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Olin [163]
2 years ago
14

Combustion of hydrogen releases 142 j/g of hydrogen reacted. How many kj of energy are released by the combustion of 16.0 oz of

hydrogen? (1 lb = 16 oz; 1 kg = 2.2 lb)

Chemistry
2 answers:
Delvig [45]2 years ago
7 0

64.61 kJ of energy is released by the combustion of 16.0 oz of hydrogen

<h3>Further explanation</h3>

Delta H reaction (ΔH) is the amount of heat/heat change between the system and its environment

(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)

The reaction of a substance with oxygen is called a combustion reaction

the combustion of hydrogen is

<h3>2H₂ + O₂ → 2H₂O.</h3>

This equation shows that 2 Hydrogen molecules react with 1 molecule of oxygen to produce 2 molecules of water

In this combustion reaction will produce large thermal energy because it involves breaking the hydrogen gas bond, so the reaction is exothermic

The combustion of hydrogen releases 142 j / g of hydrogen reacted.

Combustion of 16.0 oz of hydrogen will release heat of:

16 oz = 1 lb = 0.455 kg = 455 g

For each gram Hydrogen releases 142 J, then for 455 g releases:

142 x 455 J = 64610 J = 64.61 kJ

<h3>Learn more</h3>

the complete combustion of methane

brainly.com/question/1971314

grams of o2 are required to burn 17.0 gal of c8h18

brainly.com/question/5816411#

moles of oxygen are required to produce 2.33 moles of water

brainly.com/question/6209439

Keywords: Combustion of hydrogen, ΔH reaction, water, oxygen, exothermic

Andrej [43]2 years ago
5 0

Given the mass of hydrogen = 16.0 oz

Converting 16.0 oz hydrogen to pounds (lb) using the conversion factor 1 lb = 16 oz:

16.0 oz * \frac{1 lb}{16 oz} =1 lb

Converting 16.0 lb to g using the conversion factors 1 kg = 2.2 lb, 1 kg = 1000 g:

1lb * \frac{1kg}{2.2lb}*\frac{1000g}{1kg}= 454.5 g

Heat of combustion of hydrogen = 142 J/g

Calculating the heat released when 16.0 oz is combusted:

454.5g H_{2} * \frac{142 J}{g} *\frac{1 kJ}{1000J}=64.5kJ


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Explanation:

the correct answer is

D) 0.636 mol/dm³

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2 years ago
The normal boiling point of acetic acid is 118.1°C. If a sample of the acetic acid is at 125.2°C, predict the signs of ΔH, ΔS, a
Nostrana [21]

The question is incomplete, the complete question is;

The normal boiling point of acetic acid is 118.1°C. If a sample of the acetic acid is at 125.2°C, predict the signs of ∆H, ∆S, and ∆G for the boiling process at this temperature.

A. ∆H > 0, ∆S > 0, ∆G < 0

B. ∆H > 0, ∆S > 0, ∆G > 0

C. ∆H > 0, ∆S < 0, ∆G < 0

D. ∆H < 0, ∆S > 0, ∆G > 0

E. ∆H < 0, ∆S < 0, ∆G > 0

Answer:

A. ∆H > 0, ∆S > 0, ∆G < 0

Explanation:

During boiling, a liquid is converted to vapour. This is a phase change for which heat is absorbed because energy must be taken in to break the intermolecular bonds in the liquid before it can be converted to a gas. Hence ∆H>0

Secondly, a phase change from liquid to gas leads to an increase in entropy hence ∆S>0.

Thirdly, the process is spontaneous. For every spontaneous process ∆G<0

3 0
2 years ago
Explain why calcium combines in a different ratio to a fluoride ion versus an oxide ion.
jok3333 [9.3K]

Answer:

This is due the different charges of fluoride and oxide ions.

Explanation:

When calcium reacts it is oxidized to Ca²⁺. In the same way, fluoride ion is reduced to F⁻ and oxide ion to O²⁻.

When these ions are combined, the molecule must be neutral. That means 2 ions of F⁻ are necessaries and just 1 O²⁻ ion will reacts producing:

CaF₂ and CaO.

The different charges of these ions is the reason why calcium will combine in different ratios.

5 0
2 years ago
According to the following balanced reaction, how many moles of HNO3 are formed from 8.44 moles of NO2 if there is plenty of wat
kotegsom [21]

Answer:

5.63 mol.

Explanation:

  • The balanced chemical equation between NO₂ and H₂O is:

<em>3NO₂(s) + H₂O(l) → 2HNO₃(aq) + NO(g), </em>

It is clear that 3 mol of NO₂ reacts with 1 mol of H₂O to produce 2 mol of HNO₃ and 1 mol of NO.

<em>Water is present as an excess reactant and NO₂ is limiting reactant.</em>

<em></em>

  • To find the no. of moles of HNO₃ produced:

3 mol of NO₂ produces → 2 mol of HNO₃, from stichiometry.

8.44 mol of NO₂ produces → ??? mol of HNO₃.

∴ The no. of moles of HNO₃ are formed = (8.44 mol)(2 mol)/(3 mol) = 5.63 mol.

3 0
2 years ago
The combustion of one mole of liquid ethanol, CH3CH2OH, produces 1367 kJ of heat. Calculate how much heat is produced when 235.0
deff fn [24]

Answer:- 6984 kJ of heat is produced.

Solution:- From given information, 1367 kJ of heat is produced by the combustion of 1 mole of ethanol. We are asked to calculate the heat produced by the combustion of 235.0 g of ethanol.

Let's convert given grams to moles and multiply by the heat produced by one mole of ethanol to get the total heat produced. Molar mass of ethanol is 46 grams per mole. The set will be:

235.0g(\frac{1mole}{46g})(\frac{1367 kJ}{1mole})

= 6984 kJ

So, 6984 kJ of heat is produced by the combustion of 235.0 g of liquid ethanol.

6 0
2 years ago
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