = 1127 g
mass of solute, m₂ = number of moles × molar mass
m₂ = 2 × 95.211
m₂ = 190.422 g
mass of solvent = m₁ - m₂
= 1127 - 190.422
= 936.578 g
= 0.9366 Kg
molality = number of moles of solute / mass of solvent (in kg)
= 2 / 0.9366
= 2.135 mol/Kg
Answer:
Water moves into the cell
Explanation:
As shown in the question above, the cell is high in glucose and placed in a glass filled with water. This cell has a semi permeable membrane that allows only water to pass through, as the concentration of water within the cell is low, the cell will attempt to strike a balance with the medium it is inserted into. For this reason, what is likely to happen is the passage of water from the most concentrated to the least concentrated medium, that is, the water will pass from the cup to the cell.
water moves into the cell through osmosis.during osmosis water moves from a region of low concentration of solute to a region of high concentration of solute.the glucose introduced into the cell makes it more concentrated.
In this case the cell is hypertonic and water would enter into the cell through the semi permeable membrane.this membrane allows water to pass through but not glucose.this movement of water into the cell causes the cell to become turgid.
Example of an element that has an electron distribution ending in s2p1 is Na or sodium. The complete electron configuration of Na 1s22s22p63s<span>1. </span>Example of an element that has an electron distribution ending in s2d2 is Ca or calcium. The complete electron configuration of Ca is 1s22s22p63s23p64s2.