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insens350 [35]
2 years ago
7

Why does 4.03/0.0000035 = 1.2 x 106, instead of a different number of significant figures?

Chemistry
1 answer:
jasenka [17]2 years ago
4 0

Explanations:- As per the significant figures rule, In multiplication and division, we go with least number of sig figs.

4.03 has three sig figs where as 0.0000035 has two sig figs only, The zeros in this number are not sig figs as they are just holding the place values. As the least number of sig figs here is two, the answer needs to be reported with two sig figs only.

\frac{4.03}{0.0000035}=1.2*10^6



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How many moles of lithium are present in a sample that contains 2.45x10^87 formula units of Li2SO4?​
ddd [48]

The answer is: 8.14·10⁶³ moles of lithium are present.

N(Li₂SO₄) = 2.45·10⁸⁷; number of formula units of lithium sulfate.

n(Li₂SO₄) = N(Li₂SO₄) ÷ Na.

n(Li₂SO₄) = 2.45·10⁸⁷ ÷ 6.022·10²³ 1/mol.

n(Li₂SO₄) = 4.07·10⁶³ mol; amount of lithium sulfate

In one molecule of lithium sulfate, there are two atoms of lithium.

n(Li₂SO₄) : n(Li) = 1 : 2.

n(Li) = 2 · 4.07·10⁶³ mol.

n(Li) = 8.14·10⁶³ mol; amount of lithium atoms.

3 0
2 years ago
The electron dot structure for CI is
finlep [7]
The correct option is C.
A Lewis dot diagram is a representation of the valence electron of  an atom, which uses dot around the symbol of the atom. Chlorine has seven electrons in its outermost shell, these seven electrons are arranged in form of dot around the atom of chlorine. If you count the number of dot given in option C, you will notice that they are seven.
6 0
1 year ago
Read 2 more answers
Consider the element in the periodic table that is directly to the right of the element identified in part (a). Would the 1s pea
astraxan [27]

The question is incomplete. Here is the complete question.

The photoelectron spectroscopy is shwon below.

(a) Based on the photoelectron spectrum, identify the unknown element and write its electron configuration.

(b) Consider the element in the periodic table that is directly to the right of the element identified in part (a). Would the 1s peak of this element appear to the left of, the right of, or in the same position as the 1s peak of the element in part (a)? Explain your reasoning.

Answer and Explanation: <u>Photoelectron</u> <u>Spectroscopy</u> is a method of determinining the relative energy of electrons in atoms and molecules.

It is based on the <em>photoelectric effect: </em>when a radiation energy incides on a substance, an electron is ejected from it. If we know the kinetic energy of the ejected electron, known as photoelectrons, and the energy of the incident radiation, it is possible to find the energy of the electron in the substance.

The energy needed to eject an electron from the sample is called <em>Binding Energy</em> and in an atom, depends on which shell the electron is: valence eletrons (outermost shell), binding energy is lower; core eletrons (innermost shell), binding energy is highest.

In the graph, vertical axis shows 5 peaks for different energies. The peak closer to the origin, the leftmost peak, correspond to the 1s subshell, since their are closest to the nucleus, and so, has the highest binding energy.

Following from left to the right, we noticed:

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(a) Then, we can conclude the eletron configuration of the element is

1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{3}

which is Phosphorus with atomic number of 15.

(b) The element to the right of element P is Sulfur (S). The peak 1s of sulfur will appear in the same position as the 1s peak of Phosphorus, because the elements in the Periodic Table are grouped according to certain properties. Elements in the same horizontal line are elements in the same period, which one of the characteristics is they have the same total number of electron shells.

4 0
1 year ago
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WARRIOR [948]

the answer is c i think.


3 0
2 years ago
Read 2 more answers
In the reaction C + O2 → CO2, 18 g of carbon react with oxygen to produce 72 g of carbon dioxide. What mass of oxygen would be n
bulgar [2K]
<span>Molar mass(C)= 12.0 g/mol
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Molar mass (CO2)=44.0 g/mol

18g C*1mol C/12 g C = 1.5 mol C

                                 C +     O2 →                CO2

from reaction       1 mol    1 mol              1 mol
from problem     1.5 mol   1.5 mol         1.5 mol

1.5 mol O2*32 g O2/1 mol O2 = 48 g O2

In reality this reaction requires only 48 g O2 for 18 g carbon.
And from 18 g carbon you can get only
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But these problem has 72g CO2. The best that we can think, it is a mix of CO2 and O2.
So to find all amount  of O2  that was added for the reaction (probably people who wrote this problem wanted this)
we need  (the mix of 72g - mass of carbon 18 g)= 54 g.
So the only answer that is possible is 
</span><span>2.) 54 g.</span>
3 0
2 years ago
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