Answer:
Equilibrium constant of the given reaction is 
Explanation:
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The given reaction can be written as summation of the following reaction-


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Equilibrium constant of this reaction is given as-
![\frac{[NOBr]^{2}}{[N_{2}][O_{2}][Br_{2}]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BNOBr%5D%5E%7B2%7D%7D%7B%5BN_%7B2%7D%5D%5BO_%7B2%7D%5D%5BBr_%7B2%7D%5D%7D)
![=(\frac{[NOBr]}{[NO][Br_{2}]^{\frac{1}{2}}})^{2}(\frac{[NO]^{2}}{[N_{2}][O_{2}]})](https://tex.z-dn.net/?f=%3D%28%5Cfrac%7B%5BNOBr%5D%7D%7B%5BNO%5D%5BBr_%7B2%7D%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%29%5E%7B2%7D%28%5Cfrac%7B%5BNO%5D%5E%7B2%7D%7D%7B%5BN_%7B2%7D%5D%5BO_%7B2%7D%5D%7D%29)


a.200.59 amu of mercury contains = 6.02 * 1023 molecules
Mass for 3.0 * 1023 molecules = (3.0 * 1023 * 200.59) /6.02 * 1023
= 100.29 amu
Thus, mass for 3.0 * 1023 molecules is 100.29 amu
b.As, 200.59 g mercury contains = 6.02 * 1023 atoms
1 g mercury contains = (6.02 * 1023 /200) atoms
= 3.01 * 1021 atoms
Thus, 1 ng mercury contains = (3.01 * 1021) / 109
= 3.01 * 1012 atoms
Thus, 3.0 * 1012 atoms present in 1 ng mercury
Answer:
See explaination
Explanation:
See attachment for the detailed step by step solution of the given problem.
The attached file have the solved problem.
Answer:
The synthesis of p-chlorobenzenesulfonic acid with the reagents for each step and the structure of the monosubstituted intermediate compound is shown in the drawing below.
Explanation:
Benzenesulfonic acid is obtained from the sulfonation of benzene, using concentrated smoking sulfuric acid.
Chlorination of benzenesulfonic acid with chlorine without catalyst requires a polar solvent, such as acetic acid to obtain the selectivity in the position for and the ortho derivative in a low proportion.
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