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Vladimir79 [104]
1 year ago
9

Jane and Jack have a bicycling competition Jane rides a constant speed of 12 miles per hour while Jack rides at a constant speed

of 330 feet per minute. How fast are Jane and Jack going in meters per second? Who finishes first? Show your factor-label method work. There are 5280 feet in one mile. There are 3.281 feet in one meter
Chemistry
1 answer:
MariettaO [177]1 year ago
4 0

Answer:

Explanation:

I don't know how you want the conversion done. I use dimensional analysis.

Jane

12 miles / hour [1.6 km/1 mile][1000 m/1 km][1 hour / 3600 sec]

12 * [1.6 * 3600 / 1000  m/s] = 69.12 m/s

5.33 m/s      This answer is a bit shorter than using 5280 feet.

Using 5280 feet

12 miles / hour [5280 ft/1 mile] [1 m/3.281 feet] * [1 hr/3600 sec]

12 * 5280 / (3.281 * 3600)

12 *. 4470

5.36

Jack

330 feet / minute [ 1 meter / 3.281 feet] [1 minute / 60 seconds]

330 * 1/(3.281 * 60)

330 * 1/(196.86)

1.676 m/s

She's going faster than he is, no matter which method is used to do the calculation

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Explain how your experimental data for Rf values are, or are not, consistent with your predictions of enantiomeric and diastereo
hichkok12 [17]

Answer:

Answer is explained below.

Explanation:

As (+) menthol and (-) menthol are enantiomers whose physical properties are same except optical activity so we can expect they have similar Rf values.

Whereas diastereomers have different physical properties and different Rf values.

For example when the (+) menthol , (-) menthol, isomenthol and neomenthol undergo TLC (thin layer chromatography) the

Rf values of.(+menthol) = .447

Rf (+isomenthol) = .395

Rf (+neomenthol)= .487

Rf (-menthol) = .434

The above data shows that (+) menthol and (-) menthol have almost same Rf values and vary a little i.e 0.447 and 0.437. So we can conclude them as enantiomers

Whereas (+) menthol or (+) neomenthol or (+) isomenthol i.e 0.447 , 0.395 and 0.487 have different Rf values. We can conclude them as diasteromers.

(+) menthol and (-) menthol - enantiomers

(+) menthol and (+) neomenthol- diastereomers

(-) menthol and (+) isomenthol - diastereomers

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2 years ago
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1. What is the oxidation number for the silver ion in tarnish?
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Tarnish is Ag2S-silver sulfide and the oxidation state of silver is +1
7 0
1 year ago
6. The half life for uranium-235 is 7.0x108 years.
kaheart [24]

Answer:

\large \boxed{4.0}

Explanation:

\text{No. of half-lives} = 2.8  \times 10^{9 } \text{ yr} \times \dfrac{\text{1 half-life}}{7.0 \times 10^{8} \text{ yr}} = \textbf{4.0 half-lives}\\\\\text{The sample went through $\large \boxed{\textbf{4.0 half-lives}}$}

4 0
2 years ago
Elemental analysis of the unknown gas from part a revealed that it is 30.45% n and 69.55% o. what is the molecular formula for t
Gnesinka [82]

Assuming we have 100 g of sample

30.45/MW of N 14g = 2.175

69.55/MW of O 16g = 4.34

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6 0
1 year ago
An unknown compound with a molar mass of 155.06 g/mol consists of 46.47% c, 7.80% h, and 45.72% cl. find the molecular formula f
Contact [7]

Answer:- Molecular formula of the compound is C_6H_1_2Cl_2 .

Solution:- From given information:

C = 46.47%

H = 7.80%

Cl = 45.72%

First of all we find out the empirical formula from given percentages. We divide the given percentages by their respective atomic masses to calculate the moles:

C=\frac{46.47}{12.01}  = 3.87

H=\frac{7.80}{1.01}  = 7.72

Cl=\frac{45.72}{35.45}  = 1.29

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So, the empirical formula of the compound is C_3H_6Cl .

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= 36.03 + 6.06 + 35.45

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To calculate the number of formula units we divide molar mass by empirical formula mass.

number of empirical formula units = \frac{155.06}{77.54}

= 2

So, the molecular formula would be two times of empirical formula that is, C_6H_1_2Cl_2 .

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