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2 years ago

What volume is equivalent to 0.0015 m3?

Chemistry

1 answer:

vaieri [72.5K]2 years ago

3 0

Answer : Option 'D' is correct.

$0.0015m^{3}$ = $1.5\times 10^{6}mm^{3}$

Explanation 1) : 1 m = 100 cm

$1 m^{3}= 1000000 cm^{3}$ or $1 m^{3}= 10^{6} cm^{3}$

$(0.0015m^{3})\times \frac{(1000000cm^{3})}{(1m^{3})}$

$(0.0015)\times \frac{(1000000cm^{3})}{(1)}$ = $1500cm^{3}$

$0.0015m^{3}$ = $1500cm^{3}$ = $1.5\times 10^{3}cm^{3}$

Explanation 2) : 1 m = 1000 mm

$1m^{3}= 1000000000mm^{3} = 10^{9}mm^{3}$

$(0.0015m^{3})\times \frac{(10^{9}mm^{3})}{(1m^{3})}$

$(0.0015)\times \frac{(10^{9}mm^{3})}{(1)}$ = $1500000 mm^{3}$

$0.0015m^{3}$ = $1500000 mm^{3}$ = $1.5\times 10^{6}mm^{3}$

Option 'D' is right.

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Answer:

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Explanation:

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2 years ago

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A compound of barium and oxygen was dissolved in hydrochloric acid to give a solution of barium ion, which was then precipitated

n200080 [17]

Answer:

The empiricial formula of the compound is BaO2

Explanation:

Step 1: Data given

Barium and oxygen dissolved in hydrochloric acid gives a solution of barium ion. This was precipitated with an excess of potassium chromate and gives barium chromate.

The original compound weighs 1.345g and gives 2.012g of BaCrO4

Step 2: Calculate moles of BaCrO4

moles of BaCrO4 = mass of BaCrO4 / molar mass of BaCrO4

moles of BaCrO4 = 2.012g / 253.37 g/mol = 0.0079 moles

Step 3: Calculate moles of Ba

Mole ratio for Ba and BaCrO4 is 1:1 so this means for 0.0079 moles of BaCrO4, there are 0.0079 moles of Ba-ion

Step 4: Calculate mass of Ba-ion

Mass of Ba = Moles of Ba / Molar mass of Ba

Mass of Ba = 0.0079 moles * 137.327g/mole = 1.085 g Ba

Step 5: Mass of oxygen

Since the original compound has barium and oxygen, the mass of oxygen is the difference between the original mass and the mass of the Ba-ion

1.345 g - (1.085 g Ba) = 0.260 g O

Step 6: Calculate moles of Oxygen

moles oxygen = mass of oxygen / Molar mass of oxygen

moles oxygen = 0.260g / 16g/mole = 0.01625 moles O

We divide the number of moles by the smallest number of moles which is 0.0079

Ba → 0.0079/0.0079 = 1

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(0.254 g O) / (15.99943 g O/mol) = 0.0158756 mol O

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2 years ago

A solution with a hydrogen ion concentration of 3.25 × 10-2 m is ________ and has a hydroxide concentration of _______

Romashka-Z-Leto [24]

To know the acidity of a solution, we calculate the pH value. The formula for pH is given as:

pH = - log [H+] where H+ must be in Molar

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Therefore the pH is:

pH = - log [3.25 × 10-2]

pH = 1.488

Since pH is way below 7, therefore the solution is acidic.

To find for the OH- concentration, we must remember that the product of H+ and OH- is equivalent to 10^-14. Therefore,

[H+]*[OH-] = 10^-14 
[OH-] = 10^-14 / [H+]

[OH-] = 10^-14 / 3.25 × 10-2

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Answers:

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6 0

1 year ago

there is a total of seventeen constitutional isomers for the molecular formula c5h13n. draw the skeletal formula of all three co

MAXImum [283]

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Secondary Amines:
In secondary amines the nitrogen atom is attached to two alkyl groups and one hydrogen atom.

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2 years ago

Calculate the mass of olive oil in a 750mL bottle if the density of olive oil is 0.92 g/mL. *Use the GRASP method.

kap26 [50]

The mass of olive oil : 690 g

<h3>Further explanation </h3>

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

Density formula:

$\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}$

ρ = density

m = mass

v = volume

Given

volume of olive oil = V=750 ml

density of olive oil = ρ = 0.92 g/ml

Required

the mass of olive oil

Analysis

the formula :

$\tt m=\rho\times V$

Solution

$\tt m=0.92\times 750\\\\m=690~g$

Paraphrase

the mass of olive oil : 690 g

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2 years ago