answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kolezko [41]
2 years ago
13

As part of an investigation, students combined substances in a beaker to observe chemical reactions. They performed two procedur

es. They measured the mass of each substance before and after each reaction. The table shows their observations.
Assuming the students did not make any careless errors, what likely explains these changes in mass?

A. Procedure 1: All the reactants were liquids that evaporated.
Procedure 2: A gas was formed as one product, and it escaped into the air.

B. Procedure 1: One of the reactants was converted to thermal energy.
Procedure 2: All the products were liquids.

C. Procedure 1: The reactants were liquids with different densities.
Procedure 2: The reactants were combined into only one product.

D. Procedure 1: One of the products was a gas that escaped into the air.
Procedure 2: A gas from the air reacted with one of the other reactants.

Chemistry
2 answers:
asambeis [7]2 years ago
8 0

Answer:

D.

Explanation:

aniked [119]2 years ago
3 0

Answer: its D

Explanation: I took a test, got it correct.

You might be interested in
If the tip of the syringe, "The Titrator", was not filled with NaOH before the initial volume reading was recorded, would the co
Ostrovityanka [42]

Answer:

The concentration of acetic acid in vinegar of that trial would be <u><em>greater than</em></u> the actual concentration.

Explanation:

"The titrator" contains the base solution (NaOH) with which the soution of vinegar (acetic acid) is being titrated.

Under the assumption that the tip of the syringe was not filled before the initial volume reading was recorded, part of the volume of the base that you release will be retained in the tip of the syringe, and, consequently, the actual volume of base added to the acetic acid will be less than what you will calculate by the difference of readings.

So,  in your calculations you will use a larger volume of the base than what was actually used, yielding a fake larger number of moles of base than the actual amount added.

So, as at the neutralization point the number of equivalents of the base equals the number of acid equivalents, you will be reporting a greater number of acid equivalents, which in turn will result in a greater concentration than the actual one. This means that the concentration of acetic acid in vinegar of that trial would be greater than the actual concentration.

6 0
2 years ago
A sample of a radioactive isotope initially contains 20 x 10^10 atoms. After 16 days, 5 x 10^10 atoms remain. what is the half-l
nekit [7.7K]
I think the answer is A but I could be wrong
7 0
2 years ago
Iron-59 is used in medicine to diagnose blood circulation disorders. The half life of iron-59 is 44.5 days. How much of a 2.000
kolezko [41]

Answer:

0.258 mg of iron remains.

Explanation:

To solve this problem we can use the formula

M₂ = M₀ * 0.5^{\frac{t}{44.5} }

Where M₂ is the mass remaining, M₀ is the initial mass, and t is time in days.

Using the data given by the problem:

M₂ = 2.000 mg * 0.5^{\frac{133.5}{44.5} }

M₂ = 0.258 mg

7 0
2 years ago
A graduated cylinder holds 100 mL of water. A lead weight is dropped into the cylinder bringing the new volume up to 450 mL. If
dolphi86 [110]

11.43g/mL

Explanation:

Given parameters:

Volume of water in the graduated cylinder = 100mL

Volume of water + lead weight = 450mL

Mass of lead weight = 4000g

Unknown:

Density of the lead weight = ?

Solution:

Density is the mass per unit volume of a body.

  Density  = \frac{mass}{volume}

Volume of the lead weight = volume of water displaced

 Volume of lead weight = 450 - 100 = 350mL

Density = \frac{4000}{350}  = 11.43g/mL

learn more:

Density brainly.com/question/2690299

#learnwithBrainly

6 0
2 years ago
How many grams of K2CO3 would you need to put on the spill to neutralize the acid according to the following equation? 2HBr(aq)+
Mkey [24]

Full Question:

A flask containing 420 Ml of 0.450 M HBr was accidentally knocked to the floor.?

How many grams of K2CO3 would you need to put on the spill to neutralize the acid according to the following equation?

2HBr(aq)+K2CO3(aq) ---> 2KBr(aq) + CO1(g) + H2O(l)

Answer:

13.1 g K2CO3 required to neutralize spill

Explanation:

2HBr(aq) + K2CO3(aq) → 2KBr(aq) + CO2(g) + H2O(l)

Number of moles = Volume * Molar Concentration

moles HBr= 0.42L x .45 M= 0.189 moles HBr

From the stoichiometry of the reaction;

1 mole of K2CO3 reacts  with 2 moles of HBr

1 mole = 2 mole

x mole = 0.189

x = 0.189 / 2 = 0.0945 moles

Mass = Number of moles * Molar mass

Mass = 0.0945 * 138.21  = 13.1 g

3 0
2 years ago
Other questions:
  • Which statement describes a chemical reaction?
    9·2 answers
  • Matt did an experiment to study the solubility of two substances. He poured 100 mL of water at 20 °C into each of two beakers la
    14·2 answers
  • A reagent bottle on the shelf labeled 0.5m nacl was used in place of the 0.5 m cacl2. assuming c2o4^2- to be in excess, what wou
    11·1 answer
  • the air we breathe is approximately 21% oxygen.atypical breath has a volume of 450 ml.how many grams of O2 are in a breath of ai
    12·1 answer
  • H2PO4-(aq) ⇆ H+(aq) + HPO42-( which ion plays the role of hydrogen ion donor and which one plays the hydrogen ion acceptor in BP
    14·1 answer
  • An equimolar mixture of N2(g) and Ar(g) is kept inside a rigid container at a constant temperature of 300 K. The initial partial
    9·1 answer
  • If 0.15 mol of I2 vapor can effuses through an opening in a heated vessel in 36 sec, how long will it take 0.15 mol of Cl2 to ef
    5·1 answer
  • Calculate the pOH of a solution that contains 3.9 x 10-5 M H3O+ at 25°C.
    9·1 answer
  • A gas balloon has a volume of 80.0 mL at 300K , and a pressure of 50.0 kPa. if the pressure changes to 80.0 kPa and the temperat
    14·1 answer
  • Polymerization starts at the ________ end of the template.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!